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Zorluk: OrtaOhm's Law Calculations and Concepts

An automated assembly fixture uses an industrial direct current (DC) solenoid valve to actuate a pneumatic clamp. The solenoid coil has an internal resistance of 600 Ω600\text{ }\Omega and requires a steady current of 35 mA35\text{ mA} to operate reliably. What DC voltage must the power supply deliver to the solenoid valve?

  1. A
    17.1 V17.1\text{ V}
  2. B
    2.1 V2.1\text{ V}
  3. 21 V21\text{ V}Cevap
  4. D
    21,000 V21,000\text{ V}

Cevap

21 V21\text{ V}
According to Ohm's Law, voltage is calculated by multiplying current by resistance (V=I×RV = I \times R). Converting the current from milliamperes to amperes gives 35 mA=0.035 A35\text{ mA} = 0.035\text{ A}. Multiplying 0.035 A×600 Ω0.035\text{ A} \times 600\text{ }\Omega results in 21 V21\text{ V}.

Adım Adım Çözüm

1
Convert the operating current from milliamperes (mA\text{mA}) to base amperes (A\text{A}).
35 mA=351,000 A=0.035 A35\text{ mA} = \frac{35}{1,000}\text{ A} = 0.035\text{ A}
Ohm's Law calculations require electrical quantities in standard SI base units.
2
Apply Ohm's Law (V=I×RV = I \times R) to find the required supply voltage.
V=0.035 A×600 Ω=21 VV = 0.035\text{ A} \times 600\text{ }\Omega = 21\text{ V}
Voltage equals the product of current and resistance.

Anahtar Kavram

Ohm's Law (V=I×RV = I \times R) with metric prefix conversion
Tahmini Süre:1m 0s
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Ohm's Law Calculations and Concepts

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