A network administrator is verifying IPv6 autoconfiguration on a Cisco router interface. The interface has a burned-in MAC address of `7069.5a12.3456` and is configured with the command `ipv6 address 2001:db8:abc:10::/64 eui-64`. Based on standard EUI-64 interface identifier construction and IPv6 address formats, which TWO statements regarding the resulting IPv6 configuration on this interface are correct?
- The derived 64-bit EUI-64 interface identifier for this interface is `7269:5aff:fe12:3456`.Cevap
- The dynamically generated link-local IPv6 address for this interface begins with the `fe80::/10` prefix combined with the modified interface identifier.Cevap
- CThe EUI-64 calculation inserts the 16-bit hexadecimal sequence `ffff` into the midpoint of the 48-bit MAC address.
- DThe 7th bit (universal/local bit) of the MAC address is left un-inverted, yielding an interface identifier beginning with `7069`.
- EExecuting the command with the `eui-64` keyword automatically creates a link-local address within the unique local address scope (`fc00::/7`).
Cevap
The two correct statements are: (1) The derived 64-bit EUI-64 interface identifier for this interface is `7269:5aff:fe12:3456`, and (2) The dynamically generated link-local IPv6 address for this interface begins with the `fe80::/10` prefix combined with the modified interface identifier.
Generating an IPv6 EUI-64 interface identifier from a 48-bit MAC address requires two transformations: toggling the 7th bit of the first byte (changing 0x70 to 0x72) and inserting FFFE into the midpoint, forming the 64-bit identifier `7269:5aff:fe12:3456`. Additionally, IPv6 automatically configures a link-local address on the interface using the designated prefix `fe80::/10` combined with this EUI-64 identifier.
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IPv6 EUI-64 Interface Identifier Derivation and Link-Local Address Scoping
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