Geometry

157 soru

Soru 121Soru →

A circular track has an inner circumference of 440440 meters. The track has a uniform width of 77 meters. What is the circumference of the outer edge of the track? (Use π≈227\pi \approx \frac{22}{7})

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Cevap: 484 meters

Cevap

484 meters
The inner circumference is 440440 meters. Using the formula C=2πrC = 2\pi r, the inner radius is 7070 meters (440=2×227×r440 = 2 \times \frac{22}{7} \times r). Because the track has a uniform width of 77 meters, the outer radius is 70+7=7770 + 7 = 77 meters. Using the circumference formula again for the outer edge, C=2×227×77=484C = 2 \times \frac{22}{7} \times 77 = 484 meters.

Adım Adım Çözüm

1
Find the inner radius using the given circumference.
rinner=70r_{inner} = 70 meters
Using the formula C=2πrC = 2\pi r, substitute 440440 for CC and 227\frac{22}{7} for π\pi: 440=2×227×r440 = 2 \times \frac{22}{7} \times r, which simplifies to r=70r = 70.
2
Calculate the outer radius by adding the track's width.
router=77r_{outer} = 77 meters
The outer edge is 77 meters further from the center than the inner edge, so you must add the width to the inner radius (70+7=7770 + 7 = 77).
3
Calculate the outer circumference.
484484 meters
Use the formula C=2πrC = 2\pi r with the new outer radius: C=2×227×77=44×11=484C = 2 \times \frac{22}{7} \times 77 = 44 \times 11 = 484.

Anahtar Kavram

Calculating the circumference of concentric circles by determining and adjusting their respective radii.

Alternatif Yöntem

You can also solve this using the diameter. The inner diameter is 140140 meters (440=πd440 = \pi d). Since the track is 77 meters wide on all sides, the total width added to the overall diameter is 1414 meters (7×27 \times 2). The outer diameter is 140+14=154140 + 14 = 154 meters. The outer circumference is 227×154=484\frac{22}{7} \times 154 = 484 meters.
Tahmini Süre:1m 30s
Soru 122Soru →

In a blueprint for a corner bracket, a laser cuts an exact 90∘90^\circ right angle, splitting it into two adjacent sections. The measure of one section is determined by the expression (2x+18)∘(2x + 18)^\circ, while the adjacent section is measured as (3x−8)∘(3x - 8)^\circ. Based on this design, what is the degree measure of the larger section?

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Cevap: 50∘50^\circ

Cevap

The larger section measures 50∘50^\circ.
The problem states the laser cuts a 90-degree right angle into two sections, meaning the two expressions must add up to 90 degrees. Setting up the equation (2x + 18) + (3x - 8) = 90 simplifies to 5x + 10 = 90. Solving for x gives x = 16. Substituting x back into the expressions yields 50 degrees for the first section and 40 degrees for the second section. The larger of the two is 50 degrees.

Adım Adım Çözüm

1
Set up the algebraic equation based on the geometric relationship.
(2x+18)+(3x−8)=90(2x + 18) + (3x - 8) = 90
The two adjacent sections form a right angle, meaning they are complementary and must sum to 90 degrees.
2
Combine like terms on the left side of the equation.
5x+10=905x + 10 = 90
Combining the variable terms and constant terms simplifies the equation.
3
Isolate the variable x.
x=16x = 16
Subtract 10 from both sides to get 5x = 80, then divide by 5.
4
Substitute the value of x back into both angle expressions.
First section = 2(16)+18=50∘2(16) + 18 = 50^\circ; Second section = 3(16)−8=40∘3(16) - 8 = 40^\circ
The specific degree measures must be calculated to find the larger angle.
5
Compare the two angle measures.
50∘50^\circ
The question asks specifically for the measure of the larger section.

Anahtar Kavram

Complementary Angles and Algebraic Substitution
Soru 123Soru →

Match each circle-related calculation on the left to its correct numerical value on the right.

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Öğeler

Area of a circle with a radius of 55
Circumference of a circle with a diameter of 1010
Radius of a circle with an area of 100π100\pi
Diameter of a circle with a circumference of 12π12\pi

Eşleşmeler

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Cevap

Area with radius 5 matches to 25π; Circumference with diameter 10 matches to 10π; Radius of area 100π matches to 10; Diameter of circumference 12π matches to 12.
Each match is verified by accurately applying the formulas A=πr2A = \pi r^2 and C=πdC = \pi d to either solve for the resulting property or to work backwards to find the missing dimension.

Adım Adım Çözüm

1
Calculate the area for the first description.
Area = 25π25\pi
The formula for the area of a circle is A=πr2A = \pi r^2. Substituting r=5r = 5 yields 25π25\pi.
2
Calculate the circumference for the second description.
Circumference = 10π10\pi
The formula for circumference is C=πdC = \pi d. Substituting d=10d = 10 yields 10π10\pi.
3
Solve for the radius in the third description.
Radius = 1010
Given area A=100πA = 100\pi, use 100π=πr2100\pi = \pi r^2 to find that r2=100r^2 = 100, so r=10r = 10.
4
Solve for the diameter in the fourth description.
Diameter = 1212
Given circumference C=12πC = 12\pi, use 12π=πd12\pi = \pi d to determine that d=12d = 12.

Anahtar Kavram

Calculating area, circumference, radius, and diameter of a circle using fundamental geometry formulas.
Soru 124Soru →

A civil engineer is designing a railroad crossing where a straight diagonal track intersects two parallel roads. The two same-side interior angles between the parallel roads and the track are represented by the algebraic expressions (4x−20)∘(4x - 20)^\circ and (3x+25)∘(3x + 25)^\circ. Based on the geometric properties of parallel lines intersected by a transversal, match each description on the left with its correct calculated numerical value on the right.

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Öğeler

The algebraic value of xx
The measure of the acute angle formed at the intersections
The measure of the obtuse angle formed at the intersections
The difference in measure between the obtuse angle and the acute angle

Eşleşmeler

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Cevap

The correct matches are: the value of x is 25, the acute angle is 80°, the obtuse angle is 100°, and the difference between them is 20°.
Same-side interior angles formed by parallel lines and a transversal are supplementary, meaning they add up to 180 degrees. Setting up the equation (4x - 20) + (3x + 25) = 180 allows us to solve for x, which equals 25. Substituting x = 25 back into the original expressions provides the individual angle measures: 80 degrees (acute) and 100 degrees (obtuse). Finally, subtracting the acute angle from the obtuse angle yields a difference of 20 degrees.

Adım Adım Çözüm

1
Set up an equation based on the geometric relationship of the angles.
(4x−20)+(3x+25)=180(4x - 20) + (3x + 25) = 180
When a transversal intersects parallel lines, same-side interior angles are supplementary, meaning their sum is exactly 180 degrees.
2
Solve the algebraic equation to find the value of x.
7x+5=180→7x=175→x=257x + 5 = 180 \rightarrow 7x = 175 \rightarrow x = 25
Combining the like terms and isolating x provides the necessary variable value to determine the actual angle measures.
3
Substitute the value of x back into the original expressions.
4(25)−20=80∘4(25) - 20 = 80^\circ and 3(25)+25=100∘3(25) + 25 = 100^\circ
This calculation determines the specific measures of the acute and obtuse angles formed at the intersection.
4
Calculate the difference between the obtuse and acute angle measures.
100∘−80∘=20∘100^\circ - 80^\circ = 20^\circ
This satisfies the final required numerical value for the matching pairs.

Anahtar Kavram

Properties of parallel lines intersected by a transversal, specifically that same-side interior angles are supplementary.
Soru 125Soru →

A drone is tethered to a fixed landing pad and can fly within a maximum circular boundary with an area of 400π400\pi square meters. If a safety protocol requires the tether to be shortened by 88 meters, what is the maximum area of the new circular flight boundary?

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Cevap: 144π square meters144\pi \text{ square meters}

Cevap

The new flight boundary has an area of 144π square meters144\pi \text{ square meters}.
The initial area of 400π400\pi square meters indicates the original tether length (radius) was 2020 meters, because πr2=400π\pi r^2 = 400\pi. Shortening the tether by 88 meters results in a new radius of 1212 meters. The new area is calculated by squaring the new radius and multiplying by π\pi, yielding π(12)2=144π\pi(12)^2 = 144\pi square meters.

Adım Adım Çözüm

1
Find the original radius using the area formula A=πr2A = \pi r^2.
400π=πr2400\pi = \pi r^2, so r2=400r^2 = 400, which means r=20r = 20 meters.
The original tether length represents the radius of the circular boundary.
2
Calculate the new radius by subtracting 88 meters.
20−8=1220 - 8 = 12 meters.
The safety protocol shortens the tether, directly reducing the flight radius.
3
Calculate the area of the new circular boundary.
A=π(12)2=144π square metersA = \pi(12)^2 = 144\pi \text{ square meters}.
The problem asks for the maximum area of the new boundary.

Anahtar Kavram

Area of a circle and its relationship to the radius.
Soru 126Soru →

An isosceles triangle has two equal sides that each measure 1313 inches and a base that measures 1010 inches. What is the length of the altitude (height) drawn to the base?

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Cevap: 1212 inches

Cevap

The length of the altitude is 1212 inches.
Drawing an altitude to the base of an isosceles triangle splits it into two identical right triangles. The base of 1010 inches is bisected into two 55-inch segments. For one of these right triangles, the base leg is 55 inches and the hypotenuse (the equal side) is 1313 inches. Using the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2), we set up the equation h2+52=132h^2 + 5^2 = 13^2. Solving for h2h^2 gives 169−25=144169 - 25 = 144. Taking the square root of 144144 yields an altitude of 1212 inches.

Adım Adım Çözüm

1
Identify the properties of an altitude in an isosceles triangle.
The altitude bisects the 1010-inch base, creating two equal segments of 55 inches each.
This splits the isosceles triangle into two congruent right triangles, allowing the use of the Pythagorean theorem.
2
Set up the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) for one of the right triangles.
h2+52=132h^2 + 5^2 = 13^2, where hh is the altitude, 55 is the base leg, and 1313 is the hypotenuse.
The equal side of the isosceles triangle serves as the hypotenuse of the newly formed right triangle.
3
Square the known values.
h2+25=169h^2 + 25 = 169.
To begin isolating the unknown altitude squared (h2h^2).
4
Solve for the altitude.
h2=169−25=144h^2 = 169 - 25 = 144, so h=144=12h = \sqrt{144} = 12.
Taking the square root of 144144 gives the final length of the altitude.

Anahtar Kavram

Using the Pythagorean theorem to find the altitude of an isosceles triangle
Soru 127Soru →

A flat metal washer is manufactured by stamping a circular hole with a diameter of 4 mm4 \text{ mm} out of the exact center of a solid circular disk with a diameter of 12 mm12 \text{ mm}. What is the area of the remaining flat face of the washer in square millimeters? (Enter only the numerical coefficient of π\pi in your answer. For example, if the area is 50π50\pi, enter 50).

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Cevap: 32

Cevap

32
The area of the remaining metal washer face is found by calculating the area of the large outer circle (36π36\pi) and subtracting the area of the smaller inner circle hole (4π4\pi), which leaves a remaining area of 32π32\pi. Since the question asks for the coefficient of π\pi, the correct numerical entry is 32.

Adım Adım Çözüm

1
Calculate the radius of the outer disk.
R=12÷2=6 mmR = 12 \div 2 = 6 \text{ mm}
The area formula for a circle requires the radius, which is half of the diameter.
2
Calculate the area of the outer disk.
Areaouter=π×62=36π mm2\text{Area}_{\text{outer}} = \pi \times 6^2 = 36\pi \text{ mm}^2
This represents the total surface area before the center hole is removed.
3
Calculate the radius of the inner hole.
r=4÷2=2 mmr = 4 \div 2 = 2 \text{ mm}
The radius of the removed section is needed to determine how much area to subtract.
4
Calculate the area of the inner hole.
Areainner=π×22=4π mm2\text{Area}_{\text{inner}} = \pi \times 2^2 = 4\pi \text{ mm}^2
This is the area of the metal that is stamped out.
5
Subtract the inner area from the outer area.
36π−4π=32π mm236\pi - 4\pi = 32\pi \text{ mm}^2
The remaining face area of the washer is the difference between the full disk and the removed hole.
6
Identify the coefficient of π\pi.
32
The stem specifically asks for the numerical coefficient only.

Anahtar Kavram

Calculating the area of an annulus (the region between two concentric circles) by subtracting the area of the inner circle from the area of the outer circle.
Soru 128Soru →

A searchlight beam sweeps horizontally across a central angle of 72∘72^\circ. If the maximum effective range of the searchlight is 20 meters20 \text{ meters}, what is the length of the arc formed by the outer edge of the beam? (Leave your answer in terms of π\pi).

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Cevap: 8π meters8\pi \text{ meters}

Cevap

8π meters8\pi \text{ meters}
The length of an arc is calculated by multiplying the full circumference of the circle (2πr2\pi r) by the fraction of the circle represented by the central angle (θ360∘\frac{\theta}{360^\circ}). In this scenario, the full circumference is 2π(20)=40π meters2\pi(20) = 40\pi \text{ meters}. The fraction representing the 72∘72^\circ sweep is 72360\frac{72}{360}, which simplifies to 15\frac{1}{5}. Multiplying the full circumference by this fraction gives 15×40π=8π meters\frac{1}{5} \times 40\pi = 8\pi \text{ meters}.

Adım Adım Çözüm

1
Identify the formula for the arc length of a circle.
Arc Length=(θ360∘)×2πr\text{Arc Length} = (\frac{\theta}{360^\circ}) \times 2\pi r
The arc length represents a specific fraction of the entire circumference based on the central angle.
2
Determine the fraction of the circle covered by the searchlight beam.
72∘360∘=15\frac{72^\circ}{360^\circ} = \frac{1}{5}
Simplifying the angle fraction makes the subsequent multiplication easier.
3
Calculate the full circumference of the circle using the given radius (range).
C=2π(20)=40π metersC = 2\pi(20) = 40\pi \text{ meters}
The full circumference is necessary to find the length of the fractional arc.
4
Multiply the full circumference by the angle fraction.
15×40π=8π meters\frac{1}{5} \times 40\pi = 8\pi \text{ meters}
This calculation applies the proportional fraction to the total boundary of the circle, yielding the arc length.

Anahtar Kavram

Arc Length of a Circle
Tahmini Süre:1m 0s
Soru 129Soru →

Two circular dials on a control panel have a radius ratio of 2:32:3. If the circumference of the smaller dial is 12π centimeters12\pi \text{ centimeters}, what is the circumference of the larger dial?

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Cevap: 18π cm18\pi \text{ cm}

Cevap

The circumference of the larger dial is 18π cm18\pi \text{ cm}.
The ratio of the radii is 2:3. The smaller dial has a circumference of 12π12\pi, meaning its radius is 66 (since C=2πrC = 2\pi r). Setting up the proportion 6r=23\frac{6}{r} = \frac{2}{3} gives a larger radius of 99. The circumference of the larger dial is then 2π(9)=18π cm2\pi(9) = 18\pi \text{ cm}.

Adım Adım Çözüm

1
Determine the radius of the smaller dial.
2πr=12π→r=6 cm2\pi r = 12\pi \rightarrow r = 6 \text{ cm}
The radius of the smaller dial is required to use the given ratio.
2
Apply the ratio to find the radius of the larger dial.
6rlarge=23→2rlarge=18→rlarge=9 cm\frac{6}{r_{large}} = \frac{2}{3} \rightarrow 2r_{large} = 18 \rightarrow r_{large} = 9 \text{ cm}
The problem states the radius ratio between the smaller and larger dials is 2:3.
3
Calculate the circumference of the larger dial.
C=2π(9)=18π cmC = 2\pi(9) = 18\pi \text{ cm}
The question asks for the circumference of the larger dial.

Anahtar Kavram

Using proportions to find unknown circle dimensions and calculating circumference.

Alternatif Yöntem

Because circumference is directly proportional to radius (C=2πrC = 2\pi r), the circumferences of two circles share the exact same ratio as their radii (2:32:3). Therefore, you can set up the proportion 12πC=23\frac{12\pi}{C} = \frac{2}{3} to solve directly for C=18πC = 18\pi without needing to calculate the specific radii.
Tahmini Süre:1m 0s
Soru 130Soru →

A right triangle has a hypotenuse that measures 2020 centimeters and a base that measures 1212 centimeters. What is the area of this triangle?

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Cevap: 96 cm296\text{ cm}^2

Cevap

The area of the right triangle is 96 cm296\text{ cm}^2.
To find the area of a right triangle, you need both the base and the height (the two legs). The Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) reveals the missing height is 1616 cm because 162+122=20216^2 + 12^2 = 20^2. Using the area formula (A=12bhA = \frac{1}{2}bh), we multiply 12×12×16\frac{1}{2} \times 12 \times 16 to get 96 cm296\text{ cm}^2.

Adım Adım Çözüm

1
Use the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) to find the missing height (the other leg).
a2+122=202a^2 + 12^2 = 20^2
The area formula requires the base and the height. We are given the hypotenuse (2020) and the base (1212).
2
Solve for the missing height (aa).
a2+144=400⇒a2=256⇒a=16a^2 + 144 = 400 \Rightarrow a^2 = 256 \Rightarrow a = 16 centimeters.
Subtracting 144144 from 400400 gives 256256, and the square root of 256256 is 1616.
3
Calculate the area of the triangle using the formula A=12bhA = \frac{1}{2}bh.
A=12×12×16=96 cm2A = \frac{1}{2} \times 12 \times 16 = 96\text{ cm}^2.
Substituting the base (1212) and the newly found height (1616) into the area formula gives the final answer.

Anahtar Kavram

Applying the Pythagorean theorem to find a missing side length, then calculating the triangle's area.
Tahmini Süre:1m 0s
Soru 131Soru →

A circle with center OO has points AA, BB, CC, and DD on its circumference.

• Line segment ABAB passes through the center OO.
• Line segment CDCD does not pass through OO.
• Line LL intersects the circle exactly at point AA.
• Line MM intersects the circle at points CC and BB, and extends infinitely in both directions.

Match each geometric term on the left with the notation that represents it on the right.

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Öğeler

Radius
Diameter
Chord
Tangent
Secant

Eşleşmeler

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Cevap

Radius corresponds to Line segment OA; Diameter corresponds to Line segment AB; Chord corresponds to Line segment CD; Tangent corresponds to Line L; Secant corresponds to Line M.
Each geometric term strictly defines a specific type of line or segment related to a circle. By systematically checking the endpoints and intersection points described in the stem, we accurately pair each term to its corresponding notation.

Adım Adım Çözüm

1
Evaluate Line segment OA
Matches Radius
Since O is the center and A is on the circle, the segment connecting them is the radius.
2
Evaluate Line segment AB
Matches Diameter
The segment connects two points on the circle and passes through the center O.
3
Evaluate Line segment CD
Matches Chord
The segment connects two points on the circle but does not pass through the center.
4
Evaluate Line L
Matches Tangent
The line touches the circle at exactly one point, which is the definition of a tangent line.
5
Evaluate Line M
Matches Secant
The line extends infinitely and intersects the circle at exactly two points.

Anahtar Kavram

Geometric definitions of circle components
Soru 132Soru →

A rectangular swimming pool has a diagonal length of 20 meters20\text{ meters} and a width of 12 meters12\text{ meters}. What is the perimeter of the swimming pool?

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Cevap: 56 meters56\text{ meters}

Cevap

56 meters56\text{ meters}
The diagonal of a rectangle creates a right triangle where the diagonal is the hypotenuse. Using the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2), the missing length is 202−122=400−144=256=16 meters\sqrt{20^2 - 12^2} = \sqrt{400 - 144} = \sqrt{256} = 16\text{ meters}. The perimeter of the rectangle is the total distance around the outside, which is calculated as 2×(width+length)=2×(12+16)=2×28=56 meters2 \times (\text{width} + \text{length}) = 2 \times (12 + 16) = 2 \times 28 = 56\text{ meters}.

Adım Adım Çözüm

1
Identify the geometric relationship between the dimensions.
The width, length, and diagonal of a rectangle form a right triangle where the diagonal is the hypotenuse.
Rectangles have right angles at all corners, allowing the use of the Pythagorean theorem.
2
Use the Pythagorean theorem to find the length of the pool.
122+length2=20212^2 + \text{length}^2 = 20^2, which becomes 144+length2=400144 + \text{length}^2 = 400. Subtracting 144144 gives length2=256\text{length}^2 = 256, so the length is 16 meters16\text{ meters}.
The Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) allows us to find a missing side of a right triangle when two sides are known.
3
Calculate the perimeter of the rectangle.
Perimeter = 2×(width+length)=2×(12+16)=2×28=56 meters2 \times (\text{width} + \text{length}) = 2 \times (12 + 16) = 2 \times 28 = 56\text{ meters}.
The question asks for the perimeter of the entire rectangular pool, which requires combining all four outer sides.

Anahtar Kavram

Applying the Pythagorean theorem to find missing dimensions before calculating perimeter.
Tahmini Süre:1m 0s
Soru 133Soru →

Provide the missing numerical values to complete the calculations for the stage construction.

Aşağıdaki boşlukları doldurun

A theater crew is reinforcing a rectangular stage that measures 1616 feet in width and 3030 feet in length. They place a diagonal steel support beam underneath, running directly from one corner to the opposite corner. By applying the Pythagorean theorem, the length of this diagonal support beam is calculated to be feet. Consequently, the total perimeter of the right triangle formed by the width, length, and the new diagonal beam is feet.
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Cevap

The diagonal support beam is 34 feet long, and the total perimeter of the right triangle is 80 feet.
The width and length of the rectangular stage act as the two legs of a right triangle. Using the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2), we substitute the known legs: 162+302=256+900=115616^2 + 30^2 = 256 + 900 = 1156. The square root of 11561156 is 3434, so the diagonal hypotenuse is 3434 feet. The perimeter of this triangle is the sum of its three sides: 16+30+34=8016 + 30 + 34 = 80 feet.

Adım Adım Çözüm

1
Identify the lengths of the two legs of the right triangle formed by the stage's dimensions.
Leg a = 16 feet, Leg b = 30 feet.
The width and length of a rectangle meet at a 90-degree angle, serving as the legs of the right triangle.
2
Apply the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) to calculate the hypotenuse.
162+302=256+900=115616^2 + 30^2 = 256 + 900 = 1156. Taking the square root, c=1156=34c = \sqrt{1156} = 34 feet.
The diagonal beam forms the hypotenuse of the right triangle spanning opposite corners.
3
Calculate the perimeter of the newly formed right triangle.
Perimeter = 16+30+34=8016 + 30 + 34 = 80 feet.
The perimeter of a triangle is the total sum of its three side lengths.

Anahtar Kavram

Applying the Pythagorean theorem to find a missing hypotenuse, and calculating the perimeter of a right triangle.
Soru 134Soru →

A circular steel plate is cut into 66 equal sectors. If the total area of the original plate was 144π cm2144\pi \text{ cm}^2, what is the arc length of the outer edge of one sector?

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Cevap: 4π cm4\pi \text{ cm}

Cevap

The arc length of one sector is 4π cm4\pi \text{ cm}.
The correct answer is found by first using the total area (144π144\pi) to find the radius (r=12r = 12). Next, the full circumference is calculated using C=2πrC = 2\pi r, resulting in 24π24\pi. Finally, because the plate is divided into 6 equal sectors, the full circumference is divided by 6, giving an arc length of 4π cm4\pi \text{ cm}.

Adım Adım Çözüm

1
Find the radius of the original circular plate.
Using the area formula A=πr2A = \pi r^2, substitute the given area: 144π=πr2144\pi = \pi r^2. Dividing by π\pi gives r2=144r^2 = 144, so the radius r=12 cmr = 12 \text{ cm}.
The radius is needed to calculate the total circumference of the circle.
2
Calculate the full circumference of the plate.
Using the circumference formula C=2πrC = 2\pi r, substitute r=12r = 12 to get C=2π(12)=24π cmC = 2\pi(12) = 24\pi \text{ cm}.
The arc length of a sector is a fraction of the circle's total circumference.
3
Determine the arc length of one of the 6 equal sectors.
Divide the full circumference by 6: 24π6=4π cm\frac{24\pi}{6} = 4\pi \text{ cm}.
Since the plate is cut into 6 equal sectors, the outer edge of one sector is exactly one-sixth of the total circumference.

Anahtar Kavram

The relationship between a circle's area, its circumference, and the proportional arc length of its sectors.
Soru 135Soru →

A custom corner desk is shaped like a right triangle so it fits perfectly against two perpendicular walls. The sections of the desk that touch the walls measure 24 inches24\text{ inches} and 10 inches10\text{ inches} in length. What is the length of the front edge of the desk in inches?

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Cevap: 26

Cevap

26
Because the walls meet at a perpendicular right angle, the corner desk forms a right triangle. The edges touching the walls act as the legs (a=24a = 24, b=10b = 10), and the front edge is the hypotenuse (cc). Using the Pythagorean Theorem (a2+b2=c2a^2 + b^2 = c^2), we square both legs to get 576576 and 100100. Adding these together gives 676676. The square root of 676676 is 2626, which is the exact length of the front edge in inches.

Adım Adım Çözüm

1
Identify the known sides of the right triangle
Legs are a=24a = 24 and b=10b = 10.
The walls are perpendicular, forming a 90∘90^{\circ} angle. Therefore, the edges touching the walls are the legs of a right triangle.
2
Set up the Pythagorean Theorem
242+102=c224^2 + 10^2 = c^2
The Pythagorean Theorem (a2+b2=c2a^2 + b^2 = c^2) is the standard formula used to find the missing hypotenuse (cc) when both legs are known.
3
Square the lengths of the legs
576+100=c2576 + 100 = c^2
Evaluating the exponents is the required next step in the order of operations.
4
Add the squared values
676=c2676 = c^2
Combining the squares of the legs gives the square of the hypotenuse.
5
Find the square root of the sum
c=26c = 26
Taking the square root of 676676 isolates cc, revealing the true length of the desk's front edge.

Anahtar Kavram

Using the Pythagorean Theorem (a2+b2=c2a^2 + b^2 = c^2) to calculate the length of a hypotenuse.

Alternatif Yöntem

You can solve this rapidly without large calculations by recognizing special Pythagorean triples. This triangle is a scaled-up version of the fundamental 5−12−135-12-13 right triangle. Multiplying each side of a 5−12−135-12-13 triangle by 22 gives side lengths of 1010, 2424, and 2626. Since the legs are 1010 and 2424, the hypotenuse must be 2626.
Tahmini Süre:45s
Soru 136Soru →

The circular foundation of a radar dome has a circumference of 36π feet36\pi \text{ feet}. What is the area of this circular foundation, in square feet?

(Enter only the numerical coefficient of π\pi in your answer. For example, if the area is 100π100\pi, enter 100.)

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Cevap: 324

Cevap

324
The circumference of a circle is calculated using C=2πrC = 2\pi r. Setting the given circumference 36π=2πr36\pi = 2\pi r gives a radius of 18 feet18 \text{ feet}. The area is found using A=πr2A = \pi r^2, which becomes A=π(18)2=324π square feetA = \pi(18)^2 = 324\pi \text{ square feet}. Since the question asks for the numerical coefficient of π\pi, the correct value to enter is 324.

Adım Adım Çözüm

1
Find the radius of the circular foundation from its given circumference.
r=18r = 18
The circumference formula is C=2πrC = 2\pi r. Setting 2πr=36π2\pi r = 36\pi allows us to solve for the radius.
2
Calculate the area of the foundation using the radius.
A=324πA = 324\pi
The area formula is A=πr2A = \pi r^2. Substituting r=18r = 18 gives A=π(18)2=324πA = \pi(18)^2 = 324\pi.
3
Extract the numerical coefficient of π\pi for the final answer.
324
The question explicitly asks to enter only the numerical coefficient of π\pi.

Anahtar Kavram

Calculating the area of a circle by first deriving the radius from its circumference
Soru 137Soru →

A solid rectangular block has a square base with an area of 2525 square inches. If the total volume of the block is 150150 cubic inches, what is the total surface area of the block in square inches?

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Cevap: 170170

Cevap

170170
To find the total surface area, all dimensions of the block must be known. The side length of the square base is 25=5\sqrt{25} = 5 inches. The height is the volume divided by the base area: 150÷25=6150 \div 25 = 6 inches. The total surface area is the sum of the areas of all six faces: two square bases (2×25=502 \times 25 = 50) and four identical rectangular sides (4×5×6=1204 \times 5 \times 6 = 120). The total is 50+120=17050 + 120 = 170 square inches.

Adım Adım Çözüm

1
Find the side length of the square base.
55 inches
The area of a square is the side length squared (s2=25s^2 = 25), so the side length is the square root of the area.
2
Find the height of the rectangular block.
66 inches
The volume of a rectangular block is the base area multiplied by the height (V=B×hV = B \times h). Dividing the volume (150150) by the base area (2525) gives the height.
3
Calculate the total surface area of the block.
170170 square inches
The total surface area is the sum of the two square bases (2×25=502 \times 25 = 50) and the four identical rectangular sides (4×5×6=1204 \times 5 \times 6 = 120). Adding these together yields 50+120=17050 + 120 = 170.

Anahtar Kavram

Volume and Surface Area of Rectangular Prisms
Soru 138Soru →

A right-angled triangular bracket is used to support a shelf. The longest side (hypotenuse) of the bracket has a length represented by the expression 2x+12x + 1 inches, and the horizontal leg has a length represented by 3x−63x - 6 inches. If x=6x = 6, what is the length of the vertical leg?

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Cevap: 5

Cevap

The vertical leg has a length of 55 inches.
After substituting x=6x = 6, the hypotenuse is 1313 inches and the horizontal leg is 1212 inches. Using the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2), we get b2+122=132b^2 + 12^2 = 13^2. Solving for bb yields b2=25b^2 = 25, which means b=5b = 5.

Adım Adım Çözüm

1
Substitute x=6x = 6 into the expression for the hypotenuse.
2(6)+1=12+1=13 inches2(6) + 1 = 12 + 1 = 13\text{ inches}
To find the numerical length of the longest side.
2
Substitute x=6x = 6 into the expression for the horizontal leg.
3(6)−6=18−6=12 inches3(6) - 6 = 18 - 6 = 12\text{ inches}
To find the numerical length of the given leg.
3
Apply the Pythagorean theorem to find the vertical leg (let's call it bb).
b2+122=132b^2 + 12^2 = 13^2
The Pythagorean theorem relates the three sides of a right triangle: a2+b2=c2a^2 + b^2 = c^2.
4
Solve for bb.
b2+144=169⇒b2=169−144=25⇒b=5 inchesb^2 + 144 = 169 \Rightarrow b^2 = 169 - 144 = 25 \Rightarrow b = 5\text{ inches}
To calculate the final missing side length.

Anahtar Kavram

To find a missing leg in a right triangle when given the hypotenuse and the other leg, substitute the known values into the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) and solve for the unknown leg by subtracting the squares and taking the square root.

Alternatif Yöntem

Recognize that 55, 1212, and 1313 form a common Pythagorean triple. Once the hypotenuse (1313) and one leg (1212) are calculated, the other leg must immediately be 55.
Tahmini Süre:1m 15s
Soru 139Soru →

Pair the given geometric descriptions of 3D figures with their corresponding exact volumes.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

A cylinder with a base radius of 44 and a height of 55
A rectangular prism measuring 88 units long, 55 units wide, and 22 units high
A cube having an edge length of 44
A sphere with a radius of 33

Eşleşmeler

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Cevap

The cylinder matches 80π80\pi, the rectangular prism matches 8080, the cube matches 6464, and the sphere matches 36π36\pi.
Matching each figure to its correct volume requires applying the specific volume formula for that geometric shape: cylinder (V=πr2hV = \pi r^2h), rectangular prism (V=lwhV = lwh), cube (V=s3V = s^3), and sphere (V=43πr3V = \frac{4}{3}\pi r^3).

Adım Adım Çözüm

1
Calculate the volume of the cylinder.
V=π(42)(5)=80πV = \pi(4^2)(5) = 80\pi
Applying the cylinder volume formula V=πr2hV = \pi r^2h.
2
Calculate the volume of the rectangular prism.
V=8×5×2=80V = 8 \times 5 \times 2 = 80
Applying the rectangular prism volume formula V=lwhV = lwh.
3
Calculate the volume of the cube.
V=43=64V = 4^3 = 64
Applying the cube volume formula V=s3V = s^3.
4
Calculate the volume of the sphere.
V=43π(33)=36πV = \frac{4}{3}\pi(3^3) = 36\pi
Applying the sphere volume formula V=43πr3V = \frac{4}{3}\pi r^3.

Anahtar Kavram

Volume and Surface Area of 3D Figures
Soru 140Soru →

Read the scenario and provide the missing numerical value to complete the sentence.

Aşağıdaki boşlukları doldurun

A guy wire is securely attached to a vertical radio mast at a height of 60 feet60\text{ feet} above the level ground. The other end of the wire is anchored to the ground exactly 25 feet25\text{ feet} from the base of the mast. Assuming the mast is perfectly perpendicular to the ground, the length of the guy wire is feet.
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Cevap

65
The mast, the ground, and the guy wire form a right triangle where the mast and the ground act as the two legs, and the guy wire is the hypotenuse. Using the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2), we substitute the given leg lengths: 252+602=c225^2 + 60^2 = c^2. This simplifies to 625+3600=4225625 + 3600 = 4225. The square root of 42254225 is 6565, meaning the guy wire is 65 feet65\text{ feet} long. Additionally, recognizing that the side lengths (25,60,6525, 60, 65) are a multiple of the common 5−12−135-12-13 Pythagorean triple (each multiplied by 55) provides a quick way to solve the problem without large calculations.

Adım Adım Çözüm

1
Identify the shape formed by the scenario.
A right triangle is formed by the vertical mast, the level ground, and the diagonal guy wire.
The mast is perpendicular to the ground, creating a 90-degree angle.
2
Set up the Pythagorean theorem equation.
a2+b2=c2a^2 + b^2 = c^2, where a=25a = 25 and b=60b = 60.
The legs of the right triangle are the distance along the ground (25 ft) and the height up the mast (60 ft). We need to find the hypotenuse, cc.
3
Calculate the squares of the leg lengths.
252=62525^2 = 625 and 602=360060^2 = 3600.
Squaring the values is required before adding them to find the square of the hypotenuse.
4
Add the squared values together.
625+3600=4225625 + 3600 = 4225.
This sum represents c2c^2, the square of the guy wire's length.
5
Find the square root of the sum to determine the final length.
4225=65\sqrt{4225} = 65.
Taking the square root of c2c^2 gives the actual length of the hypotenuse, cc.

Anahtar Kavram

Pythagorean Theorem Application
ÖncekiSayfa 7 / 8Sonraki
Geometry Alıştırma Soruları — Armed Services Vocational Aptitude Battery (ASVAB) — Sayfa 7 | Examkin