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Zorluk: KolayVoltage and Electromotive Force (EMF)

A handheld emergency flashlight is powered by four 1.5 V1.5\text{ V} alkaline cells connected in series aiding. What is the total electromotive force (EMF) supplied to the flashlight bulb?

  1. A
    1.5 V1.5\text{ V}
  2. 6.0 V6.0\text{ V}Cevap
  3. C
    6.0 A6.0\text{ A}
  4. D
    0.375 V0.375\text{ V}

Cevap

6.0 V6.0\text{ V}
When DC voltage sources are connected in series aiding (positive terminal to negative terminal), their individual voltages add together directly. Four 1.5 V1.5\text{ V} cells in series provide a total electromotive force of 4×1.5 V=6.0 V4 \times 1.5\text{ V} = 6.0\text{ V}.

Adım Adım Çözüm

1
Identify the circuit configuration and the formula for total EMF in series.
Etotal=E1+E2+E3+E4E_{\text{total}} = E_1 + E_2 + E_3 + E_4
When electrical power sources (cells) are wired in series aiding, their individual voltages add directly together to produce the total potential difference.
2
Sum the voltages of the four identical 1.5 V1.5\text{ V} cells.
Etotal=1.5 V+1.5 V+1.5 V+1.5 V=6.0 VE_{\text{total}} = 1.5\text{ V} + 1.5\text{ V} + 1.5\text{ V} + 1.5\text{ V} = 6.0\text{ V}
Multiplying the cell voltage by the total number of cells (4×1.5 V4 \times 1.5\text{ V}) yields the total electromotive force.

Anahtar Kavram

Series Cell Electromotive Force (EMF) Addition
Tahmini Süre:45s
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