Tüm alıştırma soruları

1987 soru

Soru 201Soru

A company operates several branch offices connected to a main data center where a centralized Wireless LAN Controller (WLC) resides. Following a WAN link outage at one branch, local wireless users at that site can still access local printers and file servers, even though their CAPWAP control connection to the WLC is temporarily down. Which operational mode must be configured on the branch lightweight access points (LAPs) to support local data switching when WLC reachability is lost?

Cevabı ve açıklamayı göster

Cevap: FlexConnect mode

Cevap

FlexConnect mode
FlexConnect mode allows lightweight access points deployed at remote branch sites to locally switch user traffic onto the local VLAN without sending it across the CAPWAP data tunnel to the centralized controller. When the WAN link fails and controller reachability is lost, FlexConnect APs can operate in standalone mode, preserving local client connectivity.

Adım Adım Çözüm

1
Analyze the operational requirements of the branch office deployment
The branch access points must maintain local client traffic forwarding even when the WAN connection to the centralized Wireless LAN Controller fails.
Centralized WLC architectures typically tunnel all client data to the controller via CAPWAP, creating a dependency on WAN availability unless a localized switching mode is enabled.
2
Evaluate Cisco Lightweight Access Point (LAP) operational modes
FlexConnect mode (formerly known as HREAP) is specifically designed for remote branch deployments to allow local traffic switching at the AP level when the CAPWAP control tunnel to the centralized WLC drops.
In Local mode, an AP drops client associations if controller connection fails because all user data MUST pass through the CAPWAP tunnel.

Anahtar Kavram

Lightweight Access Point Operational Modes (FlexConnect vs Local)
Tahmini Süre:1m 15s
Soru 202Soru

A technician connects two legacy switch ports directly to each other using a standard straight-through Ethernet cable. Neither port supports Automatic Medium-Dependent Interface Crossover (Auto-MDIX). Running a status check on the local switch port yields the following CLI output:

text
FastEthernet0/1 is down, line protocol is down
Hardware is FastEthernet, address is 000d.bd2c.4a01 (bia 000d.bd2c.4a01)
MTU 1500 bytes, BW 100000 Kbit/sec, DLY 100 usec,
reliability 255/255, txload 1/255, rxload 1/255
Encapsulation ARPA, loopback not set

Which physical cabling issue is the direct cause of the interface remaining in a down/down state?

Cevabı ve açıklamayı göster

Cevap: A straight-through Ethernet cable was used instead of a crossover Ethernet cable to connect two like switch devices.

Cevap

Using a straight-through Ethernet cable instead of a crossover cable to connect two switch ports (like devices) without Auto-MDIX support prevents physical link establishment, resulting in a down/down interface state.
Switches are MDI-X devices that transmit on pins 3 and 6 and receive on pins 1 and 2. When connecting two switches together directly without Auto-MDIX functionality, a crossover cable must be used to map transmit pins on one switch to receive pins on the other switch. Using a straight-through cable connects transmit pins to transmit pins, resulting in no electrical link and keeping the interface state down/down.

Adım Adım Çözüm

1
Analyze the CLI interface state
The interface status shows 'FastEthernet0/1 is down, line protocol is down', indicating a Layer 1 physical link failure.
When both line status and line protocol are down, the physical layer cannot detect electrical signaling or link integrity.
2
Evaluate device pinout roles and cable types
Switches use MDI-X pinouts (transmitting on pins 3/6 and receiving on pins 1/2). Connecting MDI-X to MDI-X requires a crossover cable to map transmit pins to receive pins.
Without Auto-MDIX to automatically adjust pin roles, a straight-through cable connects transmit pins directly to transmit pins, preventing link detection.

Anahtar Kavram

Ethernet cable pinouts and physical interface troubleshooting (straight-through vs crossover cable selection)
Soru 203Soru

A network architect is designing a high-density Wi-Fi deployment across an enterprise facility with reinforced concrete walls and heavy multipath interference. During site survey planning, the architect must select between using 2.4 GHz channels (11, 66, 1111) and 5 GHz channels (3636, 4040, 4444, 4848) for coverage while maintaining non-overlapping channel designs and minimizing free-space path loss and attenuation. Which statement accurately reflects the physical radio frequency (RF) propagation characteristics and channel planning constraints between these two frequency bands in this scenario?

Cevabı ve açıklamayı göster

Cevap: The 2.4 GHz band experiences lower attenuation through solid obstacles compared to 5 GHz, but offers fewer non-overlapping channels in the US regulatory domain, making high-density channel reuse more susceptible to co-channel interference.

Cevap

The 2.4 GHz band experiences lower attenuation through solid obstacles compared to 5 GHz, but offers fewer non-overlapping channels in the US regulatory domain, making high-density channel reuse more susceptible to co-channel interference.
The 2.4 GHz frequency band operates at longer wavelengths than 5 GHz, resulting in lower attenuation when passing through solid barriers like reinforced concrete walls. However, because the 2.4 GHz ISM band only contains 3 non-overlapping 20 MHz channels (channels 1, 6, and 11 in standard regulatory domains), high-density deployments using 2.4 GHz quickly run out of channels, leading to co-channel interference.

Adım Adım Çözüm

1
Analyze signal propagation and attenuation across frequency bands.
Lower frequencies (2.4 GHz) have longer wavelengths, resulting in lower free-space path loss and greater ability to penetrate physical obstacles such as concrete walls compared to higher frequencies (5 GHz).
RF signal attenuation increases as frequency increases.
2
Evaluate channel availability for co-channel interference mitigation.
2.4 GHz only has 3 non-overlapping 20 MHz channels (1, 6, 11) in North America, whereas 5 GHz provides many more non-overlapping channels.
High-density access point deployments require multiple non-overlapping channels to avoid co-channel interference.
3
Synthesize propagation characteristics and channel planning constraints.
2.4 GHz penetrates solid obstacles better, but its limited count of 3 non-overlapping channels severely restricts high-density channel reuse compared to 5 GHz.
Balancing coverage (attenuation) with capacity (channel availability) is a core wireless architecture decision.

Anahtar Kavram

RF Propagation and Channel Planning Differences Between 2.4 GHz and 5 GHz
Soru 204Soru

An enterprise data center infrastructure deploys virtualized server hosts running Type 1 hypervisors. On a single physical host, multiple Virtual Machines (VMs) belong to different VLANs. Network monitoring reveals that intra-VLAN frame delivery between VMs on the host occurs locally without utilizing physical switch bandwidth, whereas inter-VLAN traffic between VMs on the same host must be forwarded out to an external Layer 3 gateway device. Which component operating within the hypervisor framework is responsible for performing local Layer 2 frame forwarding while enforcing VLAN isolation on the host?

Cevabı ve açıklamayı göster

Cevap: The internal virtual switch (vSwitch) provisioned within the hypervisor software

Cevap

The internal virtual switch (vSwitch) provisioned within the hypervisor software is responsible for switching intra-VLAN frames locally on the physical host while leaving inter-VLAN forwarding to a Layer 3 routing boundary.
The internal virtual switch (vSwitch) operates at Layer 2 within the hypervisor software environment. It inspects Ethernet frame headers and MAC addresses to bridge traffic between virtual machines assigned to the same VLAN on the same physical host. Because it operates at Layer 2, frames destined for a different VLAN must be sent across a trunk link to a Layer 3 device (such as a router or L3 switch) for inter-VLAN routing.

Adım Adım Çözüm

1
Analyze the operational requirements of host-internal VM communication.
Intra-VLAN traffic stays on the local host, while inter-VLAN traffic requires Layer 3 routing.
VLANs define separate broadcast domains at Layer 2. Passing traffic between different VLANs requires a routing decision.
2
Identify the software component inside a Type 1 hypervisor that handles Layer 2 frame forwarding.
The virtual switch (vSwitch) acts as a software-based Layer 2 switch connected to virtual network interface cards (vNICs) of virtual machines.
The vSwitch maintains MAC address tables per VLAN, enabling direct local frame delivery between VMs on the same VLAN without sending frames onto the physical network uplink.
3
Evaluate why inter-VLAN traffic must exit the host.
Standard Layer 2 virtual switches do not perform inter-VLAN routing unless a Layer 3 virtual router or external router interface is configured.
Without an integrated Layer 3 virtual router, inter-VLAN frames must be forwarded over physical uplinks to an external router or Layer 3 switch acting as the default gateway.

Anahtar Kavram

Hypervisor Virtual Switching and Traffic Isolation
Tahmini Süre:1m 30s
Soru 205Soru

A network engineer is configuring a static route on router R1 to reach remote network 2001:db8:c0ff:20::/642001:\text{db8}:\text{c0ff}:20::/64. The engineer intends to forward traffic to the neighboring router using its link-local address fe80::215:c5ff:feab:3102\text{fe80}::215:c5ff:\text{feab}:3102 through R1's local interface GigabitEthernet0/0/1. Which Cisco IOS command successfully accomplishes this configuration?

Cevabı ve açıklamayı göster

Cevap: ipv6 route 2001:db8:c0ff:20::/64 GigabitEthernet0/0/1 fe80::215:c5ff:feab:3102

Cevap

The command specifying 'ipv6 route 2001:db8:c0ff:20::/64 GigabitEthernet0/0/1 fe80::215:c5ff:feab:3102' is the correct configuration.
The correct command follows exact Cisco IOS syntax for a fully specified static route: 'ipv6 route <prefix/mask> <exit-interface> <link-local-address>'. Because link-local IPv6 addresses are only significant on the local link, Cisco IOS requires the exit interface to be explicitly named.

Adım Adım Çözüm

1
Identify the global configuration command syntax for IPv6 static routing.
The correct base command is 'ipv6 route <destination-prefix/prefix-length>'.
IPv6 routing commands use the 'ipv6' prefix rather than 'ip'.
2
Determine the mandatory parameters for link-local next-hop addresses.
A local exit interface must be included alongside the link-local address (fully specified static route).
Link-local addresses (fe80::/10) are link-scoped; without an exit interface, the router cannot determine which link to send packets out on.
3
Assemble the complete Cisco IOS command.
'ipv6 route 2001:db8:c0ff:20::/64 GigabitEthernet0/0/1 fe80::215:c5ff:feab:3102'
This places the destination network, local exit interface, and link-local next-hop in exact positional order.

Anahtar Kavram

Fully specified IPv6 static route requiring local exit interface when using link-local next-hop
Soru 206Soru

A network engineer is configuring interface IP addresses on a core layer switch for an internal corporate segment. Company policy strictly dictates that all internal devices must use RFC 1918 private IPv4 addresses and that addresses must be usable host assignments. Which of the following IP address and subnet mask combinations represents a valid, usable host address located strictly within the upper boundary limit of the RFC 1918 Class B private address space?

Cevabı ve açıklamayı göster

Cevap: 172.31.255.254 255.240.0.0

Cevap

The address 172.31.255.254 with subnet mask 255.240.0.0 is the correct choice as it represents the highest usable host address within the RFC 1918 Class B private range.
The correct answer specifies 172.31.255.254 with mask 255.240.0.0 (/12). RFC 1918 reserves 172.16.0.0 to 172.31.255.255 for Class B private networking. In the 172.16.0.0/12 block, 172.31.255.255 is the broadcast address, making 172.31.255.254 the highest usable host address within the private Class B scope.

Adım Adım Çözüm

1
Identify the exact RFC 1918 Class B private IPv4 address range boundaries.
RFC 1918 defines the Class B private address space as 172.16.0.0/12172.16.0.0/12, which encompasses IP addresses from 172.16.0.0172.16.0.0 through 172.31.255.255172.31.255.255.
Understanding exact RFC 1918 boundaries is required to filter out public IP addresses.
2
Evaluate candidate addresses against the upper boundary (172.31.255.255172.31.255.255).
172.32.0.1172.32.0.1 exceeds the upper limit and is public. 172.15.255.254172.15.255.254 is below the lower limit (172.16.0.0172.16.0.0) and is public. Both 172.31.255.254172.31.255.254 and 172.31.255.255172.31.255.255 fall inside the private range.
Only addresses between 172.16.0.0172.16.0.0 and 172.31.255.255172.31.255.255 comply with the RFC 1918 private addressing requirement.
3
Determine host address usability for the remaining compliant addresses.
For the network block, 172.31.255.255172.31.255.255 acts as a broadcast address and is unusable for host assignment. 172.31.255.254172.31.255.254 is the last valid, assignable host address in the block.
Host IP assignments must exclude the network ID and broadcast address of the given subnet.

Anahtar Kavram

RFC 1918 Private IPv4 Address Space Boundaries and Usable Host Restrictions
Soru 207Soru

A network engineer initializes OSPFv2 process 10 on router R-HQ. The router interfaces are configured as follows:

- Loopback 0: IP address 10.1.1.1/32 (Status: administratively down, Protocol: down)
- Loopback 1: IP address 192.168.50.1/32 (Status: up, Protocol: up)
- GigabitEthernet 0/0: IP address 172.16.100.254/24 (Status: up, Protocol: up)
- GigabitEthernet 0/1: IP address 10.254.254.254/30 (Status: up, Protocol: up)

No manual router ID is configured under `router ospf 10`. When the OSPF process starts, which IP address will be selected as the OSPF Router ID for R-HQ?

Cevabı ve açıklamayı göster

Cevap: 192.168.50.1

Cevap

192.168.50.1 will be selected as the OSPF Router ID.
OSPF Router ID selection follows a strict order of precedence: 1) Manually configured 'router-id' under the OSPF process, 2) Highest IPv4 address on an active (up/up) loopback interface, 3) Highest IPv4 address on an active (up/up) physical interface. Because no manual Router ID is specified and Loopback 0 is down, the router selects 192.168.50.1 (Loopback 1), which is the only operational loopback interface.

Adım Adım Çözüm

1
Check for a manually configured OSPF Router ID
No explicit router-id command is configured.
Explicit configuration is the highest priority in OSPF Router ID selection.
2
Evaluate active (up/up) loopback interfaces
Loopback 0 is down, leaving Loopback 1 (192.168.50.1) as the only active loopback interface.
Active loopback interfaces take precedence over physical interfaces regardless of numerical value.
3
Select the highest IP address among active loopbacks
192.168.50.1 is selected as the OSPF Router ID.
192.168.50.1 is the highest (and only active) loopback interface IP.

Anahtar Kavram

OSPF Router ID Election Logic
Tahmini Süre:1m 15s
Soru 208Soru

An enterprise network administrator deploys four Cisco routers (R1, R2, R3, and R4) connected to a common Layer 2 GigabitEthernet switch on the 192.168.1.0/24192.168.1.0/24 broadcast multiaccess segment. All routers are powered on simultaneously, and OSPFv2 Area 0 is initialized across all connected interfaces. The interface parameters and operational configurations are as follows:

* R1: Configured with `ip ospf priority 255` and `ip ospf network point-to-point`; Router ID is 1.1.1.11.1.1.1.
* R2: Configured with default interface priority (11); Router ID is 10.10.10.1010.10.10.10 (derived from Loopback0).
* R3: Configured with `ip ospf priority 0`; Router ID is 30.30.30.3030.30.30.30 (derived from Loopback0).
* R4: Configured with interface priority set to 100100 (`ip ospf priority 100`); Router ID is 20.20.20.2020.20.20.20 (derived from Loopback0).

Assuming all routers run default OSPF timers and IP settings match, which two outcomes correctly describe the resulting OSPFv2 operational states and DR/BDR election results on this segment? (Choose two.)

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: R4 is elected as the Designated Router (DR) for the broadcast multiaccess segment.; R2 is elected as the Backup Designated Router (BDR) for the broadcast multiaccess segment.

Cevap

The statement identifying R4 as the DR and the statement identifying R2 as the BDR are the correct choices.
In OSPFv2, DR/BDR elections only take place on multiaccess network types (such as broadcast). Because R1's interface is set to point-to-point, it does not participate in DR/BDR elections despite its high priority of 255. Furthermore, R3's priority of 0 explicitly disqualifies it from becoming DR or BDR. Comparing the remaining eligible routers on the broadcast network (R2 with priority 1 and R4 with priority 100), R4 wins the DR election due to its higher priority (100), and R2 wins the BDR election as the remaining eligible candidate.

Adım Adım Çözüm

1
Evaluate eligibility for DR/BDR election based on OSPF network type
R1 is configured with network type point-to-point. Point-to-point networks do not perform DR/BDR elections. Therefore, R1 is completely eliminated from the election regardless of its priority of 255.
DR/BDR selection only occurs on multiaccess network types (Broadcast and Non-Broadcast Multi-Access).
2
Evaluate eligibility for DR/BDR election based on interface priority values
R3 has an interface priority of 0 (`ip ospf priority 0`), which renders it ineligible to become either DR or BDR. Thus, R3 is eliminated from election consideration.
An OSPF interface priority of 0 explicitly configured on an interface prevents the router from participating in DR/BDR elections.
3
Determine DR and BDR election winners among remaining eligible candidates
The remaining eligible candidates on the broadcast segment are R4 (priority 100) and R2 (priority 1). R4 has the highest priority and is elected DR. R2 has the next highest priority among eligible routers and is elected BDR.
OSPF DR election prioritizes highest interface priority first, followed by highest Router ID as a tie-breaker.

Anahtar Kavram

OSPFv2 DR/BDR Election Mechanics and Interface Network Type Rules
Tahmini Süre:3m 0s
Soru 209Soru

A network engineer is assigned the IPv4 subnetwork block 192.168.100.0/23192.168.100.0/23 for a high-density enterprise server rack. What is the maximum number of usable host IPv4 addresses that can be assigned to active network interfaces within this subnet?

Cevabı ve açıklamayı göster

Cevap: 510

Cevap

510 usable host addresses
A /23/23 prefix leaves 3223=932 - 23 = 9 bits for host addresses. Total addresses equal 29=5122^9 = 512. Subtracting 2 for the network address (192.168.100.0192.168.100.0) and broadcast address (192.168.101.255192.168.101.255) leaves exactly 510 usable host IP addresses.

Adım Adım Çözüm

1
Calculate the number of host bits from the prefix length.
Host bits = 3223=932 - 23 = 9 bits
An IPv4 address consists of 32 bits. Subtracting the prefix length yields the remaining host portion bits.
2
Calculate the total number of IPv4 addresses in the subnetwork block.
29=5122^9 = 512 total addresses
The formula 2n2^n gives the complete block size in total IP addresses.
3
Subtract reserved subnetwork and broadcast addresses to determine usable host capacity.
5122=510512 - 2 = 510 usable hosts
The lowest address in the subnet acts as the subnet ID, and the highest address acts as the directed broadcast address; neither can be assigned to host interfaces.

Anahtar Kavram

IPv4 Usable Host Calculation
Soru 210Soru

A network administrator is reviewing telemetry and alerting mechanisms across enterprise Cisco routers. Which TWO statements accurately describe the operational differences between SNMP traps and SNMP informs? (Select TWO.)

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: SNMP traps are unacknowledged notification messages sent asynchronously by managed devices to an SNMP management station over UDP port 162.; SNMP informs require the receiving SNMP manager to acknowledge receipt of the notification, providing reliable delivery confirmation to the sending device.

Cevap

SNMP traps are unacknowledged notifications sent over UDP port 162, while SNMP informs require an explicit acknowledgement from the receiving SNMP management station to confirm delivery.
SNMP traps are unacknowledged notifications sent to UDP port 162 on the management station. In contrast, SNMP informs provide reliable delivery by requiring the manager to respond with an acknowledgement PDU.

Adım Adım Çözüm

1
Identify the transport port and delivery mechanism for SNMP traps.
SNMP traps are unacknowledged UDP messages directed to UDP port 162 on the NMS.
Traps provide best-effort, fire-and-forget event reporting.
2
Identify the acknowledgment behavior of SNMP informs.
SNMP informs require an explicit application-layer response from the receiving NMS.
If no acknowledgement is received, the agent holds the inform in memory and retransmits it until confirmed or timed out.

Anahtar Kavram

SNMP Trap vs Inform Operations and UDP Port Assignments
Soru 211Soru

A network administrator is deploying a centralized Wireless LAN Controller (WLC) within an enterprise campus network. Which two operational functions are primary responsibilities of the WLC? (Select two.)

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: Automating radio frequency (RF) management and dynamic channel assignment across Lightweight Access Points; Providing centralized configuration management and security policy enforcement for managed Access Points

Cevap

The primary operational responsibilities of a Wireless LAN Controller (WLC) include automating radio frequency (RF) management across Lightweight Access Points and providing centralized configuration management and security policy enforcement.
Wireless LAN Controllers (WLCs) serve as the central intelligence in a split-MAC architecture. They handle control-plane functions including dynamic radio frequency (RF) management, channel assignment, transmit power control, centralized authentication, firmware updates, and security policy distribution to lightweight access points.

Adım Adım Çözüm

1
Identify the primary role of a Wireless LAN Controller (WLC) in a split-MAC architecture.
The WLC offloads control plane functions—such as provisioning, security policies, RF management, and firmware management—from lightweight access points (LAPs).
Centralizing AP management simplifies enterprise wireless deployments and ensures consistent security and performance enforcement.
2
Evaluate the candidate options to select the two valid WLC functions.
Dynamic RF management/channel assignment and centralized configuration/policy management are correct. Hypervisor virtualization functions and CDP/LLDP TLV neighbor discovery reflect unrelated hardware and protocol roles.
Only RF management and centralized configuration/policy enforcement align with WLC responsibilities.

Anahtar Kavram

Wireless LAN Controller (WLC) Roles and Operational Functions
Soru 212Soru

A network engineer is configuring a backup path on router HQ-R1 to reach the corporate subnet 172.20.40.0/22172.20.40.0/22. The primary route to this prefix is currently learned via Internal EIGRP with a default administrative distance of 90. The backup connection uses a point-to-point Ethernet link where HQ-R1 local interface GigabitEthernet0/1 is assigned IP address 198.51.100.1/30198.51.100.1/30 and the remote peer router interface is assigned 198.51.100.254/30198.51.100.254/30.

Which Cisco IOS command must be configured on HQ-R1 to ensure the static route acts as a floating backup route that only enters the routing table if the primary EIGRP route fails?

Cevabı ve açıklamayı göster

Cevap: ip route 172.20.40.0 255.255.252.0 198.51.100.254 95

Cevap

The correct command is `ip route 172.20.40.0 255.255.252.0 198.51.100.254 95`, which specifies the destination network, valid subnet mask, remote next-hop IP, and an administrative distance higher than Internal EIGRP (90).
The correct command properly formats the /22 mask as 255.255.252.0, uses the remote neighbor's interface IP (198.51.100.254) as the next hop, and sets an administrative distance of 95. Because 95 is higher than Internal EIGRP's administrative distance of 90, the router keeps this route out of the active routing table until the EIGRP route fails.

Adım Adım Çözüm

1
Convert the CIDR prefix length /22 to dotted-decimal subnet mask format.
A /22 prefix corresponds to 22 binary ones (11111111.11111111.11111100.00000000), which evaluates to 255.255.252.0.
Cisco IOS static routing syntax requires a valid IPv4 subnet mask following the destination network prefix.
2
Identify the correct next-hop IP address for static route forwarding.
The next-hop IP address must be the neighbor router's IP address on the point-to-point link, which is 198.51.100.254.
Configuring a local interface IP address as a next hop is invalid because a router cannot forward packets to its own local interface.
3
Determine the required Administrative Distance (AD) for a floating static route.
Select an administrative distance value strictly greater than 90 (e.g., 95).
Internal EIGRP has a default AD of 90. To act as a floating backup, the static route's AD must be higher than the active primary routing protocol so that it remains untrusted until the primary route drops from the routing table.

Anahtar Kavram

Floating Static Route Administrative Distance Configuration
Tahmini Süre:1m 30s
Soru 213Soru

A network engineer is troubleshooting internet connectivity issues on a Cisco IOS router configured for Network Address Translation. Internal hosts on the 10.10.10.0/2410.10.10.0/24 network report that only one host can access external resources at any given time. Subsequent host traffic is dropped. The engineer inspects the router configuration and operational state using verification commands:

text
Router# show ip nat statistics
Total active translations: 1 (0 static, 1 dynamic, 1 extended)
Outside interfaces:
GigabitEthernet0/1
Inside interfaces:
GigabitEthernet0/0
Hits: 48 Misses: 12
CEF Translated packets: 48, Fast Switched packets: 0
Expired translations: 15
Dynamic mappings:
-- Inside Source
[id 1] access-list 101 pool INTERNET-POOL refcount 1
pool INTERNET-POOL: netmask 255.255.255.252
start 203.0.113.1 end 203.0.113.1
type generic, total addresses 1, allocated 1 (100%), misses 12

Router# show running-config | include ip nat
ip nat pool INTERNET-POOL 203.0.113.1 203.0.113.1 netmask 255.255.255.252
ip nat inside source list 101 pool INTERNET-POOL
access-list 101 permit ip 10.10.10.0 0.0.0.255 any

Which configuration change is required to allow all internal hosts on the 10.10.10.0/2410.10.10.0/24 network to share the single public IPv4 address simultaneously?

Cevabı ve açıklamayı göster

Cevap: Append the overload keyword to the command ip nat inside source list 101 pool INTERNET-POOL.

Cevap

Appending the overload keyword to the statement ip nat inside source list 101 pool INTERNET-POOL converts dynamic 1-to-1 NAT into Port Address Translation (PAT), enabling multiple internal hosts to share a single public IP address using unique source port numbers.
The command output indicates that the NAT pool contains only one IP address (203.0.113.1) and is 100% allocated without overload enabled. Because the overload keyword was omitted from the inside source translation statement, Cisco IOS performs dynamic 1-to-1 translation. Appending the overload keyword enables Port Address Translation (PAT), allowing multiple inside hosts to share the single IP address by using unique Layer 4 port numbers.

Adım Adım Çözüm

1
Analyze the output of show ip nat statistics and show running-config.
The pool INTERNET-POOL contains 1 total public IPv4 address (203.0.113.1). Allocation shows 1 allocated (100%) with 12 misses, indicating address pool exhaustion.
Without port multiplexing, dynamic NAT performs strict 1-to-1 mapping. Once all pool addresses are allocated, subsequent translation requests fail.
2
Identify the missing keyword in the NAT translation command.
The configuration entry ip nat inside source list 101 pool INTERNET-POOL lacks the overload keyword.
The overload keyword instructs Cisco IOS to track Layer 4 source port numbers (PAT), enabling thousands of concurrent internal connections over a single IP address.
3
Formulate the correct configuration fix.
Reconfigure the router statement to ip nat inside source list 101 pool INTERNET-POOL overload.
This modification resolves translation misses and allows all hosts on the 10.10.10.0/24 network to share 203.0.113.1 simultaneously.

Anahtar Kavram

Port Address Translation (PAT) Overload Configuration
Soru 214Soru

A network engineer is configuring static IPv4 addresses for new host interfaces within a server cluster assigned the subnetwork block 172.24.16.0/21172.24.16.0/21. Which TWO of the following IPv4 addresses are valid, usable host addresses within this subnetwork?

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: 172.24.22.255172.24.22.255; 172.24.16.1172.24.16.1

Cevap

The valid usable host addresses for the 172.24.16.0/21172.24.16.0/21 subnetwork are 172.24.22.255172.24.22.255 and 172.24.16.1172.24.16.1.
For a /21 prefix (255.255.248.0255.255.248.0), the third octet increments by 8. The network block starting at 172.24.16.0172.24.16.0 covers 172.24.16.0172.24.16.0 to 172.24.23.255172.24.23.255. The network address is 172.24.16.0172.24.16.0 and the broadcast address is 172.24.23.255172.24.23.255. Therefore, the range of usable host addresses is 172.24.16.1172.24.16.1 through 172.24.23.254172.24.23.254. Both 172.24.16.1172.24.16.1 and 172.24.22.255172.24.22.255 fall within this valid usable host range.

Adım Adım Çözüm

1
Determine the subnet mask and block size for CIDR prefix /21.
A /21 prefix corresponds to the dotted-decimal subnet mask 255.255.248.0255.255.248.0. The block size in the third octet is 256248=8256 - 248 = 8.
Calculating block size establishes the boundary interval for networks incrementing in the third octet.
2
Calculate the network address, broadcast address, and usable host range.
Network ID: 172.24.16.0172.24.16.0; Broadcast address: 172.24.23.255172.24.23.255; Usable host range: 172.24.16.1172.24.16.1 through 172.24.23.254172.24.23.254.
The third octet spans from 1616 up to 16+81=2316 + 8 - 1 = 23.
3
Evaluate candidate addresses against the usable host range.
172.24.16.1172.24.16.1 is the first usable host address. 172.24.22.255172.24.22.255 falls strictly between 172.24.16.1172.24.16.1 and 172.24.23.254172.24.23.254. 172.24.23.255172.24.23.255 is the reserved broadcast address. 172.32.20.5172.32.20.5 is outside the network and not in the private RFC 1918 Class B space.
Identify which candidates lie within the inclusive host boundary without matching the network or broadcast ID.

Anahtar Kavram

Subnet Boundary and Usable Host Range Calculation for Supernets/Subnets wider than /24
Soru 215Soru

A network administrator configures four routers (R1, R2, R3, and R4) on a single multiaccess Ethernet segment running OSPFv2. The OSPF interface parameters are configured as follows:

- R1: OSPF Priority = 100, Router ID = 1.1.1.1
- R2: OSPF Priority = 0, Router ID = 4.4.4.4
- R3: OSPF Priority = 100, Router ID = 3.3.3.3
- R4: OSPF Priority = 50, Router ID = 2.2.2.2

All four routers boot simultaneously and form neighbor relationships. Which role will router R2 assume on this network segment?

Cevabı ve açıklamayı göster

Cevap: DROTHER, because an interface priority of 0 explicitly excludes the router from becoming a DR or BDR.

Cevap

Router R2 will assume the role of DROTHER because an interface priority of 0 prevents it from participating in the DR/BDR election.
On an OSPF broadcast network, routers elect a DR and BDR based on the highest interface priority. If there is a tie in priority, the highest Router ID breaks the tie. However, any interface configured with an OSPF priority of 0 is strictly excluded from participating in the election and will immediately assume the role of DROTHER, regardless of how high its Router ID is.

Adım Adım Çözüm

1
Evaluate the OSPF interface priority settings for all routers on the broadcast network segment.
R1 has priority 100, R3 has priority 100, R4 has priority 50, and R2 has priority 0.
OSPF DR/BDR elections first compare interface priority values (range 0 to 255, default 1).
2
Identify the impact of an interface priority setting of 0.
Router R2 with priority 0 is disqualified from DR and BDR election.
An OSPF interface priority of 0 explicitly instructs the OSPF process that the router must never become a DR or BDR.
3
Determine the elected roles for all participating routers.
R3 becomes DR (priority 100, highest Router ID 3.3.3.3 among eligible routers), R1 becomes BDR (priority 100, Router ID 1.1.1.1), and R2 becomes DROTHER.
Only routers with a priority greater than 0 participate in DR/BDR selection.

Anahtar Kavram

OSPFv2 DR/BDR Election Exclusion via Priority 0
Soru 216Soru

Match each network topology architectural layer to its primary functional responsibility within an enterprise campus or data center network.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Campus Core Layer
Campus Access Layer
Data Center Spine Layer
Data Center Leaf Layer

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Campus Core Layer matches high-speed non-blocking backbone transport. Campus Access Layer matches direct end-user endpoint connectivity and edge policy enforcement. Data Center Spine Layer matches interconnecting all leaf switches via ECMP routing without host connections. Data Center Leaf Layer matches directly connecting servers and storage while linking to every spine switch.
Each functional layer serves a distinct architectural purpose: the Campus Core provides rapid backbone transit; the Campus Access layer connects user devices and enforces edge policies; the Data Center Spine interconnects leaf switches via ECMP without host attachments; and the Data Center Leaf connects endpoints while maintaining links to every spine.

Adım Adım Çözüm

1
Identify the role of the Campus Core Layer in a 3-Tier model.
Match with high-speed packet transport without CPU-intensive filtering.
The core layer must maintain maximum packet throughput across the campus core network.
2
Identify the role of the Campus Access Layer.
Match with direct connectivity and security enforcement for user endpoints.
Access switches form the network edge where workstations and IP phones plug into the network.
3
Differentiate between Spine and Leaf layers in a Clos data center topology.
Spine switches interconnect leaf switches via ECMP, while Leaf switches connect hosts and link to all spines.
Spine switches form the core interconnect fabric without host attachment, whereas leaf switches act as access nodes for servers.

Anahtar Kavram

Campus 3-Tier and Data Center Spine-Leaf Layer Responsibilities
Soru 217Soru

A network engineer is configuring interface GigabitEthernet1/0/10 on a Cisco Catalyst switch to connect a single end-user workstation. VLAN 75 ('FINANCE') has not yet been created in global configuration mode. The engineer enters the following CLI commands:

Switch(config)# interface gigabitethernet1/0/10
Switch(config-if)# switchport mode access
Switch(config-if)# switchport access vlan 75

Which two statements accurately describe the resulting switch behavior and interface operation? (Select two.)

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: The switch automatically creates VLAN 75 in the VLAN database and assigns interface GigabitEthernet1/0/10 to VLAN 75.; Frames transmitted out interface GigabitEthernet1/0/10 toward the connected workstation will be untagged standard Ethernet frames.

Cevap

The switch automatically creates VLAN 75 in the VLAN database and assigns the interface to it, and frames transmitted out interface GigabitEthernet1/0/10 toward the workstation are untagged standard Ethernet frames.
Assigning an interface to a VLAN that does not yet exist using 'switchport access vlan' prompts Cisco IOS to automatically create the VLAN in the switch database. Additionally, ports configured with 'switchport mode access' operate exclusively as untagged ports for that single VLAN when transmitting traffic to attached end-user devices.

Adım Adım Çözüm

1
Analyze the Cisco IOS dynamic behavior when assigning an interface to a missing VLAN.
Cisco IOS automatically instantiates VLAN 75 in the switch VLAN database.
Automatic creation of missing VLANs is standard Cisco IOS software behavior during access port VLAN assignment.
2
Analyze frame encapsulation on a statically assigned access port.
The port strips any internal VLAN tags before transmitting frames out to the workstation.
Access ports belong to only one VLAN and send standard untagged 802.3 frames to host endpoints.

Anahtar Kavram

Cisco IOS Dynamic VLAN Creation and Access Port Framing Mechanics
Soru 218Soru

A network engineer is configuring OSPFv2 between two directly connected Cisco routers over a GigabitEthernet link. Upon inspecting the neighbor status, the engineer notes that the routers fail to form a neighbor relationship. Which TWO configuration mismatches between the interconnected interfaces will prevent these routers from establishing an OSPFv2 neighbor adjacency?

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: Mismatched OSPF Hello and Dead timer interval settings; Mismatched OSPF Area ID assignments on the interconnecting interfaces

Cevap

The two conditions preventing OSPFv2 neighbor adjacency formation are mismatched Hello/Dead timer intervals and mismatched OSPF Area IDs on the connected interfaces.
For OSPFv2 routers to establish a neighbor adjacency, specific fields exchanged inside the OSPF Hello packet must match. These include matching OSPF Area IDs and identical Hello and Dead timer intervals. If either of these parameters differs between the connected interfaces, Hello packets are dropped and the routers remain in a Down state.

Adım Adım Çözüm

1
Analyze OSPF Hello packet parameter matching requirements for neighbor adjacency.
Identify parameters exchanged in Hello packets that must strictly match: Area ID, Subnet Mask, Hello/Dead Timers, Authentication, and Stub Area Flag.
OSPF Hello packets validate neighbor compatibility before establishing an adjacency.
2
Evaluate local vs network-wide OSPF configuration parameters.
Confirm that Process IDs and interface metric costs are locally significant or used for path metric calculations rather than adjacency gating.
Process IDs distinguish local routing process instances, while interface costs affect metric accumulation downstream.

Anahtar Kavram

OSPFv2 Hello Packet Parameter Verification for Neighbor Adjacencies
Soru 219Soru

Place the criteria evaluated during an OSPFv2 Designated Router (DR) election in order of precedence, starting with the highest priority evaluation criteria first.

Öğeleri doğru sıraya koymak için sürükleyin

Cevabı ve açıklamayı göster

Cevap

The correct order of precedence for OSPFv2 DR/BDR election tie-breaking is: 1. Highest interface OSPF priority value (non-zero), 2. Highest manually configured OSPF Router ID, 3. Highest IP address among active loopback interfaces, 4. Highest IP address among active physical interfaces.
In OSPFv2 DR/BDR elections on broadcast or non-broadcast multiaccess networks, the selection process follows a strict precedence: interface priority is checked first (highest wins, while priority 0 is ineligible). If priorities tie, the OSPF Router ID determines the winner. The Router ID selection itself follows a deterministic hierarchy: explicit manual configuration via 'router-id' first, followed by the highest active loopback IP address, and finally the highest active physical interface IP address.

Adım Adım Çözüm

1
Evaluate OSPF Interface Priority
Highest priority (1-255) wins. A priority of 0 excludes the router from becoming DR/BDR.
OSPF prioritizes administrator design intent via interface priority over IP address tie-breakers.
2
Evaluate Explicit Router ID
If priority values are equal, the router with the highest manually configured router-id value is selected.
Manual Router ID configuration overrides dynamically determined interface IP addresses.
3
Evaluate Active Loopback Interfaces
If no manual router ID exists, the highest IP address configured on an active loopback interface is chosen.
Loopback interfaces are logically stable and preferred over physical interfaces for RID determination.
4
Evaluate Active Physical Interfaces
If no loopback interfaces exist, the highest IP address configured on an active physical interface is used as the final tie-breaker.
Physical interface IPs serve as the final fallback for Router ID determination in OSPFv2.

Anahtar Kavram

OSPFv2 DR/BDR Election Precedence and Router ID Selection Criteria
Soru 220Soru

An enterprise network administrator is updating the SNMP monitoring configuration on a Cisco IOS XE core router to meet strict security and monitoring compliance standards. The updated policy mandates two specific requirements for outbound system event notifications sent to the central Network Management System (NMS):
1. All notifications must be encrypted using AES privacy and cryptographically authenticated using SHA.
2. Outbound notifications must require explicit application-layer acknowledgments from the NMS, causing the router to resend notification packets if no acknowledgment is received.

Which combination of SNMP protocol settings and message types must be configured on the router to fulfill both requirements?

Cevabı ve açıklamayı göster

Cevap: SNMPv3 operating at the authPriv security level utilizing SNMP Informs

Cevap

The router must be configured for SNMPv3 operating at the authPriv security level using SNMP Informs.
SNMPv3 with the authPriv security level supports both authentication (SHA/MD5) and encryption/privacy (AES/DES). SNMP Informs provide reliable notification delivery because the managed device holds the notification in memory and retries transmission until an explicit acknowledgment PDU is received from the NMS.

Adım Adım Çözüm

1
Evaluate the security requirement (authentication and encryption).
Identify that SNMPv3 defines three security models: noAuthNoPriv (no security), authNoPriv (authentication without encryption), and authPriv (authentication with encryption).
To satisfy the mandate for SHA authentication combined with AES encryption, the authPriv security level must be selected.
2
Evaluate the notification delivery requirement (acknowledgments and retries).
Differentiate between SNMP Traps and SNMP Informs.
SNMP Traps are unacknowledged notifications (fire-and-forget). SNMP Informs require the receiving NMS to return an acknowledgment PDU; if the agent does not receive an ACK within the timeout period, it retransmits the Inform.
3
Synthesize the security and operational mechanics requirements.
Selecting SNMPv3 authPriv with SNMP Informs satisfies both cryptographic security and reliable delivery criteria.
Combining authPriv (for SHA/AES) and Informs (for acknowledged delivery) satisfies all security policy constraints.

Anahtar Kavram

SNMPv3 Security Levels (authPriv) and Notification Reliability Mechanics (Informs vs Traps)
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