A naval shipyard allocates its weekly steel supply for submarine repair, surface ship repair, and new construction in a ratio of . If the surface ship repair division receives tons of steel, what is the total amount of steel allocated to all three divisions combined?
- A480
- B576
- 720Cevap
- D960
Cevap
The total amount of steel allocated to all three divisions is 720 tons.
The ratio of steel for submarine repair, surface ship repair, and new construction is , which means there are total parts (). We are given that surface ship repair, the middle term representing parts of the ratio, receives tons. To find the value of a single part, divide by , yielding tons. Finally, multiply this unit rate by the total parts to find the total steel allocation: tons.
Adım Adım Çözüm
Anahtar Kavram
Solving multi-part ratio problems by finding a unit rate
Alternatif Yöntem
You can set up a direct proportion: 4 parts / 240 tons = 12 total parts / x tons. Cross-multiplying gives 4x = 2880, so dividing both sides by 4 yields x = 720.
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