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Zorluk: OrtaFactoring Polynomials

When the algebraic expression 5x2−13x−65x^2 - 13x - 6 is factored completely, it can be written in the form (5x+a)(x−b)(5x + a)(x - b), where aa and bb are positive integers. What is the value of a+ba + b?

Cevap: 5 / five

Cevap

5
Factoring the quadratic 5x2−13x−65x^2 - 13x - 6 yields (5x+2)(x−3)(5x + 2)(x - 3). By comparing this to the target format (5x+a)(x−b)(5x + a)(x - b), we can identify that a=2a = 2 and b=3b = 3. Adding these together gives the final answer of 5.

Adım Adım Çözüm

1
Determine the factoring method for the non-monic quadratic expression 5x2−13x−65x^2 - 13x - 6.
Since the leading coefficient is 5, look for two numbers that multiply to (5)(−6)=−30(5)(-6) = -30 and add to the middle coefficient, −13-13.
This sets up the factor-by-grouping method.
2
Find the two numbers.
The numbers are −15-15 and 22.
(−15)×2=−30(-15) \times 2 = -30 and −15+2=−13-15 + 2 = -13.
3
Rewrite the middle term using these two numbers and factor by grouping.
5x2−15x+2x−6=5x(x−3)+2(x−3)=(5x+2)(x−3)5x^2 - 15x + 2x - 6 = 5x(x - 3) + 2(x - 3) = (5x + 2)(x - 3).
Grouping common terms extracts the binomial factors.
4
Match the factored form to the given format (5x+a)(x−b)(5x + a)(x - b).
Comparing (5x+2)(x−3)(5x + 2)(x - 3) to (5x+a)(x−b)(5x + a)(x - b) reveals that a=2a = 2 and b=3b = 3.
Both aa and bb correspond exactly to the positive integer components of the binomials.
5
Calculate the final required sum, a+ba + b.
2+3=52 + 3 = 5.
The question specifically asks for the sum of the parameters.

Anahtar Kavram

Factoring non-monic quadratic trinomials
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