A solid machine part is suspended from a spring scale. In the air, the scale reads . When the part is completely submerged in water, the scale reads . The part is then removed, dried, and completely submerged in a vat of unknown oil, where the scale reads . Based on these readings, what is the density of the oil compared to the density of water?
- 0.75 times the density of waterCevap
- B1.33 times the density of water
- C0.25 times the density of water
- D1.13 times the density of water
Cevap
The oil is 0.75 times the density of water.
According to Archimedes' principle, buoyant force equals the weight of the displaced fluid (). The buoyant force in water is . The buoyant force in the oil is . Because the part is fully submerged in both instances, the displaced volume () is identical. Therefore, the buoyant forces are directly proportional to the fluid densities. The ratio of the oil's density to the water's density is the ratio of their buoyant forces: .
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Anahtar Kavram
Apparent weight and Archimedes' Principle