Under federal cargo securement regulations (FMCSA § 393.110), an 8-foot-long piece of machinery weighing 4,000 pounds requires at least two tiedowns if it is not blocked against forward movement, but requires only one tiedown if it is properly blocked against forward movement, provided aggregate Working Load Limit (WLL) requirements are satisfied.
Cevap: Cevap
Cevap
True
The statement is correct because FMCSA 49 CFR § 393.110 explicitly establishes two distinct tiedown schedules: unblocked items between 5 and 10 feet require two tiedowns, whereas items blocked against forward movement by approved blocking or bulkheads require only one tiedown per 10 feet of length (or fraction thereof). An 8-foot item qualifies for the single tiedown rule when properly blocked, provided the tiedown meets the 50% aggregate Working Load Limit.
Adım Adım Çözüm
Anahtar Kavram
FMCSA Tiedown Count Reduction Rules for Forward-Blocked Cargo
Tahmini Süre:1m 30s