A network engineer is provisioning subnets within a corporate network allocation of 172.16… — CompTIA Network+

A network engineer is provisioning subnets within a corporate network allocation of $172.16.96.0/21$ . The engineer must create subnets that each accommodate at least $200$ usable host IP addresses while minimizing wasted address space. If these subnets are assigned sequentially starting from the beginning of the block, what is the broadcast address of the second subnet?

$172.16.97.255$ Cevap
B
$172.16.96.255$
C
$172.16.97.254$
D
$172.16.99.255$

Cevap

The broadcast address of the second subnet is 172.16.97.255.

To host at least

200

usable devices,

8

host bits (

2^8 - 2 = 254

usable IPs) are required, resulting in a

/24

prefix (subnet mask

255.255.255.0

). Starting from

172.16.96.0

, the first

/24

subnet spans

172.16.96.0

172.16.96.255

. The second

/24

subnet spans

172.16.97.0

172.16.97.255

. The broadcast address of this second subnet is

172.16.97.255

Adım Adım Çözüm

Determine the required host bits and subnet mask prefix.

Using the formula

2^n - 2 \ge 200

n = 8

bits are needed for host addressing (

2^8 - 2 = 254

usable hosts). The prefix length is

32 - 8 = /24

Choosing 8 host bits minimizes address waste while meeting the requirement of at least 200 usable host IPs.

Identify the block boundaries of the subnets.

/24

subnet increments by

1

in the third octet. The first subnet is

172.16.96.0/24

(

172.16.96.0

172.16.96.255

). The second sequential subnet is

172.16.97.0/24

(

172.16.97.0

172.16.97.255

Subnetting starts sequentially at the beginning of the

172.16.96.0/21

parent block.

Determine the broadcast address of the second subnet.

The highest address in the

172.16.97.0/24

range is

172.16.97.255

The broadcast address is the last IP address in the subnet block.

Anahtar Kavram

Subnet sizing with CIDR and sequential block allocation

Soru

Cevap

Adım Adım Çözüm

Anahtar Kavram

Sık Yapılan Hatalar

Konular

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