Tüm alıştırma soruları

2237 soru

Soru 2161Soru

A network administrator executes a command-line query to verify how an application alias is configured in the domain zone file. The `dig` output displays the following answer section:

text
;; ANSWER SECTION:
app.example.com. 3600 IN CNAME web-server-01.example.com.

Which DNS record type is being used to map the alias hostname `app.example.com` to the canonical domain name `web-server-01.example.com`?

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Cevap: CNAME record

Cevap

The CNAME record is used to map an alias domain name to its canonical domain name.
The CNAME (Canonical Name) record is specifically designed to create an alias that points one domain name to another canonical domain name.

Adım Adım Çözüm

1
Examine the output snippet from the `dig` command.
The answer section shows `app.example.com. 3600 IN CNAME web-server-01.example.com.`.
The record type field in the resource record explicitly states `CNAME`.
2
Determine the functional role of the identified record type.
CNAME stands for Canonical Name, which creates an alias pointing to another hostname.
When a query is made for `app.example.com`, the DNS resolver follows the CNAME to `web-server-01.example.com` to obtain its IP address.

Anahtar Kavram

DNS Resource Record Types (CNAME)
Tahmini Süre:45s
Soru 2162Soru

A client computer on an enterprise network attempts to resolve the domain name www.example.com for the first time without any local cached records. Place the steps of the DNS lookup process in the correct chronological order from the initial request to receiving the IP address.

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct sequence starts with the client querying its local cache and local recursive DNS server, followed by the recursive server querying the Root Name Server, the TLD Name Server, and finally the Authoritative Name Server before returning the IP address to the client.
The standard DNS resolution flow moves from client stub resolver to local recursive resolver, then hierarchically traverses the DNS tree: Root Name Server -> TLD Name Server -> Authoritative Name Server, before caching and returning the IP address to the requesting host.

Adım Adım Çözüm

1
Initiate query locally
Client stub resolver checks cache and sends query to local recursive resolver.
Local resolution reduces unnecessary network traffic if the mapping is already known.
2
Query Root Server
Recursive resolver contacts a Root Name Server.
Root servers direct queries to the correct Top-Level Domain server (e.g., .com).
3
Query TLD Server
Recursive resolver contacts the TLD Server.
TLD servers maintain delegation records (NS records) pointing to the domain's authoritative name servers.
4
Query Authoritative Server
Recursive resolver requests the specific host record from the Authoritative Name Server.
Authoritative servers hold the actual mapping records (A/AAAA) for hostnames in their zone.
5
Return result to client
The IP address is cached by the recursive resolver and delivered to the client stub resolver.
Completes the DNS lookup lifecycle and enables network communication to the IP address.

Anahtar Kavram

DNS Recursive Resolution Hierarchy
Soru 2163Soru

A network administrator is configuring interface `GigabitEthernet1/0/12` on a switch to connect to a multi-tenant device. The device sends tagged frames for VLAN 200 (Data) and untagged frames for device management. The administrator needs to ensure that untagged management frames are assigned to VLAN 50 while allowing tagged VLAN 200 frames across the link. Which configuration snippet correctly satisfies these requirements?

Cevabı ve açıklamayı göster

Cevap: switchport mode trunk
switchport trunk native vlan 50
switchport trunk allowed vlan 50,200

Cevap

The correct configuration enables 802.1Q trunking on the switchport, sets native VLAN 50 to process untagged management frames, and includes both VLAN 50 and VLAN 200 in the allowed VLAN list.
The correct choice configures the interface in trunking mode, sets the native VLAN to 50 (which maps all untagged incoming frames to VLAN 50), and permits both VLAN 50 and VLAN 200 across the trunk link.

Adım Adım Çözüm

1
Identify the trunking requirement
The link must carry both tagged traffic (VLAN 200) and untagged traffic (Management), requiring an 802.1Q trunk configuration.
Access mode interfaces support only one untagged VLAN, whereas trunks support multiple VLANs over a single physical port.
2
Map untagged traffic to the target management VLAN
Set the native VLAN on the trunk to 50 using `switchport trunk native vlan 50`.
By default, 802.1Q trunks assign untagged frames to VLAN 1; defining a custom native VLAN redirects untagged frames to VLAN 50.
3
Verify allowed VLAN list
Include VLAN 50 and VLAN 200 using `switchport trunk allowed vlan 50,200`.
Both the native VLAN and tagged VLANs must be permitted on the trunk interface to allow bidirectionally passed frames.

Anahtar Kavram

802.1Q Native VLAN & Trunk Allowed List Configuration
Soru 2164Soru

An enterprise layer 3 switch receives an IP packet destined for 10.20.30.4510.20.30.45. The active routing table contains three matching entries for this destination:

- Static route to 10.20.30.0/2410.20.30.0/24 (Administrative Distance: 11)
- OSPF route to 10.20.30.32/2810.20.30.32/28 (Administrative Distance: 110110)
- BGP route to 10.0.0.0/810.0.0.0/8 (Administrative Distance: 2020)

Which route will the switch select to forward the packet?

Cevabı ve açıklamayı göster

Cevap: The OSPF route (10.20.30.32/2810.20.30.32/28), because it has the longest matching network prefix.

Cevap

The switch will forward the packet using the OSPF route (10.20.30.32/2810.20.30.32/28) because it represents the longest prefix match for the destination address 10.20.30.4510.20.30.45.
The router selects the OSPF route (10.20.30.32/2810.20.30.32/28) because Longest Prefix Match (LPM) is the top priority in IP routing decisions. The /28/28 prefix matches 2828 bits of the destination address 10.20.30.4510.20.30.45, making it more specific than the /24/24 or /8/8 routes.

Adım Adım Çözüm

1
Analyze the destination IP address against the routing table subnet masks.
The destination address 10.20.30.4510.20.30.45 falls within 10.0.0.0/810.0.0.0/8 (88 matching bits), 10.20.30.0/2410.20.30.0/24 (2424 matching bits), and 10.20.30.32/2810.20.30.32/28 (2828 matching bits, range 10.20.30.3210.20.30.32 - 10.20.30.4710.20.30.47).
Before comparing administrative distance, the router must identify all routes that encompass the target address.
2
Apply the Longest Prefix Match (LPM) rule.
The 10.20.30.32/2810.20.30.32/28 route has the longest prefix length (/28/28), making it the most specific route.
LPM is the fundamental criteria for IP packet forwarding, overriding Administrative Distance when destination network masks differ.

Anahtar Kavram

Longest Prefix Match (LPM) Precedence
Tahmini Süre:1m 15s
Soru 2165Soru

A network administrator is deploying OSPF across an enterprise edge router connected to a service provider. The administrator configures a static default route (0.0.0.0/00.0.0.0/0) pointing toward the ISP gateway for external Internet destination handling. The internal routers within the enterprise network need to learn this default egress route automatically through the existing dynamic routing process without manually adding static routes to every downstream router. Which of the following configuration actions should the administrator perform on the edge router to fulfill this routing requirement?

Cevabı ve açıklamayı göster

Cevap: Issue the default-information originate command within the OSPF routing process configuration.

Cevap

Issue the default-information originate command within the OSPF routing process configuration.
The correct action is to execute the default-information originate command under the OSPF router configuration mode. This command allows the autonomous system boundary router (ASBR) to inject the default route (0.0.0.0/00.0.0.0/0) into the OSPF domain, enabling all internal routers to dynamically learn the default path to external destinations.

Adım Adım Çözüm

1
Identify the goal of distributing an existing static default route (0.0.0.0/00.0.0.0/0) to internal dynamic routing peers.
Recognize that OSPF requires an explicit instruction to originate and advertise default routing information into the LSA database.
By default, OSPF does not automatically redistribute static routes, including default routes, without specific protocol configuration.
2
Evaluate the correct protocol command used to inject a default path into OSPF.
Determine that default-information originate advertises 0.0.0.0/00.0.0.0/0 into OSPF.
This command generates a Type 5 LSA to inform all interior OSPF routers of the default gateway path.

Anahtar Kavram

Default Route Redistribution and Origination in Dynamic Routing Protocols
Soru 2166Soru

A network administrator is reviewing how a link-state routing protocol like OSPF establishes network topology visibility and calculates paths. Place the operational steps of a link-state routing protocol in the correct chronological sequence, starting from initial neighbor discovery to final IP routing table entry installation.

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Cevap

The correct operational sequence begins with discovering neighbors via Hello packets, creating Link-State Advertisements (LSAs), flooding LSAs to build a synchronized Link-State Database (LSDB), executing the Dijkstra Shortest Path First (SPF) algorithm, and finally populating the IP routing table with the best paths.
Link-state dynamic routing protocols follow a strictly defined sequence of operations to achieve convergence. The process begins with neighbor discovery using Hello packets. Once adjacencies are established, routers generate Link-State Advertisements (LSAs) detailing their local interfaces and costs. These LSAs are flooded throughout the network area until every router holds an identical Link-State Database (LSDB). Each router then independently runs the Dijkstra Shortest Path First (SPF) algorithm on the LSDB to compute the shortest paths to all known destinations. Finally, the calculated best routes are populated into the router's IP routing table for forwarding operations.

Adım Adım Çözüm

1
Identify neighbor discovery phase
Routers send and receive Hello packets to find adjacent routers on active interfaces.
Direct communication must be established before control plane routing details can be exchanged.
2
Identify link state generation phase
Each router creates Link-State Advertisements (LSAs) representing its local link states and metrics.
Routers are only authoritative for the status of their directly connected networks.
3
Identify database synchronization phase
LSAs are flooded reliably across the routing area, building an identical Link-State Database (LSDB).
Link-state protocols require every router to possess the complete topology map of the area.
4
Identify path computation phase
Each router runs Dijkstra's Shortest Path First (SPF) algorithm locally using its LSDB.
The SPF algorithm processes the LSDB to construct a loop-free tree of shortest paths.
5
Identify route installation phase
The best paths from the SPF calculation are installed into the router's IP routing table.
The routing table holds the active forwarding entries used for handling incoming data packets.

Anahtar Kavram

Link-State Routing Protocol Convergence Sequence
Soru 2167Soru

A network engineer is dividing the enterprise IPv4 address block 10.45.0.0/2110.45.0.0/21 into equal-sized subnets using a prefix mask of /26/26. What is the total number of usable host IP addresses available across all of the newly created /26/26 subnets?

Cevabı ve açıklamayı göster

Cevap: 1984

Cevap

1984 total usable host IP addresses
Subnetting a /21/21 block into /26/26 subnets borrows 5 bits, creating 25=322^5 = 32 subnets. Each /26/26 subnet has 232262=622^{32-26} - 2 = 62 usable host IP addresses. Multiplying 32 subnets by 62 usable host IPs per subnet equals 1984 total usable host IP addresses across the allocated block.

Adım Adım Çözüm

1
Calculate the total number of subnets created from the /21/21 parent block.
32 subnets (22621=25=322^{26-21} = 2^5 = 32)
Borrowing 5 additional subnet bits (262126 - 21) yields 25=322^5 = 32 equal-sized subnets.
2
Calculate the usable host IP address capacity per /26/26 subnet.
62 usable host IP addresses (232262=642=622^{32-26} - 2 = 64 - 2 = 62)
Each /26/26 subnet has 6 host bits (26=642^6 = 64 total IPs), minus 2 addresses reserved for the network ID and broadcast address.
3
Compute total usable host capacity across all subnets.
1984 total usable hosts (32×62=198432 \times 62 = 1984)
Multiplying the total number of subnets by the usable capacity of a single subnet yields the aggregate usable host addresses.

Anahtar Kavram

Subnetting and Aggregate Host Capacity Calculation
Soru 2168Soru

A systems engineer queries an internal name server using the `nslookup` command to verify host address resolution for a database server:

text
> nslookup db01.contoso.local
Server: dns1.contoso.local
Address: 10.0.0.2

Name: db01.contoso.local
Address: 10.0.1.50

Which DNS resource record type provides this direct mapping of a hostname to an IPv4 address?

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Cevap: A record

Cevap

An A record is used to resolve a hostname directly to an IPv4 address.
An A (Address) record is the fundamental DNS resource record type used to map a domain name or hostname to a standard 32-bit IPv4 address. In the command output, the hostname `db01.contoso.local` resolves directly to `10.0.1.50`, which represents a standard IPv4 forward lookup.

Adım Adım Çözüm

1
Analyze the output snippet from the `nslookup` command line tool.
The query for `db01.contoso.local` returned the IP address `10.0.1.50`.
Identifying the target data format (IPv4 address) is necessary to determine the corresponding DNS record type.
2
Evaluate the address format returned by the DNS query.
The address `10.0.1.50` is a 32-bit IPv4 address.
IPv4 host resolution requires a specific forward lookup resource record type.
3
Select the record type responsible for IPv4 host mapping.
The A (Address) record matches IPv4 forward mappings.
An A record specifically binds a domain name to an IPv4 address in DNS zone files.

Anahtar Kavram

DNS A Record IPv4 Resolution
Tahmini Süre:45s
Soru 2169Soru

A network administrator is categorizing dynamic routing protocols based on administrative distance and metric calculations for an enterprise baseline audit. Match each dynamic routing protocol on the left with its corresponding default administrative distance and primary metric characteristics on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

OSPF (Open Shortest Path First)
RIPv2 (Routing Information Protocol version 2)
Internal EIGRP (Enhanced Interior Gateway Routing Protocol)
eBGP (External Border Gateway Protocol)

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

OSPF pairs with Default Administrative Distance 110 (cost based on bandwidth); RIPv2 pairs with Default Administrative Distance 120 (hop count); Internal EIGRP pairs with Default Administrative Distance 90 (composite bandwidth/delay metric); eBGP pairs with Default Administrative Distance 20 (path attributes).
Each routing protocol is accurately matched to its standard administrative distance hierarchy and path selection metric calculation method: eBGP (20, AS-Path), Internal EIGRP (90, composite bandwidth/delay), OSPF (110, cost/bandwidth), and RIPv2 (120, hop count).

Adım Adım Çözüm

1
Identify administrative distance and metric type for OSPF.
OSPF has an AD of 110 and uses bandwidth-derived cost.
OSPF link-state calculations evaluate cumulative cost based on interface reference bandwidth.
2
Identify administrative distance and metric type for RIPv2.
RIPv2 has an AD of 120 and relies on hop count (max 15).
As a distance-vector protocol, RIP uses simple hop counts up to 15.
3
Identify administrative distance and metric type for Internal EIGRP.
Internal EIGRP has an AD of 90 and uses composite bandwidth and delay.
EIGRP assigns an AD of 90 for internal routes and uses K-values (bandwidth and delay by default).
4
Identify administrative distance and metric type for eBGP.
eBGP has an AD of 20 and uses path attributes like AS-Path.
External BGP routes take high trustworthiness priority (AD 20) over internal dynamic routing protocols when selecting paths across autonomous systems.

Anahtar Kavram

Administrative Distance and Metric Properties of Dynamic Routing Protocols
Soru 2170Soru

A network engineer is configuring access control lists on a core switch that routes traffic between an enterprise client VLAN and a server subnet hosting central network services. Endpoints on the client VLAN rely on a local DHCP relay agent embedded in their default gateway to receive IP assignments from the central DHCP server. Which of the following port and transport protocol combinations must be permitted to allow full bidirectional DHCP relay and client-server operation? (Select TWO.)

Geçerli olan tümünü seçin

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Cevap: UDP port 67 for communication directed to the DHCP server; UDP port 68 for communication directed to the DHCP client

Cevap

The correct port and protocol combinations are UDP port 67 for communication directed to the DHCP server and UDP port 68 for communication directed to the DHCP client.
DHCP operates over UDP using port 67 for destination servers and relay agents, and port 68 for destination clients. Allowing both UDP 67 and UDP 68 ensures that broadcast and unicast DHCP messages (DISCOVER, OFFER, REQUEST, ACK) can traverse network boundaries between client endpoints and central services.

Adım Adım Çözüm

1
Identify the transport protocol used by Dynamic Host Configuration Protocol (DHCP).
DHCP uses User Datagram Protocol (UDP) because initial bootstrapping messages are sent before hosts have configured IP addresses.
TCP requires a valid IP address to complete a three-way handshake, making UDP the necessary choice for host configuration protocols.
2
Determine the destination ports assigned to DHCP server and client roles.
UDP port 67 is utilized by the DHCP server/relay agent, while UDP port 68 is used by the DHCP client.
Both ports must be permitted on intervening firewalls and access lists to allow bidirectional messaging (DISCOVER/REQUEST to server on port 67, and OFFER/ACK to client on port 68).

Anahtar Kavram

DHCP Port and Transport Protocol Specification
Tahmini Süre:1m 30s
Soru 2171Soru

A network engineer is allocated the IPv4 block 198.51.100.0/24198.51.100.0/24 and needs to provision subnets for departmental networks. Each departmental network must support a minimum of 2525 usable host IP addresses. Using the longest prefix length (smallest subnet size) that satisfies this host requirement, what is the maximum number of usable host IP addresses available on each generated subnet?

Cevabı ve açıklamayı göster

Cevap: 30

Cevap

Each subnet supports a maximum of 30 usable host IP addresses.
To support at least 2525 usable host IP addresses, 55 host bits are required (252=302^5 - 2 = 30). This corresponds to a /27/27 subnet prefix length (325=2732 - 5 = 27). Each /27/27 subnet contains 3232 total IP addresses. Subtracting 22 reserved addresses for the network identifier and broadcast address leaves 3030 usable host IP addresses per subnet.

Adım Adım Çözüm

1
Determine the minimum number of host bits (hh) required to accommodate 2525 usable host IP addresses using the formula 2h2252^h - 2 \ge 25.
h=5h = 5 host bits are needed because 242=142^4 - 2 = 14 (too small) and 252=30252^5 - 2 = 30 \ge 25.
Host bits determine the size of the host portion of the IPv4 address space for the subnet.
2
Calculate total usable host IP addresses per subnet created with 55 host bits (a /27/27 subnet mask, or 255.255.255.224255.255.255.224).
252=302^5 - 2 = 30 usable host IP addresses.
Two IP addresses in every block are reserved for the network ID and the broadcast address, leaving 3030 addresses available for host assignment.

Anahtar Kavram

IPv4 Subnet Mask and Usable Host Capacity Calculation
Tahmini Süre:1m 30s
Soru 2172Soru

An enterprise router receives routing updates for the identical destination network prefix (172.16.10.0/24) from two dynamic routing protocols: EIGRP and OSPF. Assuming default protocol settings and identical prefix lengths, which criterion determines which path the router places into its active IP routing table?

Cevabı ve açıklamayı göster

Cevap: Administrative distance, selecting EIGRP because its default value of 90 is lower than OSPF's default value of 110

Cevap

Administrative distance determines the path installed in the routing table, choosing EIGRP because its default administrative distance of 90 is lower than OSPF's 110.
When multiple routing protocols advertise the identical destination prefix, the router uses Administrative Distance (AD) to assess source trustworthiness. Internal EIGRP has a default AD of 90, whereas OSPF has a default AD of 110. Because 90 is lower than 110, the router selects the EIGRP path for installation into the routing table.

Adım Adım Çözüm

1
Check prefix length of competing routes
Both OSPF and EIGRP offer routes to the exact same prefix length (172.16.10.0/24).
Longest prefix match is evaluated first; since prefix lengths are equal (/24), the router proceeds to compare Administrative Distance.
2
Compare default Administrative Distance (AD) values
Internal EIGRP default AD = 90; OSPF default AD = 110.
Lower administrative distance represents a more trustworthy routing source.
3
Determine installed route
The router installs the EIGRP route into the active routing table.
EIGRP's administrative distance of 90 is lower than OSPF's administrative distance of 110.

Anahtar Kavram

Administrative Distance vs Metric in Route Selection
Soru 2173Soru

A network administrator is provisioning a dedicated IPv4 subnet for a store's point-of-sale terminals using the network address block 172.16.100.0/22172.16.100.0/22. Which of the following represents the first usable host IP address within this subnet?

Cevabı ve açıklamayı göster

Cevap: 172.16.100.1172.16.100.1

Cevap

The first usable host IP address in the 172.16.100.0/22172.16.100.0/22 subnet is 172.16.100.1172.16.100.1.
For the network block 172.16.100.0/22172.16.100.0/22, the subnet mask is 255.255.252.0255.255.252.0. The network boundary starts at 172.16.100.0172.16.100.0. Because the network address cannot be assigned to an endpoint, the first usable host IP address is obtained by adding 1 to the network address, yielding 172.16.100.1172.16.100.1.

Adım Adım Çözüm

1
Determine the network address and block size for a /22 prefix.
A /22 mask (255.255.252.0255.255.252.0) has a block size of 256252=4256 - 252 = 4 in the third octet. Since 100100 is a multiple of 44, 172.16.100.0172.16.100.0 is the valid network boundary.
Identifying the network ID establishes the starting boundary of the subnet.
2
Calculate the first usable host IP address by adding 1 to the host portion of the network ID.
Network ID 172.16.100.0172.16.100.0 + 11 = 172.16.100.1172.16.100.1.
The network address itself cannot be assigned to hosts, so the first usable host IP is immediately after the network ID.

Anahtar Kavram

IPv4 Subnet Boundaries and Usable Host Range
Soru 2174Soru

Match each 802.1Q switch interface configuration command with its corresponding operational behavior on an enterprise switch link.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

switchport trunk native vlan 99
switchport mode trunk
switchport trunk allowed vlan 10,20
switchport nonegotiate

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Matching pairs:
- 'switchport trunk native vlan 99' maps to 'Configures the interface to transmit and receive untagged traffic belonging to a designated non-default broadcast domain across the trunk.'
- 'switchport mode trunk' maps to 'Forces the interface into permanent trunking mode while continuing to send Dynamic Trunking Protocol (DTP) negotiation frames.'
- 'switchport trunk allowed vlan 10,20' maps to 'Prunes all traffic from the trunk link except for tagged frames matching the explicitly specified VLAN identification numbers.'
- 'switchport nonegotiate' maps to 'Prevents the interface from sending Dynamic Trunking Protocol (DTP) frames while operating in trunking mode.'
Each command directly aligns with standard 802.1Q trunk operational behaviors: native VLAN commands set the untagged broadcast domain, mode trunk forces 802.1Q encapsulation while keeping DTP active, allowed vlan restricts active VLAN IDs over the trunk, and nonegotiate suppresses DTP packets for enhanced security.

Adım Adım Çözüm

1
Analyze 'switchport trunk native vlan 99'
Identified as setting the 802.1Q native VLAN parameter to VLAN 99.
802.1Q trunking sends traffic for the native VLAN without inserting an 802.1Q header tag.
2
Analyze 'switchport mode trunk'
Identified as configuring unconditional trunking.
Statically setting trunk mode overrides dynamic auto/desirable modes, though DTP packets are still emitted unless explicitly suppressed.
3
Analyze 'switchport trunk allowed vlan 10,20'
Identified as configuring VLAN pruning on the trunk.
By default, all VLANs (1-4094) are allowed on a trunk link unless filtered using the allowed VLAN parameter.
4
Analyze 'switchport nonegotiate'
Identified as disabling Dynamic Trunking Protocol (DTP).
Security best practices recommend disabling unnecessary negotiation protocols on manually configured trunk links.

Anahtar Kavram

802.1Q Trunking Interface Commands and Operational Behaviors
Tahmini Süre:1m 30s
Soru 2175Soru

A network administrator is deploying a DHCP relay service on a Layer 3 boundary router to service workstations located on VLAN 40 (172.28.40.0/24172.28.40.0/24). The centralized corporate DHCP server is located on a distant management network at 10.50.1.10010.50.1.100. Workstations on VLAN 40 are currently getting APIPA addresses (169.254.x.x169.254.x.x) because broadcast DHCPDISCOVER messages are stopped at the router. Which TWO of the following requirements or configuration steps are necessary on the router to allow clients on VLAN 40 to successfully obtain leases from the central DHCP server? (Select TWO.)

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: Apply the IP helper address command targeting 10.50.1.10010.50.1.100 specifically on the router interface or SVI directly attached to VLAN 40.; Ensure the router interface facing VLAN 40 has an active IPv4 address assigned in the 172.28.40.0/24172.28.40.0/24 subnet to populate the Gateway IP Address (giaddr) field.

Cevap

The administrator must apply the IP helper address command targeting 10.50.1.10010.50.1.100 directly on the VLAN 40 interface/SVI, and ensure that the interface facing VLAN 40 has an active IPv4 address in the 172.28.40.0/24172.28.40.0/24 subnet to populate the giaddr header field.
To successfully relay DHCP traffic across Layer 3 boundaries, the router must intercept client broadcast traffic on the local client-facing interface (VLAN 40) where the `ip helper-address` command is applied. Additionally, the router uses the IP address configured on that client-facing interface to fill the `giaddr` (Gateway IP Address) field in the DHCP packet header. This field informs the remote DHCP server which subnet scope to select for assigning an IP address lease.

Adım Adım Çözüm

1
Identify the ingress boundary interface for client DHCP broadcasts.
The router interface/SVI connected directly to VLAN 40 is identified as the ingress point for broadcast DHCPDISCOVER frames.
Routers drop Layer 2 broadcasts by default. The relay agent must listen on the incoming interface receiving the broadcasts.
2
Configure the DHCP relay statement on the client-facing interface.
Applying `ip helper-address 10.50.1.100` on the VLAN 40 interface enables the conversion of incoming broadcasts to unicast packets sent to the server.
This tells the router where to forward unicast DHCP requests across routing boundaries.
3
Verify giaddr field population requirements.
The router inserts its own IP address from the VLAN 40 interface into the `giaddr` field of the unicast DHCP packet.
The centralized DHCP server reads the `giaddr` value to determine which IP address pool (172.28.40.0/24172.28.40.0/24) to issue a lease from.

Anahtar Kavram

DHCP Relay Agent Operation and Gateway IP Address (giaddr) Insertion
Soru 2176Soru

A network architect is evaluating dynamic routing protocol behaviors for an enterprise network expansion. Which of the following statements accurately contrast the operational characteristics and algorithms of link-state routing protocols with distance-vector routing protocols? (Select TWO.)

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: Link-state protocols maintain a complete topology database of the network before calculating paths, whereas distance-vector protocols rely on routing updates received from immediate neighbors.; Link-state protocols calculate optimal paths using Dijkstra's Shortest Path First (SPF) algorithm, whereas distance-vector protocols compute routes using the Bellman-Ford algorithm.

Cevap

Link-state protocols maintain a complete topology database of the network before calculating paths, whereas distance-vector protocols rely on routing updates received from immediate neighbors; and link-state protocols calculate optimal paths using Dijkstra's Shortest Path First (SPF) algorithm, whereas distance-vector protocols compute routes using the Bellman-Ford algorithm.
The correct selections describe fundamental operational differences between dynamic routing protocol classes: (1) Link-state protocols assemble a complete topological map (LSDB) before determining optimal paths, while distance-vector protocols rely on periodic vector updates from adjacent neighbors ('routing by rumor'); and (2) Link-state protocols apply Dijkstra's Shortest Path First (SPF) algorithm to their topology database, while distance-vector protocols use the Bellman-Ford algorithm.

Adım Adım Çözüm

1
Analyze network topology visibility across routing protocol families
Link-state protocols (such as OSPF) build a complete link-state database (LSDB) representing the entire network topology before running path calculation. Distance-vector protocols (such as RIP) only receive destination subnets and distance values from adjacent neighbors.
This core distinction defines how topology information is gathered and maintained.
2
Evaluate path calculation algorithms
Link-state protocols process their LSDB using Dijkstra's Shortest Path First (SPF) algorithm to construct a shortest-path tree. Distance-vector protocols calculate route metric updates using the Bellman-Ford routing algorithm.
Algorithmic foundation differentiates link-state database processing from distance-vector metric accumulation.
3
Verify metric definitions and protocol layering
Link-state protocols evaluate cost based on bandwidth, while standard distance-vector protocols use hop count. Both protocol families serve Layer 3 network routing operations.
Options reversing metrics or categorizing link-state protocols as Layer 2 mechanisms are incorrect.

Anahtar Kavram

Operational Differences Between Link-State and Distance-Vector Routing Protocols
Soru 2177Soru

A network administrator needs to assign an IPv4 subnet for a database cluster requiring static IP addresses for 110110 physical node interfaces, 22 virtual load balancer IP addresses, and 22 redundant default gateway interfaces. Which CIDR prefix length represents the smallest subnet mask that will accommodate all required host addresses?

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Cevap: /25

Cevap

The smallest subnet mask in CIDR notation that accommodates all required addresses is /25.
The scenario requires allocating 114 usable IP addresses (110+2+2=114110 + 2 + 2 = 114). A /25 subnet allocates 7 host bits, giving 27=1282^7 = 128 total IP addresses. Subtracting 2 for the network ID and broadcast address results in 126 usable host IP addresses. This satisfies the 114 required addresses while using the smallest possible subnet block.

Adım Adım Çözüm

1
Calculate total host IP addresses required
110 physical interfaces+2 load balancer virtual IPs+2 gateway interfaces=114 host IP addresses110 \text{ physical interfaces} + 2 \text{ load balancer virtual IPs} + 2 \text{ gateway interfaces} = 114 \text{ host IP addresses}.
Every active physical interface, redundant gateway, and virtual IP assigned on the local subnet requires a unique usable IPv4 host address.
2
Determine required host bits (n) using formula 2^n - 2 >= required usable hosts
For n=6n = 6, 262=622^6 - 2 = 62 usable host IPs (insufficient). For n=7n = 7, 272=1262^7 - 2 = 126 usable host IPs (sufficient for 114).
Subnet calculations must subtract 2 addresses (the Network ID and the Broadcast address) from the total pool of 2n2^n addresses.
3
Calculate the CIDR prefix length
32 total IPv4 bits7 host bits=/25 prefix length32 \text{ total IPv4 bits} - 7 \text{ host bits} = /25 \text{ prefix length}.
Subtracting the number of host bits from the 32-bit total IPv4 address space yields the subnet prefix length.

Anahtar Kavram

Calculating usable IPv4 host capacity and determining optimal CIDR subnet mask allocation.
Tahmini Süre:1m 30s
Soru 2178Soru

A client host connected to a remote VLAN requires an IPv4 address lease from a centralized DHCP server located across a Layer 3 boundary router configured with a DHCP relay agent (ip helper-address). Arrange the packet forwarding, header modifications, and protocol processing steps of the initial DHCP lease negotiation in the correct chronological order from first to last.

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Cevap

The correct chronological order of the cross-VLAN DHCP discovery and lease offer process is: (1) Host broadcasts a DHCPDISCOVER frame on UDP port 67 locally -> (2) Relay agent intercepts the broadcast, populates the giaddr header field with its interface IP, and unicasts the packet to the DHCP server on UDP port 67 -> (3) DHCP server inspects the giaddr value to select the matching scope pool and unicasts a DHCPOFFER back to the relay agent -> (4) Relay agent forwards the DHCPOFFER on UDP port 68 to the client host -> (5) Host broadcasts a DHCPREQUEST frame on UDP port 67 to accept the offer.
The cross-VLAN DHCP process follows a strict sequence: First, the host broadcasts a DHCPDISCOVER packet on UDP port 67 into its local subnet. Next, the Layer 3 relay agent intercepts this broadcast, writes its ingress interface IP address into the giaddr header field, and unicasts the modified packet across the routed network to the DHCP server on UDP port 67. Upon receipt, the DHCP server evaluates the giaddr value to select the correct IP scope pool and unicasts a DHCPOFFER back to the relay agent's IP. The relay agent then forwards this DHCPOFFER to the local client subnet on UDP port 68. Finally, the client host broadcasts a DHCPREQUEST on UDP port 67 to formally confirm its intent to lease the offered IP configuration.

Adım Adım Çözüm

1
Identify the initial packet transmission generated by the unconfigured client host.
The host broadcasts a DHCPDISCOVER packet locally (destination 255.255.255.255) using UDP destination port 67.
Because the host lacks an IP address, it must use a local broadcast to discover listening DHCP services on its segment.
2
Determine how the Layer 3 router's relay agent processes the incoming local broadcast.
The relay agent captures the broadcast, sets the giaddr (Gateway IP Address) field to its ingress interface IP, and unicasts the packet to the remote DHCP server on UDP port 67.
Routers drop Layer 2/3 broadcasts by default; the relay agent turns the broadcast into a routable unicast packet while embedding the subnet context via giaddr.
3
Analyze how the centralized DHCP server handles the relayed unicast packet and constructs its response.
The DHCP server matches the giaddr field to its configured address pools, allocates an available IP from that specific scope, and sends a unicast DHCPOFFER back to the relay agent's IP.
The server uses giaddr rather than the source IP of the relay agent packet to determine which network scope to lease an address from.
4
Trace the delivery of the lease offer from the relay agent back to the target host.
The relay agent forwards the DHCPOFFER frame onto the local client VLAN targeting UDP destination port 68.
The relay agent translates the unicast server reply back to the local client segment, directing it to client port 68.
5
Identify the client host's action upon receiving and accepting the offer.
The client host broadcasts a DHCPREQUEST message on UDP port 67.
Broadcasting the request notifies all DHCP servers that an offer was accepted, allowing other servers to release any implicitly reserved leases.

Anahtar Kavram

DHCP Relay Operation, Header Modification (giaddr), and DORA Packet Traversal
Soru 2179Soru

An enterprise network administrator deploys a new segment of 250 internal workstations that require simultaneous outbound internet access. The edge firewall is configured with dynamic NAT using a public IP pool consisting of a single /28/28 prefix (14 usable public IPv4 addresses). During peak operational hours, only the first 14 hosts can establish outbound sessions, while all remaining workstations experience connection timeouts when reaching external web servers. Which of the following configuration modifications will resolve the connectivity issue without acquiring additional public IP addresses?

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Cevap: Reconfigure the network address translation policy to enable overload (PAT) on the dynamic IP pool.

Cevap

Reconfiguring the network address translation policy to enable overload (PAT) on the existing pool will allow up to thousands of concurrent outbound connections across the available public addresses.
Standard Dynamic NAT maps internal private IP addresses to external public IP addresses on a one-to-one basis without modifying Layer 4 port numbers. Because the pool contains only 14 public IP addresses (/28/28 prefix has 16 addresses minus network and broadcast), only 14 hosts can communicate externally at any given time. Enabling Port Address Translation (PAT / NAT Overload) allows the firewall to map multiple internal private IP addresses to a single public IP address by assigning a unique ephemeral source port number to each outbound session, enabling all 250 hosts to communicate simultaneously over the existing pool.

Adım Adım Çözüm

1
Analyze the reported symptom and environment constraints.
Dynamic NAT without port mapping (1:1 dynamic binding) limits concurrent external sessions strictly to the number of available public IP addresses (14 addresses for 250 hosts).
Once all 14 public pool addresses are assigned to active host connections, the pool is exhausted and subsequent translation requests are dropped.
2
Evaluate the technical requirement.
All 250 internal hosts need outbound access simultaneously without purchasing additional public IPv4 space.
Port Address Translation (PAT / Overload) tracks outbound traffic streams using source port numbers in addition to IP addresses, allowing thousands of sessions to share a single public IP address.
3
Select the appropriate NAT implementation strategy.
Enabling PAT (NAT overload) on the existing pool configuration resolves the session exhaustion issue.
PAT scales concurrent connectivity exponentially by multiplexing Layer 4 port numbers.

Anahtar Kavram

Port Address Translation (PAT / Overload) vs Dynamic NAT Pool Exhaustion
Soru 2180Soru

A workstation on a remote branch subnet requests an IPv4 address from a centralized DHCP server located across a routed WAN link via a local Layer 3 DHCP relay agent. Arrange the steps of the initial DHCP discovery and offer phase in the correct chronological order from start to finish.

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Cevap

The correct sequence is: 1) Workstation broadcasts DHCPDISCOVER locally, 2) Relay agent populates giaddr and unicasts DHCPDISCOVER to the server, 3) DHCP server selects scope via giaddr and unicasts DHCPOFFER to relay agent, 4) Relay agent forwards DHCPOFFER to the local subnet, 5) Workstation broadcasts DHCPREQUEST.
The standard DHCP relay packet flow begins when an unconfigured host broadcasts a DHCPDISCOVER packet locally on UDP port 67. The local router acting as a relay agent receives this broadcast, stamps its own interface address into the Gateway IP Address (giaddr) field, and unicasts the packet to the centralized DHCP server on UDP port 67. Upon receiving the packet, the DHCP server inspects giaddr to identify the appropriate IP pool, picks an available IP address, and unicasts a DHCPOFFER back to the relay agent on UDP port 68. The relay agent then forwards the DHCPOFFER onto the local subnet to the host on UDP port 68. Finally, the host processes the offer and broadcasts a DHCPREQUEST to formally select the offered address.

Adım Adım Çözüm

1
Identify the initial client transmission
Workstation broadcasts a DHCPDISCOVER frame locally on UDP port 67.
Clients lacking an IP address must broadcast locally to find a server or relay agent.
2
Trace the relay agent behavior upon packet ingress
Relay agent modifies packet with giaddr field and unicasts it to the server.
Layer 3 boundaries block broadcast frames; the relay converts broadcast to unicast so routing works.
3
Determine central server processing and egress response
Server uses giaddr to select the correct IP scope and unicasts DHCPOFFER to the relay agent.
The server must know which subnet the client belongs to, which is indicated by the giaddr field.
4
Trace relay agent forwarding back to client
Relay agent receives DHCPOFFER unicast and forwards it onto the client's local subnet.
The relay agent bridges communication between the remote server and local host.
5
Identify client response to complete the offer acceptance phase
Workstation broadcasts a DHCPREQUEST accepting the IP lease.
In the standard DORA sequence, DISCOVER is followed by OFFER, then REQUEST.

Anahtar Kavram

DHCP Relay Agent Operational Packet Flow (DORA across L3 boundaries)
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