A circuit is constructed with a DC power supply connected in series with a current-limiting resistor. After the resistor, the circuit splits into two parallel branches that eventually reconnect to the negative terminal of the power supply. The first parallel branch contains a Zener diode (rated at ) installed in a reverse-biased orientation. The second parallel branch contains a standard silicon diode installed in a forward-biased orientation. Based on this configuration, what is the approximate voltage measured across the parallel diode combination, and which component dictates this voltage?
- , dictated by the forward-biased standard silicon diode clamping the voltage.Cevap
- B, dictated by the reverse-biased Zener diode regulating the branch voltage.
- C, dictated by the combined additive voltage drops of both diodes in the circuit.
- D, dictated by the power supply because the reverse-biased Zener diode acts as an open circuit.
Cevap
The correct answer is , dictated by the forward-biased standard silicon diode clamping the voltage.
The correct answer accurately identifies that in a parallel circuit, the component with the lowest forward voltage drop or breakdown voltage dictates the voltage across the entire parallel block. Since the standard silicon diode is forward-biased, it drops approximately 0.7 V. This prevents the voltage across the parallel branches from ever reaching the 6.2 V required to cause the Zener diode to break down and conduct. The Zener diode remains effectively an open circuit, and the standard diode clamps the branch voltage at 0.7 V.
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Diode Biasing and Parallel Circuit Voltage Clamping
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