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Zorluk: OrtaIPv4 Addressing and Subnetting

A network engineer is configuring a static IPv4 address for a server residing on a network segment assigned the network ID 172.24.16.0/22172.24.16.0/22. Which IPv4 address represents a valid usable host address that can be assigned to this server?

  1. 172.24.19.254172.24.19.254Cevap
  2. B
    172.24.19.255172.24.19.255
  3. C
    172.24.20.1172.24.20.1
  4. D
    172.32.16.5172.32.16.5

Cevap

172.24.19.254172.24.19.254 is a valid usable host address within the 172.24.16.0/22172.24.16.0/22 subnet.
The IP address 172.24.19.254172.24.19.254 is the last valid usable host IP address in the 172.24.16.0/22172.24.16.0/22 subnet range, which spans from 172.24.16.1172.24.16.1 to 172.24.19.254172.24.19.254.

Adım Adım Çözüm

1
Determine the subnet mask and block size
A prefix of /22/22 corresponds to a subnet mask of 255.255.252.0255.255.252.0. The block size in the third octet is 256252=4256 - 252 = 4.
Calculating the block size identifies how the subnets increment across the third octet.
2
Identify the network boundary and next subnet
The network address is 172.24.16.0172.24.16.0. Adding the block size of 44 to the third octet gives the next subnet network address of 172.24.20.0172.24.20.0.
The next subnet boundary defines the upper limit of the current subnet.
3
Calculate the broadcast address and usable host range
The broadcast address is 172.24.19.255172.24.19.255 (one IP before 172.24.20.0172.24.20.0). The usable host range spans from 172.24.16.1172.24.16.1 through 172.24.19.254172.24.19.254.
Usable host addresses lie strictly between the network ID and the broadcast ID.

Anahtar Kavram

IPv4 Subnet Boundaries and Usable Host Identification
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