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Zorluk: OrtaProperties of Integers

The sum of three consecutive negative even integers is −102-102. What is the absolute value of the smallest of these integers?

Cevap: 36

Cevap

36
By defining the consecutive even integers algebraically, the smallest integer is correctly identified as −36-36. Taking the absolute value of −36-36 yields 3636.

Adım Adım Çözüm

1
Define variables for the three consecutive even integers.
Let the smallest integer be xx. The next consecutive even integers are x+2x + 2 and x+4x + 4.
Consecutive even integers are always 2 units apart.
2
Set up the equation.
x+(x+2)+(x+4)=−102x + (x + 2) + (x + 4) = -102
The sum of the three integers is given as −102-102.
3
Solve for xx.
3x+6=−1023x + 6 = -102 leads to 3x=−1083x = -108, yielding x=−36x = -36.
Isolating xx provides the value of the smallest integer.
4
Calculate the absolute value.
∣−36∣=36|-36| = 36
The question specifically asks for the absolute value of the smallest integer.

Anahtar Kavram

Consecutive integers and absolute value properties
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