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Zorluk: OrtaCalculating Rate and Time

A supply convoy is scheduled to travel a total distance of 135135 miles to a forward operating base in exactly 33 hours and 3030 minutes. For the first 9090 minutes, the convoy travels along a secured highway at an average rate of 5050 miles per hour. For the remainder of the route, what must be the convoy's average rate of speed, in miles per hour, to arrive exactly on time?

Cevap: 30 mph

Cevap

30
The convoy must cover the remaining 6060 miles in the remaining 2.02.0 hours, which requires an average speed of 3030 miles per hour.

Adım Adım Çözüm

1
Convert the given travel times from minutes to hours.
33 hours and 3030 minutes = 3.53.5 hours. 9090 minutes = 1.51.5 hours.
Since the speed is given in miles per hour, all time values must be in hours.
2
Calculate the distance covered on the secured highway.
50 miles/hour×1.5 hours=75 miles50 \text{ miles/hour} \times 1.5 \text{ hours} = 75 \text{ miles}
To find out how much of the total distance has already been traveled.
3
Calculate the remaining distance to the forward operating base.
135 miles−75 miles=60 miles135 \text{ miles} - 75 \text{ miles} = 60 \text{ miles}
This is the distance that must be covered during the off-road portion of the route.
4
Calculate the remaining travel time available.
3.5 hours−1.5 hours=2.0 hours3.5 \text{ hours} - 1.5 \text{ hours} = 2.0 \text{ hours}
This is the time limit for completing the rest of the journey.
5
Calculate the required average speed for the remaining distance.
60 miles÷2.0 hours=30 miles per hour60 \text{ miles} \div 2.0 \text{ hours} = 30 \text{ miles per hour}
Rate equals distance divided by time (r=dtr = \frac{d}{t}).

Anahtar Kavram

Calculating Rate and Time

Alternatif Yöntem

You could set up an algebraic equation for the total distance: (50×1.5)+(r×2.0)=135(50 \times 1.5) + (r \times 2.0) = 135. Solving for rr: 75+2r=13575 + 2r = 135, so 2r=602r = 60, which means r=30r = 30.
Tahmini Süre:1m 30s
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