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Zorluk: ZorParallel Circuits

An electrical test bench delivers a constant 80 V80\text{ V} direct-current supply to four separate parallel circuit arrangements. Match each circuit configuration on the left with its corresponding equivalent resistance (ReqR_{eq}) and total supply current (ITI_T) on the right.

  • Two resistors of 40 Ω40\ \Omega and 10 Ω10\ \Omega connected in parallel across the supplyReq=8 ΩR_{eq} = 8\ \Omega and IT=10 AI_T = 10\text{ A}
  • Four identical 64 Ω64\ \Omega resistive heating elements connected in parallelReq=16 ΩR_{eq} = 16\ \Omega and IT=5 AI_T = 5\text{ A}
  • Three parallel branches containing 120 Ω120\ \Omega, 60 Ω60\ \Omega, and 40 Ω40\ \Omega resistorsReq=20 ΩR_{eq} = 20\ \Omega and IT=4 AI_T = 4\text{ A}
  • Two parallel branches containing a 150 Ω150\ \Omega sensor and a 75 Ω75\ \Omega resistorReq=50 ΩR_{eq} = 50\ \Omega and IT=1.6 AI_T = 1.6\text{ A}

Cevap

The configuration with 40 Ω40\ \Omega and 10 Ω10\ \Omega matches Req=8 Ω,IT=10 AR_{eq} = 8\ \Omega, I_T = 10\text{ A}; four 64 Ω64\ \Omega elements match Req=16 Ω,IT=5 AR_{eq} = 16\ \Omega, I_T = 5\text{ A}; three branches of 120 Ω,60 Ω,40 Ω120\ \Omega, 60\ \Omega, 40\ \Omega match Req=20 Ω,IT=4 AR_{eq} = 20\ \Omega, I_T = 4\text{ A}; and two branches of 150 Ω,75 Ω150\ \Omega, 75\ \Omega match Req=50 Ω,IT=1.6 AR_{eq} = 50\ \Omega, I_T = 1.6\text{ A}.
In any direct-current parallel network, the total equivalent resistance (ReqR_{eq}) is calculated using the reciprocal formula 1Req=∑1Rn\frac{1}{R_{eq}} = \sum \frac{1}{R_n} (or R/NR/N for identical branches). Total current drawn from the supply is determined by Ohm's Law: IT=VSReqI_T = \frac{V_S}{R_{eq}}. Evaluating each configuration against the constant 80 V80\text{ V} bus correctly establishes all four resistance and current pairs.

Adım Adım Çözüm

1
Calculate the equivalent resistance and total current for the 40 Ω40\ \Omega and 10 Ω10\ \Omega parallel branch pair.
Req=40×1040+10=8 ΩR_{eq} = \frac{40 \times 10}{40 + 10} = 8\ \Omega; IT=80 V8 Ω=10 AI_T = \frac{80\text{ V}}{8\ \Omega} = 10\text{ A}.
Two unequal parallel resistors follow the product-over-sum rule, and total current is determined by Ohm's Law (I=V/RI = V/R).
2
Calculate the equivalent resistance and current for the four parallel 64 Ω64\ \Omega elements.
Req=644=16 ΩR_{eq} = \frac{64}{4} = 16\ \Omega; IT=80 V16 Ω=5 AI_T = \frac{80\text{ V}}{16\ \Omega} = 5\text{ A}.
Identical parallel resistors simplify to branch resistance divided by the number of branches (R/NR/N).
3
Calculate the equivalent resistance and current for the three parallel branches (120 Ω,60 Ω,40 Ω120\ \Omega, 60\ \Omega, 40\ \Omega).
1Req=1120+2120+3120=6120=120  ⟹  Req=20 Ω\frac{1}{R_{eq}} = \frac{1}{120} + \frac{2}{120} + \frac{3}{120} = \frac{6}{120} = \frac{1}{20} \implies R_{eq} = 20\ \Omega; IT=80 V20 Ω=4 AI_T = \frac{80\text{ V}}{20\ \Omega} = 4\text{ A}.
Three or more unequal parallel branches require finding the reciprocal sum over a common denominator.
4
Calculate the equivalent resistance and current for the 150 Ω150\ \Omega and 75 Ω75\ \Omega parallel branches.
Req=150×75150+75=11250225=50 ΩR_{eq} = \frac{150 \times 75}{150 + 75} = \frac{11250}{225} = 50\ \Omega; IT=80 V50 Ω=1.6 AI_T = \frac{80\text{ V}}{50\ \Omega} = 1.6\text{ A}.
Applying product-over-sum and dividing bus voltage by equivalent resistance yields the total circuit current.

Anahtar Kavram

Parallel circuit rules require that full bus voltage appears across each branch, equivalent resistance is always lower than the smallest branch resistance, and total current equals the sum of all individual branch currents.
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