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Zorluk: KolaySpanning Tree Protocol Operations

In a local network where multiple switches are deployed with default Spanning Tree Protocol (STP) configuration settings, all switches possess the same bridge priority of 32768. How does STP break this tie to select the root bridge?

  1. The switch with the lowest numerical MAC address is elected as the root bridge.Cevap
  2. B
    The switch with the highest numerical MAC address is elected as the root bridge.
  3. C
    The switch with the highest numerical priority value overrides the tie and becomes the root bridge.
  4. D
    The switch that experiences the highest untagged traffic volume on its native VLAN is selected.

Cevap

The switch with the lowest numerical MAC address is elected as the root bridge.
In 802.1D Spanning Tree Protocol, the switch with the lowest Bridge ID (BID) becomes the root bridge. The BID consists of a 2-byte Priority field followed by a 6-byte MAC address. When all switches use the default bridge priority (32768), the priority comparison results in a tie. STP resolves this tie by selecting the switch with the lowest numerical MAC address.

Adım Adım Çözüm

1
Analyze the Bridge ID structure used for root election.
The Bridge ID consists of a priority value concatenated with the switch's MAC address.
STP elects the bridge with the lowest overall Bridge ID as the root bridge.
2
Compare priority values across the switches.
All switches have an identical default priority of 32768.
Since the priority values are equal, priority alone cannot determine a winner.
3
Evaluate the secondary tiebreaker.
The switch with the lowest numerical MAC address wins the tiebreaker.
STP election rules designate the lowest MAC address as the decisive factor when priorities match.

Anahtar Kavram

Spanning Tree Protocol Root Bridge Election Tiebreaker
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Konular

Spanning Tree Protocol Operations

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