Soru

Zorluk: ZorWheel and Axle

An electric motor directly turns the rear solid axle of an industrial transport cart. The axle has a diameter of 4 inches4 \text{ inches}, and the attached drive wheels have a diameter of 24 inches24 \text{ inches}. If the motor applies a rotational force of 1200 lbs1200 \text{ lbs} at the outer surface of the axle, what is the resulting forward force exerted by the wheels against the ground? (Assume zero friction losses).

  1. 200 lbs200 \text{ lbs}Cevap
  2. B
    7200 lbs7200 \text{ lbs}
  3. C
    1200 lbs1200 \text{ lbs}
  4. D
    100 lbs100 \text{ lbs}

Cevap

200 lbs200 \text{ lbs}
In a vehicle drive system, the effort is applied to the smaller axle and the output is at the outer edge of the larger wheel. The mechanical advantage is the ratio of the input radius (2 inches2 \text{ inches}) to the output radius (12 inches12 \text{ inches}), which is 1/61/6. Therefore, the 1200 lbs1200 \text{ lbs} of input force is reduced to 1/61/6 of its value, resulting in 200 lbs200 \text{ lbs} of forward force.

Adım Adım Çözüm

1
Identify the input and output components of the machine.
Input is applied to the axle. Output is delivered at the edge of the wheel.
Determining where force is applied dictates whether the system acts as a force multiplier or a speed/distance multiplier.
2
Determine the radius of both the input and output components.
Axle radius = 2 inches2 \text{ inches} (4÷24 \div 2). Wheel radius = 12 inches12 \text{ inches} (24÷224 \div 2).
Mechanical advantage must be calculated using consistent dimensions, typically the radius of rotation.
3
Calculate the Ideal Mechanical Advantage (IMA) of the system.
IMA=Input RadiusOutput Radius=212=16\text{IMA} = \frac{\text{Input Radius}}{\text{Output Radius}} = \frac{2}{12} = \frac{1}{6}.
When an axle drives a wheel, the output force is distributed over a larger distance, resulting in a mechanical advantage of less than 1.
4
Calculate the output force.
Output Force=Input Force×IMA=1200 lbs×16=200 lbs\text{Output Force} = \text{Input Force} \times \text{IMA} = 1200 \text{ lbs} \times \frac{1}{6} = 200 \text{ lbs}.
The output force is the product of the applied effort and the mechanical advantage.

Anahtar Kavram

Mechanical Advantage of Axle-Driven Systems

Alternatif Yöntem

You can also use diameters directly without converting to radii: IMA = (Input Diameter) / (Output Diameter) = 4 / 24 = 1/6. Then multiply by the 1200 lbs force to get 200 lbs.
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