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Zorluk: OrtaMultiplying Polynomials

If the polynomial expression (3x−5)(3x - 5) is multiplied by the expression (Ax2+2x−7)(Ax^2 + 2x - 7), the resulting simplified polynomial has an x2x^2 coefficient of −19-19. What is the value of the constant AA?

Cevap: 5

Cevap

5
The x2x^2 terms in the product of (3x−5)(3x - 5) and (Ax2+2x−7)(Ax^2 + 2x - 7) are generated by multiplying the xx terms together (3x⋅2x=6x2)(3x \cdot 2x = 6x^2) and by multiplying the constant by the x2x^2 term (−5⋅Ax2=−5Ax2)(-5 \cdot Ax^2 = -5Ax^2). Setting their sum equal to −19x2-19x^2 gives the equation 6−5A=−196 - 5A = -19. Solving for AA yields A=5A = 5.

Adım Adım Çözüm

1
Identify combinations that yield an x2x^2 term
The x2x^2 terms come from multiplying (3x)(3x) by (2x)(2x) and (−5)(-5) by (Ax2)(Ax^2).
To find the coefficient of a specific term without expanding the entire polynomial, only multiply the terms whose exponents sum to the target power.
2
Calculate the partial products
(3x)(2x)=6x2(3x)(2x) = 6x^2 and (−5)(Ax2)=−5Ax2(-5)(Ax^2) = -5Ax^2
These represent the only contributions to the x2x^2 term in the final expanded polynomial.
3
Formulate an equation for the coefficient
6−5A=−196 - 5A = -19
The sum of the partial x2x^2 coefficients must equal the total x2x^2 coefficient given in the problem.
4
Solve the linear equation for AA
−5A=−25→A=5-5A = -25 \rightarrow A = 5
Isolating the variable AA provides the final answer.

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Multiplying Polynomials
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