Probability and Statistics Alıştırma Soruları — Armed Services Vocational Aptitude Battery (ASVAB) — Sayfa 3

Soru 41Soru →

A logistics officer is inspecting a shipment of $120$ combat helmets. The shipment contains $45$ large helmets, $35$ medium helmets, $24$ small helmets, and the remaining helmets are extra-large. If the officer randomly selects one helmet for quality control, what is the probability that it is an extra-large helmet? Express your answer as a fraction in simplest form.

Cevabı ve açıklamayı göster

Cevap: 2/15; 2 / 15

Cevap

2/15

The correct answer is derived by first finding the number of extra-large helmets. Subtracting the known sizes from the total yields

120 - 104 = 16

extra-large helmets. The probability of selecting an extra-large helmet is the ratio of extra-large helmets to the total inventory, which is

\frac{16}{120}

. Simplifying this fraction by dividing both the numerator and the denominator by their greatest common divisor (

8

) yields the final probability of

\frac{2}{15}

.

Adım Adım Çözüm

1

Calculate the total number of known helmets.

45 + 35 + 24 = 104

To find the number of extra-large helmets, we first need to determine how many helmets belong to the other given size categories.

2

Determine the number of extra-large helmets.

120 - 104 = 16

Subtracting the sum of the known sizes from the total number of helmets gives the remaining count, which represents the extra-large helmets.

3

Set up the probability fraction.

\frac{16}{120}

The probability of a single event is the number of favorable outcomes (

16

extra-large helmets) divided by the total number of possible outcomes (

120

total helmets).

4

Simplify the fraction.

\frac{2}{15}

Divide the numerator and denominator by their greatest common divisor, which is

8

(

16 \div 8 = 2

and

120 \div 8 = 15

).

Anahtar Kavram

Single Event Probability

Soru 42Soru →

A supply room contains 25 identical-looking computer mice, of which 10 are wireless and 15 are wired. If an IT technician randomly selects two mice from the room one after the other without replacement, what is the probability that both selected mice are wireless? (Express your answer as a decimal.)

Cevabı ve açıklamayı göster

Cevap: 0.15

Cevap

0.15

The correct answer is found by multiplying the probability of the first event by the conditional probability of the second event. First draw:

\frac{10}{25}

. Second draw:

\frac{9}{24}

. Multiplying these gives

\frac{90}{600}

, which simplifies exactly to

0.15

.

Adım Adım Çözüm

1

Determine the probability of the first event.

The probability of drawing the first wireless mouse is

\frac{10}{25}

.

There are 10 target items (wireless mice) out of 25 total items.

2

Determine the probability of the second event given the first event occurred.

The probability of drawing a second wireless mouse is

\frac{9}{24}

.

Because the selection is without replacement, one wireless mouse has been removed, leaving 9 wireless mice out of 24 total mice.

3

Calculate the compound probability.

\frac{10}{25} \times \frac{9}{24} = 0.15

For dependent events occurring in sequence, multiply the probability of the first event by the conditional probability of the second event.

Anahtar Kavram

Compound Probability (Dependent Events)

Tahmini Süre:1m 0s

Soru 43Soru →

A radar operator tracks the number of aircraft detected in their sector during $5$ consecutive hours. The hourly counts are $24$ , $18$ , $35$ , $21$ , and $12$ . What is the median number of aircraft detected per hour?

21

22

35

23

Cevabı ve açıklamayı göster

Cevap: $21$

Cevap

The median number of aircraft detected per hour is

21

.

The median is found by arranging the values in ascending order (

12

,

18

,

21

,

24

,

35

) and identifying the middle value. The middle number is

21

.

Adım Adım Çözüm

1

Order the hourly aircraft counts from least to greatest.

12

,

18

,

21

,

24

,

35

The median is the middle value of an ordered dataset.

2

Identify the middle number in the sorted sequence.

The third number is

21

.

Since there are

5

data points (an odd number), the median is exactly in the middle.

Anahtar Kavram

The median is the middle value of a sorted dataset. If a dataset has an odd number of values, the median is the single middle number.

Soru 44Soru →

A recruiting station commander records the number of new applicants processed each day for $5$ consecutive days. The daily counts are $3$ , $3$ , $5$ , $8$ , and $11$ . Match each measure of central tendency to its correct calculated value for this data set.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Cevabı ve açıklamayı göster

Cevap

The correct matches are: Mode pairs with

3

, Median pairs with

5

, and Mean pairs with

6

.

Based on the data set of

3, 3, 5, 8, 11

, the mode is

3

because it appears most frequently. The median is

5

because it is the central value of the ordered list. The mean is

6

because the sum (

30

) divided by the count (

5

) equals

6

.

Adım Adım Çözüm

1

Determine the mode of the data set.

Mode =

3

The mode is the number that appears most frequently.

3

is the only number that appears more than once.

2

Determine the median of the data set.

Median =

5

The data is already arranged in ascending order:

3, 3, 5, 8, 11

. The middle number (third position out of five) is

5

.

3

Calculate the mean of the data set.

Mean =

6

Calculate the sum of the numbers (

3 + 3 + 5 + 8 + 11 = 30

) and divide by the number of days (

5

):

30 \div 5 = 6

.

Anahtar Kavram

Calculating the primary measures of central tendency (mean, median, and mode) for a data set.

Tahmini Süre:45s

Soru 45Soru →

A game at a school carnival involves drawing two wooden blocks from a bag without looking. The bag initially contains 9 red blocks, 7 yellow blocks, and 5 blue blocks. If a player draws two blocks one after the other without replacing the first block, what is the probability that the first block drawn is blue and the second block drawn is yellow?

\frac{1}{12}

\frac{5}{63}

\frac{4}{7}

\frac{12}{41}

Cevabı ve açıklamayı göster

Cevap: $\frac{1}{12}$

Cevap

\frac{1}{12}

The correct answer is found by multiplying the probability of the first event by the probability of the second event, accounting for the reduced total pool. The probability of drawing a blue block first is

\frac{5}{21}

. Because this block is not replaced, only 20 blocks remain in the bag. The probability of then drawing a yellow block is

\frac{7}{20}

. Multiplying these probabilities gives

\frac{5}{21} \times \frac{7}{20} = \frac{35}{420}

, which simplifies to

\frac{1}{12}

.

Adım Adım Çözüm

1

Calculate the total number of blocks initially in the bag.

9 \text{ (red)} + 7 \text{ (yellow)} + 5 \text{ (blue)} = 21 \text{ total blocks}

The denominator for the first probability requires the total count of all possible outcomes.

2

Determine the probability of the first event (drawing a blue block).

\frac{5}{21}

There are 5 blue blocks out of the 21 total blocks.

3

Determine the probability of the second event (drawing a yellow block) given that a blue block was already removed.

\frac{7}{20}

Because the first block was not replaced, there are now

21 - 1 = 20

total blocks. There are still 7 yellow blocks in the bag.

4

Multiply the probabilities of the two dependent events and simplify.

\frac{5}{21} \times \frac{7}{20} = \frac{35}{420} = \frac{1}{12}

To find the compound probability of both events occurring in sequence, you must multiply their individual probabilities.

Anahtar Kavram

Dependent Compound Probability

Soru 46Soru →

A sonar technician records the number of acoustic anomalies detected during $5$ consecutive watch shifts. The counts are $7, 2, 8, 2$ , and $6$ . What is the median number of anomalies detected per shift?

2

5

6

8

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

6

To find the median, the values must first be ordered from least to greatest:

2, 2, 6, 7, 8

. Because there is an odd number of values (

5

), the median is the single middle number. The third number in this sorted list is

6

.

Adım Adım Çözüm

1

Order the given numbers from least to greatest.

2, 2, 6, 7, 8

The median must always be found from a sorted list of values.

2

Identify the middle value in the sorted list.

Since there are

5

values, the middle value is the

3

rd number, which is

6

.

For an odd number of data points, the median is exactly the single middle number.

Anahtar Kavram

The median is the middle value of a data set when the numbers are arranged in numerical order.

Soru 47Soru →

A navigation briefcase contains $15$ identical-looking USB drives. $9$ of the drives contain map data, and $6$ contain communication protocols. If a pilot randomly selects two drives from the briefcase one after the other without replacing the first, what is the probability that both selected drives contain map data? Express your answer as a simplified fraction.

Cevabı ve açıklamayı göster

Cevap: 12/35; 12 / 35

Cevap

12/35

The correct answer is derived by multiplying the initial probability of drawing a map drive (

\frac{9}{15}

) by the updated probability of drawing a second map drive from the remaining inventory (

\frac{8}{14}

). Simplifying the fractions to

\frac{3}{5}

and

\frac{4}{7}

before multiplying gives the final result of

\frac{12}{35}

.

Adım Adım Çözüm

1

Determine the probability of selecting a map data drive on the first draw.

P(First Map) =

9

map drives /

15

total drives =

\frac{9}{15} = \frac{3}{5}

.

The probability of a single event is the number of favorable outcomes divided by the total number of possible outcomes.

2

Determine the probability of selecting a map data drive on the second draw, given that one map drive has already been removed.

P(Second Map) =

8

map drives remaining /

14

total drives remaining =

\frac{8}{14} = \frac{4}{7}

.

Since the first drive is not replaced, both the number of map drives and the total number of drives decrease by one. This is a dependent event.

3

Calculate the compound probability of both dependent events occurring.

\frac{3}{5} \times \frac{4}{7} = \frac{12}{35}

.

To find the probability of two dependent events happening in sequence, you multiply the probability of the first event by the conditional probability of the second event.

Anahtar Kavram

Compound probability of dependent events (without replacement)

Soru 48Soru →

A motor pool dispatcher logs the number of vehicles dispatched each day from Monday to Friday. The daily totals are $11$ , $18$ , $23$ , $13$ , and $15$ . What is the mean number of vehicles dispatched per day?

Cevabı ve açıklamayı göster

Cevap: 16

Cevap

16

The mean is found by adding together all the numbers in the data set and then dividing by the count of numbers. The sum of

11

,

18

,

23

,

13

, and

15

is

80

. Because there are

5

values, dividing

80

by

5

results in a mean of

16

.

Adım Adım Çözüm

1

Calculate the sum of the dataset.

11 + 18 + 23 + 13 + 15 = 80

The first step in calculating the mean is finding the total sum of all values.

2

Count the number of values in the dataset.

5

days

The mean formula requires dividing the sum by the number of data points.

3

Divide the sum by the number of values.

80 \div 5 = 16

Dividing the total sum by the count of values yields the mean.

Anahtar Kavram

Calculating the arithmetic mean of a dataset

Soru 49Soru →

A military supply depot has $6$ different types of field rations, $4$ different types of hydration packs, and $3$ different types of medical kits. A soldier must build a standardized supply bundle containing exactly $2$ different types of field rations, $1$ hydration pack, and $1$ medical kit. How many different supply bundles can be created?

180

360

72

22

Cevabı ve açıklamayı göster

Cevap: 180

Cevap

180

To find the total number of distinct supply bundles, we must calculate the number of ways to make each independent selection and multiply them together. First, calculating the number of ways to choose

2

rations from

6

requires combinations because order does not matter:

C(6, 2) = 15

. There are

4

ways to choose a hydration pack and

3

ways to choose a medical kit. Multiplying these together using the Fundamental Counting Principle yields

15 \times 4 \times 3 = 180

possible bundles.

Adım Adım Çözüm

1

Determine the number of ways to select the field rations.

C(6, 2) = \frac{6 \times 5}{2 \times 1} = 15

ways.

Since the order in which the two rations are selected does not matter, we use the combinations formula.

2

Determine the number of ways to select the hydration pack and the medical kit.

4

ways to select a hydration pack and

3

ways to select a medical kit.

Selecting

1

item from a group of

n

items gives

n

possible choices.

3

Calculate the total number of possible supply bundles.

15 \times 4 \times 3 = 180

different supply bundles.

Apply the Fundamental Counting Principle by multiplying the number of independent choices together.

Anahtar Kavram

Combinations and the Fundamental Counting Principle

Soru 50Soru →

A communications center needs to assemble a rapid response team from a pool of $7$ qualified technicians. The team must consist of exactly $1$ team chief and $3$ field technicians. The $3$ field technicians share identical duties. How many different rapid response teams can be formed?

Cevabı ve açıklamayı göster

Cevap: 140

Cevap

140

To find the total number of possible teams, we must account for the distinct roles across two stages of selection. First, we select

1

team chief from the

7

available technicians, which gives

7

options. Next, we select

3

field technicians from the remaining

6

technicians. Because the field technicians have identical roles, the order in which they are selected does not matter. This requires calculating a combination:

C(6,3) = \frac{6!}{3!(6-3)!} = 20

. Finally, using the Fundamental Counting Principle, we multiply the number of choices for the chief by the number of combinations for the field technicians:

7 \times 20 = 140

.

Adım Adım Çözüm

1

Select the team chief.

7 possible choices

There are 7 available technicians, and 1 must be chosen for the distinct role of team chief.

2

Select the field technicians.

20 possible combinations

After choosing the chief, 6 technicians remain. We need to select 3 for identical roles. Since order does not matter, this is a combination: C(6,3) = (6 × 5 × 4) / (3 × 2 × 1) = 20.

3

Calculate the total number of unique teams.

140 teams

Using the Fundamental Counting Principle, multiply the independent choices for each stage: 7 × 20 = 140.

Anahtar Kavram

Combining the Fundamental Counting Principle with combinations for multi-stage selection.

Soru 51Soru →

A communications specialist is inventorying a batch of hand-held radios. The batch contains $18$ VHF radios, $12$ UHF radios, and $20$ dual-band radios. If one radio is randomly selected for a quality check, what is the probability that it is a VHF radio? Express your answer as a simplified fraction.

Cevabı ve açıklamayı göster

Cevap: $9/25; 9 / 25; \frac{9}{25}$

Cevap

9/25

The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes. There are

18

VHF radios and a total of

50

radios (

18 + 12 + 20

). The probability is

\frac{18}{50}

, which simplifies to

\frac{9}{25}

by dividing both the numerator and the denominator by

2

.

Adım Adım Çözüm

1

Calculate the total number of radios in the batch.

18 + 12 + 20 = 50

The denominator of a probability fraction represents the total number of possible outcomes.

2

Identify the number of favorable outcomes.

18

VHF radios

The numerator of a probability fraction represents the number of favorable outcomes.

3

Set up the probability ratio and simplify.

\frac{18}{50} = \frac{9}{25}

Probability is the ratio of favorable outcomes to total outcomes, and the question asks for a simplified fraction.

Anahtar Kavram

Single event probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

Soru 52Soru →

An intelligence analyst has a container of map pins used for marking locations on a briefing board. The container holds $24$ red pins, $16$ blue pins, and $10$ green pins. If the analyst randomly selects one pin from the container, what is the probability that it is a blue pin?

\frac{8}{25}

\frac{8}{17}

\frac{12}{25}

\frac{2}{3}

Cevabı ve açıklamayı göster

Cevap: $\frac{8}{25}$

Cevap

The probability of selecting a blue pin is

\frac{8}{25}

.

The probability of a single event is found by dividing the number of favorable outcomes by the total number of outcomes. There are

16

blue pins (favorable outcomes) and a total of

50

pins (

24 + 16 + 10

). This creates the fraction

\frac{16}{50}

, which simplifies to

\frac{8}{25}

when both numbers are divided by

2

.

Adım Adım Çözüm

1

Determine the total number of possible outcomes.

24 \text{ (red)} + 16 \text{ (blue)} + 10 \text{ (green)} = 50 \text{ total pins}

The denominator of a probability fraction must represent all possible items that can be selected.

2

Identify the number of favorable outcomes.

16 \text{ blue pins}

The numerator must represent the specific event being asked for (selecting a blue pin).

3

Set up the probability fraction and simplify.

\frac{16}{50} = \frac{16 \div 2}{50 \div 2} = \frac{8}{25}

Fractions must always be reduced to their simplest form by dividing both the numerator and denominator by their greatest common factor.

Anahtar Kavram

Single Event Probability

Soru 53Soru →

A logistics officer needs to form a specialized transport convoy consisting of exactly $2$ cargo trucks and $1$ security vehicle. If there are $6$ available cargo trucks and $3$ available security vehicles, how many different combinations of vehicles can be selected for the convoy?

18

45

84

90

Cevabı ve açıklamayı göster

Cevap: 45

Cevap

45

The total number of convoy combinations is found by calculating the combinations for each vehicle type and multiplying them together. Choosing

2

cargo trucks from

6

yields

15

combinations, and choosing

1

security vehicle from

3

yields

3

combinations. Multiplying these results gives

45

possible convoys.

Adım Adım Çözüm

1

Calculate the number of ways to select the cargo trucks.

_{6}C_{2} = \frac{6!}{2!(6-2)!} = 15

Since the selection order does not matter, use combinations to choose

2

cargo trucks from the

6

available.

2

Calculate the number of ways to select the security vehicle.

_{3}C_{1} = 3

Use combinations to choose

1

security vehicle from the

3

available.

3

Determine the total combinations for the convoy.

15 \times 3 = 45

Apply the Fundamental Counting Principle by multiplying the independent category selections together.

Anahtar Kavram

Combinations and the Fundamental Counting Principle

Tahmini Süre:1m 30s

Soru 54Soru →

A motor pool has a fleet of $40$ vehicles available for dispatch. The fleet consists of $25$ HMMWVs, $10$ transport trucks, and $5$ tactical ambulances. If a dispatcher selects one vehicle at random for a surprise inspection, what is the probability, expressed as a fraction in simplest form, that the selected vehicle is a tactical ambulance?

Cevabı ve açıklamayı göster

Cevap: 1/8; 1 / 8

Cevap

1/8

The probability of an event is found by dividing the number of favorable outcomes by the total number of possible outcomes. There are 5 tactical ambulances out of a total 40 vehicles. The resulting fraction is 5/40, which simplifies to 1/8 by dividing both the numerator and the denominator by 5.

Adım Adım Çözüm

1

Identify the total number of possible outcomes.

The total number of vehicles in the motor pool is

40

.

The denominator of a single event probability fraction represents the total number of items in the population.

2

Identify the number of favorable outcomes.

There are

5

tactical ambulances.

The numerator represents the count of the specific target items being selected.

3

Set up the probability ratio and simplify the fraction.

The initial ratio is

\frac{5}{40}

. Dividing both the numerator and denominator by

5

yields

\frac{1}{8}

.

Probability is the ratio of favorable outcomes to total outcomes, and the question requires the answer in simplest fraction form.

Anahtar Kavram

Single Event Probability

Soru 55Soru →

A supply room bin contains a mixture of $30$ electronic components. There are $12$ resistors, $10$ capacitors, and $8$ inductors. If a technician randomly selects one component from the bin, what is the probability that the selected component is an inductor?

\frac{4}{15}

\frac{4}{11}

\frac{11}{15}

\frac{15}{4}

Cevabı ve açıklamayı göster

Cevap: $\frac{4}{15}$

Cevap

The probability of selecting an inductor is

\frac{4}{15}

.

The correct probability is found by dividing the number of inductors (

8

) by the total number of components (

30

). This gives the fraction

\frac{8}{30}

, which simplifies to

\frac{4}{15}

by dividing both the numerator and the denominator by their greatest common factor,

2

.

Adım Adım Çözüm

1

Identify the total number of possible outcomes.

Total components =

30

The denominator for single event probability is always the total number of items available.

2

Identify the number of favorable outcomes.

Number of inductors =

8

The numerator represents the specific event being measured (selecting an inductor).

3

Set up the probability fraction and simplify.

Probability =

\frac{8}{30} = \frac{4}{15}

Probability is favorable outcomes over total outcomes, and the resulting fraction must be reduced to its simplest form.

Anahtar Kavram

Single Event Probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

Soru 56Soru →

A supply cabinet contains $10$ identical safety helmets, of which $2$ are yellow and $8$ are white. A construction worker randomly selects a helmet, records its color, returns it to the cabinet, and then randomly selects a second helmet. What is the probability of selecting a yellow helmet both times? Express your answer as a decimal.

Cevabı ve açıklamayı göster

Cevap: 0.04

Cevap

0.04

Since the helmet is replaced after the first draw, the two events are independent. The probability of drawing a yellow helmet is

\frac{2}{10}

(or

0.2

). To find the probability of drawing a yellow helmet twice in a row, multiply the probabilities of the two independent events:

0.2 \times 0.2 = 0.04

.

Adım Adım Çözüm

1

Find the probability of the first event.

\frac{2}{10}

or

0.2

There are

2

yellow helmets out of

10

total.

2

Find the probability of the second event.

\frac{2}{10}

or

0.2

Because the helmet was replaced, the total number and the number of yellow helmets remain the same.

3

Calculate the compound probability.

0.04

For independent events, multiply the individual probabilities together:

0.2 \times 0.2 = 0.04

.

Anahtar Kavram

The probability of two independent events occurring is the product of their individual probabilities:

P(A \text{ and } B) = P(A) \times P(B)

.

Soru 57Soru →

A motor pool dispatcher has a set of $6$ vehicle keys on a desk. Exactly $2$ of the keys belong to trucks, and $4$ belong to sedans. If the dispatcher blindly grabs two keys, one after the other without putting the first back, what is the probability that both keys belong to trucks?

\frac{1}{9}

\frac{2}{15}

\frac{1}{15}

\frac{3}{11}

Cevabı ve açıklamayı göster

Cevap: $\frac{1}{15}$

Cevap

\frac{1}{15}

The correct answer accurately calculates the compound probability of dependent events. The chance of grabbing a truck key first is 2/6. Because that key is held and not replaced, there is only 1 truck key left among the 5 remaining keys, making the chance of the second draw 1/5. Multiplying these fractions (2/6 × 1/5) results in 2/30, which simplifies to 1/15.

Adım Adım Çözüm

1

Determine the probability of selecting a truck key on the first draw.

\frac{2}{6}

There are

2

truck keys out of a total of

6

keys.

2

Determine the probability of selecting a truck key on the second draw, assuming one truck key has already been removed.

\frac{1}{5}

Since one truck key was taken and not replaced, there is now

1

truck key remaining out of a total of

5

keys.

3

Multiply the probabilities of the two dependent events to find the compound probability.

\frac{2}{6} \times \frac{1}{5} = \frac{2}{30} = \frac{1}{15}

The probability of two dependent events both occurring is the product of their individual probabilities.

Anahtar Kavram

Compound Probability (Dependent Events)

Soru 58Soru →

Match each counting scenario to the mathematical concept that is used to solve it.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Cevabı ve açıklamayı göster

Cevap

The cleaning crew matches to Combination, the spelling bee winners matches to Permutation, and the lunch menu matches to the Fundamental Counting Principle.

Each scenario perfectly aligns with the core definition of its matching counting principle based on whether order matters, and whether the events are sequential and independent.

Adım Adım Çözüm

1

Analyze the volunteer scenario to determine if order matters.

It matches to a Combination.

Because the members of a cleaning crew have identical roles, selecting Person A then Person B is exactly the same as selecting Person B then Person A.

2

Analyze the spelling bee scenario to determine if order matters.

It matches to a Permutation.

Since 1st, 2nd, and 3rd places are distinct, the arrangement or sequence of the winners matters.

3

Analyze the lunch menu scenario to identify the counting structure.

It matches to the Fundamental Counting Principle.

The scenario involves a sequence of independent events (choosing from different categories), which requires multiplying the number of choices.

Anahtar Kavram

Distinguishing between combinations (order does not matter), permutations (order matters), and the Fundamental Counting Principle (multiplying independent events).

Soru 59Soru →

A military dining facility offers $5$ different main courses, $3$ different side dishes, and $4$ different beverages. If a standard meal consists of exactly one main course, one side dish, and one beverage, how many different meal combinations can be chosen?

12

19

60

20

Cevabı ve açıklamayı göster

Cevap: 60

Cevap

There are

60

different meal combinations possible.

The correct answer is

60

. According to the Fundamental Counting Principle, when there are multiple independent choices to be made to form a single outcome, the total number of combinations is found by multiplying the number of options for each choice. Here, we multiply the

5

main courses by the

3

side dishes and the

4

beverages:

5 \times 3 \times 4 = 60

possible meal combinations.

Adım Adım Çözüm

1

Identify the number of available choices for each part of the meal.

Main courses =

5

, Side dishes =

3

, Beverages =

4

.

The Fundamental Counting Principle requires knowing the total number of options for each independent selection stage.

2

Apply the Fundamental Counting Principle by multiplying the choices together.

5 \times 3 \times 4

When selections are made in sequence and are independent of one another, the total number of combinations is the product of the number of options at each individual step.

3

Calculate the final product.

60

Multiplying the choices yields the total possible unique meal combinations.

Anahtar Kavram

Fundamental Counting Principle

Probability and Statistics

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