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Zorluk: Çok zorIPv4 Addressing and Subnetting

A network architect is assigned the parent block 10.200.16.0/2010.200.16.0/20 to provision subnets for a new regional facility. Using Variable Length Subnet Masking (VLSM), the subnets must be allocated contiguously starting from the lowest available IP address in the block, ordered from the largest host requirement to the smallest. The site requirements are as follows:

- Data Center: minimum 900900 usable host IPs
- Office Floor A: minimum 400400 usable host IPs
- Office Floor B: minimum 100100 usable host IPs

After successfully allocating these three subnets, what is the broadcast address of the subnet allocated to Office Floor B?

  1. 10.200.22.12710.200.22.127Cevap
  2. B
    10.200.22.12610.200.22.126
  3. C
    10.200.22.25510.200.22.255
  4. D
    10.200.21.25510.200.21.255

Cevap

The broadcast address of the subnet allocated to Office Floor B is 10.200.22.12710.200.22.127.
Allocating subnets sequentially using VLSM requires allocating block sizes based on power-of-two host requirements. 900 hosts need a /22 (1024 IPs: 10.200.16.0–10.200.19.255). 400 hosts need a /23 (512 IPs: 10.200.20.0–10.200.21.255). 100 hosts need a /25 (128 IPs: 10.200.22.0–10.200.22.127). The broadcast address for Office Floor B's /25 subnet is 10.200.22.127.

Adım Adım Çözüm

1
Calculate the required prefix length and range for the Data Center (900 usable hosts).
Requires 1010 host bits (210−2=10222^{10} - 2 = 1022 usable hosts), which corresponds to a /22/22 mask (10241024 total addresses). The subnet range is 10.200.16.0/2210.200.16.0/22, spanning 10.200.16.010.200.16.0 to 10.200.19.25510.200.19.255.
VLSM requires placing the largest subnet first at the start of the block.
2
Calculate the required prefix length and range for Office Floor A (400 usable hosts).
Requires 99 host bits (29−2=5102^9 - 2 = 510 usable hosts), which corresponds to a /23/23 mask (512512 total addresses). Starting at the next available IP (10.200.20.010.200.20.0), the subnet range is 10.200.20.0/2310.200.20.0/23, spanning 10.200.20.010.200.20.0 to 10.200.21.25510.200.21.255.
The subnet must begin immediately after the preceding /22/22 block boundary.
3
Calculate the required prefix length and range for Office Floor B (100 usable hosts).
Requires 77 host bits (27−2=1262^7 - 2 = 126 usable hosts), which corresponds to a /25/25 mask (128128 total addresses). Starting at 10.200.22.010.200.22.0, the subnet range is 10.200.22.0/2510.200.22.0/25, spanning 10.200.22.010.200.22.0 to 10.200.22.12710.200.22.127.
A /25/25 subnet provides 128 total addresses, with the first address (10.200.22.010.200.22.0) as Network ID and the last address (10.200.22.12710.200.22.127) as Broadcast.

Anahtar Kavram

Variable Length Subnet Masking (VLSM) Host Capacity Allocation
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Konular

IPv4 Addressing and Subnetting

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