Examkin

Soru

Zorluk: OrtaIPv4 Addressing and Subnetting

A network engineer is configuring an interface on a core router with the IP address 10.88.140.165/2610.88.140.165/26. What is the broadcast address for this IPv4 subnet?

  1. 10.88.140.191Cevap
  2. B
    10.88.140.190
  3. C
    10.88.140.192
  4. D
    10.88.140.255

Cevap

The broadcast address for the IPv4 subnet is 10.88.140.191.
With a /26 prefix length (subnet mask 255.255.255.192), subnets increment in blocks of 64 addresses. The IP 10.88.140.165 resides within the network range 10.88.140.128 through 10.88.140.191. The last address in this range, 10.88.140.191, is the broadcast address.

Adım Adım Çözüm

1
Determine the subnet block size from the CIDR prefix.
A /26 mask equals 255.255.255.192. Subtracting 192 from 256 gives a block size of 64 IP addresses per subnet.
Calculating block size establishes the increment step between subnets.
2
Locate the network ID for IP address 10.88.140.165.
Subnet boundaries in the 4th octet increase by multiples of 64: 0, 64, 128, 192. The address .165 falls into the 10.88.140.128 subnet.
The network ID identifies the beginning of the subnet block.
3
Calculate the broadcast address.
The broadcast address is one less than the next network boundary: 128 + 64 - 1 = 191, yielding 10.88.140.191.
The broadcast address is always the final IP address in a subnet block.

Anahtar Kavram

IPv4 Subnet Boundaries and Broadcast Address Calculation
Tahmini Süre:1m 0s
Bu soruyu puanla

Konular

IPv4 Addressing and Subnetting

Bu konudan daha fazla soru