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Zorluk: OrtaAtomic Structure and Periodic Table

An ion with a +3+3 positive charge has 1010 electrons and a mass number of 2727. How many neutrons are located inside the nucleus of this ion?

Cevap: 14 neutrons

Cevap

14 neutrons
For any atom or ion, the mass number equals the total count of protons and neutrons in the nucleus. Because this ion has a +3+3 charge and 1010 electrons, it must contain 1313 protons (10+310 + 3). Subtracting 1313 protons from the mass number of 2727 gives exactly 1414 neutrons.

Adım Adım Çözüm

1
Calculate the atomic number (number of protons) using the ion's charge and electron count.
The atom has 1313 protons.
A positive charge (+3+3) indicates that the atom has lost 33 electrons relative to its proton count. Therefore, Protons=Electrons+Charge=10+3=13\text{Protons} = \text{Electrons} + \text{Charge} = 10 + 3 = 13.
2
Calculate the number of neutrons using the mass number and the proton count.
The nucleus contains 1414 neutrons.
Mass number is the sum of protons and neutrons (A=Z+NA = Z + N). Thus, Neutrons=Mass Number−Protons=27−13=14\text{Neutrons} = \text{Mass Number} - \text{Protons} = 27 - 13 = 14.

Anahtar Kavram

Relationship between mass number, atomic number (protons), net ionic charge, and subatomic particle counts.
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