A network administrator is allocating an IPv4 subnet for a new IP telephony pool that requ… — CompTIA Network+

A network administrator is allocating an IPv4 subnet for a new IP telephony pool that requires host IP addresses for $58$ VoIP phones and $2$ dedicated administrative consoles. What is the maximum number of usable host IP addresses available in the smallest standard subnet prefix that satisfies this requirement?

$62$ Cevap
B
$64$
C
$126$
D
$30$

Cevap

62

usable host IP addresses

The scenario requires addressing for 60 total host devices (

58 + 2 = 60

). The smallest standard IPv4 subnet block that can accommodate this requirement is a

/26

network prefix, which allocates

6

host bits (

32 - 26 = 6

). A 6-bit host portion provides

2^6 = 64

total IP addresses. Subtracting

2

reserved addresses for the network ID and broadcast address gives

64 - 2 = 62

usable host IP addresses.

Adım Adım Çözüm

Calculate the total number of host IP addresses required.

58 \text{ (phones)} + 2 \text{ (consoles)} = 60 \text{ total host IP addresses required}

Both phones and administrative consoles require valid, assignable IPv4 addresses.

Determine the smallest power of 2 that accommodates at least the required usable host count.

The smallest power of

2

greater than or equal to

60 + 2 = 62

2^6 = 64

. This corresponds to a

/26

prefix length.

Subnet blocks are allocated in powers of 2 (

2^n

), where

n

is the number of host bits.

Calculate usable host IP addresses by applying the formula

2^n - 2

2^6 - 2 = 64 - 2 = 62 \text{ usable host IP addresses}

The first address in the block is reserved as the Network ID, and the final address is reserved as the Network Broadcast address.

Anahtar Kavram

Usable IPv4 Host Address Calculation

Tahmini Süre:1m 30s

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