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Zorluk: KolaySeries Circuits

A direct current (12 V12\text{ V} DC) circuit contains two indicator lamps connected in series. If a voltmeter measures a 7 V7\text{ V} drop across the first lamp, what is the voltage drop across the second lamp?

  1. A
    12 V12\text{ V}
  2. 5 V5\text{ V}Cevap
  3. C
    7 V7\text{ V}
  4. D
    19 V19\text{ V}

Cevap

The voltage drop across the second lamp is 5 V5\text{ V}.
In a series circuit, total voltage supplied by the source is distributed across all series components such that the sum of the individual voltage drops equals the source voltage (Vtotal=V1+V2V_{\text{total}} = V_1 + V_2). Subtracting the 7 V7\text{ V} drop across the first lamp from the 12 V12\text{ V} total supply gives 5 V5\text{ V} across the second lamp.

Adım Adım Çözüm

1
Identify the fundamental rule for voltage distribution in a series circuit.
The total supply voltage equals the sum of the individual voltage drops across each series load: Vtotal=V1+V2V_{\text{total}} = V_1 + V_2.
According to Kirchhoff's Voltage Law, the algebraic sum of all voltages around any closed loop in a circuit must equal zero.
2
Substitute the known values into the equation and solve for the unknown voltage drop (V2V_2).
V2=Vtotal−V1=12 V−7 V=5 VV_2 = V_{\text{total}} - V_1 = 12\text{ V} - 7\text{ V} = 5\text{ V}.
Subtracting the known component voltage drop from the source voltage yields the remaining voltage dropped across the second component.

Anahtar Kavram

Series Voltage Distribution (Kirchhoff's Voltage Law)
Tahmini Süre:45s
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Series Circuits

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