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Zorluk: OrtaIPv6 Addressing and Prefixes

A network engineer is deploying IPv6 across an enterprise branch using the assigned global unicast prefix 2001:db8:85a3::/482001:\text{db8}:85\text{a}3::/48. Interfaces are set to use SLAAC with EUI-64 interface identifier generation. Which two statements correctly describe the prefix subnetting and EUI-64 address generation for this implementation? (Select TWO.)

  1. Subnetting the 2001:db8:85a3::/482001:\text{db8}:85\text{a}3::/48 prefix into standard /64/64 subnets yields 65,53665,536 (2162^{16}) unique subnets.Cevap
  2. A host with MAC address 70:6D:15:AB:CD:EF70:6\text{D}:15:\text{AB}:\text{CD}:\text{EF} using EUI-64 auto-configuration generates the interface identifier 726D:15FF:FEAB:CDEF726\text{D}:15\text{FF}:\text{FEAB}:\text{CDEF}.Cevap
  3. C
    Subnetting the /48/48 prefix into /64/64 subnets yields 65,53465,534 usable subnets because the first and last subnets are reserved for network and broadcast identities.
  4. D
    Generating an EUI-64 interface ID from a 48-bit MAC address requires inserting the 16-bit hex value FFFF\text{FFFF} between the OUI and vendor-assigned serial number.
  5. E
    The prefix 2001:db8:85a3::/482001:\text{db8}:85\text{a}3::/48 falls within the Unique Local IPv6 address block allocated for non-routable private enterprise networks.

Cevap

Subnetting a /48/48 prefix into /64/64 subnets produces 65,53665,536 unique subnets, and converting the MAC address 70:6D:15:AB:CD:EF70:6\text{D}:15:\text{AB}:\text{CD}:\text{EF} via EUI-64 produces 726D:15FF:FEAB:CDEF726\text{D}:15\text{FF}:\text{FEAB}:\text{CDEF}.
Subnetting a /48/48 prefix to /64/64 provides 1616 subnet bits (6448=1664 - 48 = 16), giving 216=65,5362^{16} = 65,536 subnets without subtracting any reserved subnets. Additionally, converting the MAC address 70:6D:15:AB:CD:EF70:6\text{D}:15:\text{AB}:\text{CD}:\text{EF} to EUI-64 splits the address into 706D:15706\text{D}:15 and AB:CD:EF\text{AB}:\text{CD}:\text{EF}, inserts FFFE\text{FFFE} to form 706D:15FF:FEAB:CDEF706\text{D}:15\text{FF}:\text{FEAB}:\text{CDEF}, and flips the 7th bit of 0x700\text{x}70 (0111000020111\,0000_2) to 0x720\text{x}72 (0111001020111\,0010_2), giving 726D:15FF:FEAB:CDEF726\text{D}:15\text{FF}:\text{FEAB}:\text{CDEF}.

Adım Adım Çözüm

1
Calculate the available subnet bits and total subnets from /48/48 to /64/64.
Subnet bits = 6448=1664 - 48 = 16. Total subnets = 216=65,5362^{16} = 65,536.
IPv6 does not deduct subnets for network or broadcast designations.
2
Perform EUI-64 interface ID conversion on MAC address 70:6D:15:AB:CD:EF70:6\text{D}:15:\text{AB}:\text{CD}:\text{EF}.
Insert FFFE\text{FFFE} between 70:6D:1570:6\text{D}:15 and AB:CD:EF\text{AB}:\text{CD}:\text{EF} to get 706D:15FF:FEAB:CDEF706\text{D}:15\text{FF}:\text{FEAB}:\text{CDEF}. Flip the 7th bit of byte 11 (0x70=011100002011100102=0x720\text{x}70 = 0111\,0000_2 \rightarrow 0111\,0010_2 = 0\text{x}72), yielding 726D:15FF:FEAB:CDEF726\text{D}:15\text{FF}:\text{FEAB}:\text{CDEF}.
EUI-64 standard requires inserting FFFE\text{FFFE} in the center of the MAC address and setting the U/L bit to 1 for globally unique scope.

Anahtar Kavram

IPv6 Subnetting & EUI-64 Address Generation
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