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Zorluk: OrtaOhm's Law

In an auxiliary radio circuit, a direct-current source applies 24 V24\text{ V} across a fixed resistor, producing a measured current flow of 8 mA8\text{ mA}. What is the resistance of the component?

  1. A
    3 Ω3\ \Omega
  2. B
    192 Ω192\ \Omega
  3. C
    300 Ω300\ \Omega
  4. 3000 Ω3{}000\ \OmegaCevap

Cevap

3000 Ω3{}000\ \Omega
Applying Ohm's Law (R=VIR = \frac{V}{I}) with the current converted to amperes (8 mA=0.008 A8\text{ mA} = 0.008\text{ A}) gives 24 V0.008 A=3000 Ω\frac{24\text{ V}}{0.008\text{ A}} = 3{}000\ \Omega.

Adım Adım Çözüm

1
Convert the current from milliamperes (mA) to base amperes (A)
8 mA=8×10−3 A=0.008 A8\text{ mA} = 8 \times 10^{-3}\text{ A} = 0.008\text{ A}
Ohm's Law calculations require current in base units of amperes.
2
Apply Ohm's Law to solve for resistance (RR)
R=VI=24 V0.008 A=3000 ΩR = \frac{V}{I} = \frac{24\text{ V}}{0.008\text{ A}} = 3{}000\ \Omega
Resistance equals voltage divided by current.

Anahtar Kavram

Ohm's Law defines the direct relationship between voltage, current, and resistance in a DC circuit (R=VIR = \frac{V}{I}).
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Ohm's Law

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