Soru

Zorluk: OrtaIPv6 Addressing and Deployment

A network engineer is deploying IPv6 across an enterprise LAN using Stateless Address Autoconfiguration (SLAAC). A client workstation on the subnet has the physical MAC address 00:14:22:01:23:4500:14:22:01:23:45. Which of the following represents the correct 64-bit interface identifier generated for this host using the modified EUI-64 format?

  1. 0214:22ff:fe01:2345Cevap
  2. B
    0014:22ff:fe01:2345
  3. C
    0214:22ff:ff01:2345
  4. D
    0114:22ff:fe01:2345

Cevap

0214:22ff:fe01:2345
The interface identifier '0214:22ff:fe01:2345' correctly follows the modified EUI-64 conversion procedure. The MAC address 00:14:22:01:23:45 is divided into two 24-bit halves (00:14:22 and 01:23:45), the 16-bit hex string FFFE is inserted in the middle, and the 7th bit (Universal/Local bit) of the first byte is inverted from 0 to 1 (changing 0x00 to 0x02).

Adım Adım Çözüm

1
Split the 48-bit MAC address into two 24-bit halves.
The left half is 00:14:2200:14:22 and the right half is 01:23:4501:23:45.
Modified EUI-64 formatting requires inserting a 16-bit delimiter into the middle of the MAC address.
2
Insert the hex value FFFEFFFE between the two halves.
The combined 64-bit value becomes 0014:22FF:FE01:23450014:22FF:FE01:2345.
IEEE EUI-64 specifications define FFFEFFFE as the expansion sequence to turn a 48-bit MAC address into a 64-bit identifier.
3
Invert the Universal/Local (U/L) bit, which is the 7th bit of the first byte.
The first byte 001600_{16} (00000000200000000_2) with its 7th bit inverted becomes 021602_{16} (00000010200000010_2), giving 0214:22ff:fe01:23450214:22ff:fe01:2345.
Inverting the U/L bit designates that the generated EUI-64 IPv6 interface identifier is derived from a globally unique IEEE MAC address.

Anahtar Kavram

Modified EUI-64 Interface Identifier Generation
Tahmini Süre:1m 30s
Bu soruyu puanla