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Soru 21Soru →

An IT infrastructure team is upgrading a data center's storage and core network architecture by introducing a dedicated Storage Area Network (SAN) alongside a full-mesh topology for core switches. Which of the following statements correctly describe the technical characteristics and operational trade-offs of these implementations? (Select TWO.)

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Cevap: A full-mesh topology delivers complete link redundancy and high fault tolerance by connecting every node to every other node, requiring n(n−1)2\frac{n(n-1)}{2} total physical links for nn nodes.; A SAN provides a dedicated, high-speed network environment optimized specifically for block-level storage access by servers.

Cevap

A full-mesh topology provides complete redundancy using n(n−1)2\frac{n(n-1)}{2} physical links, and a Storage Area Network (SAN) provides dedicated block-level access to consolidated storage devices.
The statement regarding full-mesh topology accurately identifies its fault-tolerant nature and physical link calculation formula n(n−1)2\frac{n(n-1)}{2}. Additionally, the statement describing a Storage Area Network (SAN) correctly highlights its dedicated role in delivering block-level storage access to enterprise servers.

Adım Adım Çözüm

1
Analyze full-mesh topology characteristics
Full-mesh topologies eliminate single points of failure by interconnecting every node directly to every other node using n(n−1)2\frac{n(n-1)}{2} physical links.
This mathematical formula calculates the total un-directed links required for complete mesh interconnection.
2
Evaluate Storage Area Network (SAN) architecture
A SAN is designed for high-throughput, low-latency block-level data access rather than file-level network sharing.
Block-level access enables operating systems to treat remote SAN volumes as locally attached physical drives.
3
Identify misconceptions in distractors
Inter-VLAN communication strictly requires Layer 3 routing, and file-level sharing describes NAS rather than SAN.
VLAN boundaries enforce Layer 2 isolation, while file sharing operates at higher network protocol layers above raw block access.

Anahtar Kavram

Full-Mesh Topology and Storage Area Network (SAN) Architecture
Soru 22Soru →

A network switch interface configured with legacy IEEE 802.1D Spanning Tree Protocol (STP) has just experienced a physical link bring-up event. In what precise chronological order will the port transition through its operational states from initial activation to active data forwarding?

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Cevap

The correct operational order of IEEE 802.1D STP port states from initial link bring-up to full operation is Blocking State, Listening State, Learning State, and Forwarding State.
Under IEEE 802.1D STP, a switch interface transitions through four distinct operational states upon physical link up to guarantee loop avoidance. It begins in Blocking (discarding traffic and listening for BPDUs), transitions after the forward delay timer to Listening (exchanging BPDUs to determine roles), moves after a second forward delay timer to Learning (populating MAC tables without forwarding data), and finally settles in Forwarding (actively transmitting user frames and BPDUs).

Adım Adım Çözüm

1
Identify the state immediately entered upon physical link up.
The port initializes in the Blocking State.
STP defaults to Blocking to safeguard the Layer 2 domain from transient loops while initial BPDU exchange occurs.
2
Determine the state focused on topology determination and role negotiation.
The port transitions to the Listening State.
During Listening, the port active participates in BPDU transmission and election processes without altering MAC tables or forwarding data.
3
Identify the state focused on building layer 2 forwarding tables prior to frame delivery.
The port transitions to the Learning State.
Learning allows the switch to populate its MAC address table from source addresses to prevent unnecessary unicast flooding when data forwarding begins.
4
Identify the final fully operational state.
The port enters the Forwarding State.
In Forwarding, all loop management checks are complete, enabling full ingress and egress user payload traffic handling.

Anahtar Kavram

IEEE 802.1D Spanning Tree Protocol Port State Transitions
Tahmini Süre:1m 30s
Soru 23Soru →

A lead network administrator is organizing the operational documentation repository for an enterprise infrastructure. Match each network documentation record below to the specific operational task where it serves as the essential source of truth.

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Öğeler

Physical Topology Diagram
Port Mapping Schedule
Performance Baseline Document
Change Management Log

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Physical Topology Diagram matches with identifying physical cabling runs and equipment room locations. Port Mapping Schedule matches with tracing switch port numbers and patch panel terminations. Performance Baseline Document matches with evaluating current bandwidth spikes against historical normal metrics. Change Management Log matches with auditing administrative modification history and approvals.
Network documentation artifacts serve specialized operational purposes: physical topology diagrams record hardware locations and cabling paths; port mapping schedules specify exact interface-to-patch panel connections; performance baselines provide reference thresholds for historical system utilization; and change management logs maintain chronological records of configuration updates and approvals.

Adım Adım Çözüm

1
Analyze the operational requirements presented in each task.
Categorize the tasks into physical location mapping, individual interface tracking, performance comparison, and historical change tracking.
Categorization aligns specific operational needs with the specialized role of each network documentation artifact.
2
Match hardware layout and cabling details to physical documentation.
Associate physical cable paths and rack positions with physical topology diagrams, and specific port-to-jack bindings with port mapping schedules.
Physical diagrams cover spatial equipment arrangements, whereas port mapping sheets focus on specific pinouts and interface terminations.
3
Match operational metrics and historical modification records to management documentation.
Associate traffic evaluation against norms with performance baselines, and modification audit trails with change management logs.
Baselines quantify normal system behavior over time, whereas change management logs preserve audit records of system maintenance and configuration updates.

Anahtar Kavram

Operational Documentation and Diagram Classification
Tahmini Süre:1m 30s
Soru 24Soru →

A client host on a newly configured workstation network (VLAN 30) initiates an IP address lease request. A Layer 3 switch configured with an IP helper address relays this request to a centralized DHCP server located on a separate management network. Place the sequence of events handling the DHCPDISCOVER and DHCPOFFER exchange in chronological order from initial client transmission to final relay delivery.

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Cevap

The chronological sequence of the relayed DHCP exchange is: 1) Client broadcasts DHCPDISCOVER on local VLAN 30; 2) Relay agent populates giaddr and unicasts request to DHCP server; 3) DHCP server selects address pool matching giaddr; 4) DHCP server unicasts DHCPOFFER to relay agent SVI IP; 5) Relay agent forwards DHCPOFFER to client on VLAN 30.
The correct sequence follows the standard DHCP relay process: first, the client host broadcasts a DHCPDISCOVER message locally on UDP port 67. The Layer 3 relay agent intercepts this broadcast, inserts its SVI address into the giaddr header field, and forwards the packet via unicast to the DHCP server. The DHCP server uses the giaddr value to choose the correct subnet pool and returns a unicast DHCPOFFER to the relay agent on UDP port 67. Finally, the relay agent forwards the DHCPOFFER to the client host on UDP port 68.

Adım Adım Çözüm

1
Identify initial local broadcast
The unconfigured host transmits a broadcast DHCPDISCOVER frame on UDP port 67 across VLAN 30.
Hosts lacking IP addresses must initiate communications using local Layer 2 and Layer 3 broadcasts.
2
Trace relay agent header modification and forwarding
The Layer 3 switch SVI captures the broadcast, populates the giaddr header field with its interface IP, and forwards a unicast packet to the server on UDP port 67.
The relay agent converts non-routable local broadcasts into routable unicast traffic while adding subnet tracking information.
3
Determine server address allocation logic
The DHCP server matches the giaddr field to its configured address scope for VLAN 30 and reserves an available lease.
The giaddr field explicitly informs the centralized server which subnet pool must be used for assignment.
4
Trace server response transmission
The DHCP server creates a DHCPOFFER and sends it as a unicast packet directly to the relay agent's giaddr on UDP port 67.
The server returns the payload to the relay agent because the client cannot be reached across routed networks directly.
5
Verify final delivery to client
The relay agent receives the offer and sends a DHCPOFFER packet onto VLAN 30 addressed to the client on UDP port 68.
The relay agent delivers the leased address details back to the host on its local access segment.

Anahtar Kavram

DHCP Relay Packet Processing and Header Modification Lifecycle
Tahmini Süre:1m 30s
Soru 25Soru →

A network technician is configuring DNS resources for a newly deployed web server that must support dual-stack network connectivity. Which TWO of the following DNS record types must be created to resolve the server's hostname directly to its assigned IPv4 and IPv6 addresses?

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Cevap: A record; AAAA record

Cevap

The host name must be mapped to an IPv4 address using an A record and to an IPv6 address using an AAAA record.
To support dual-stack connectivity for a web server, an A record is required to resolve the hostname to an IPv4 address, and an AAAA record is required to resolve the exact same hostname to an IPv6 address.

Adım Adım Çözüm

1
Identify the requirement for forward IPv4 resolution.
Determine that mapping a hostname to an IPv4 address requires an A (Address) record.
Standard forward DNS resolution for 32-bit IPv4 addresses relies on A records.
2
Identify the requirement for forward IPv6 resolution.
Determine that mapping a hostname to an IPv6 address requires an AAAA (Quad-A) record.
IPv6 addresses are 128 bits in length (four times the size of an IPv4 address), requiring Quad-A (AAAA) records.

Anahtar Kavram

DNS Host Record Mapping for IPv4 and IPv6
Soru 26Soru →

Two enterprise switches, Switch-1 and Switch-2, run Rapid Spanning Tree Protocol (IEEE 802.1w). Switch-1 is the elected Root Bridge. Switch-2 connects to Switch-1 via a direct full-duplex Ethernet link. Additionally, Switch-2 has two redundant physical links connected directly to the same downstream shared hub. Which TWO of the following statements correctly describe the RSTP port roles and operational behaviors in this scenario?

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Cevap: The full-duplex link between Switch-1 and Switch-2 allows Switch-2 to rapidly transition its Root Port to the Forwarding state via the sync and Proposal/Agreement handshake without relying on legacy timers.; On the dual connections to the shared hub, one port on Switch-2 is elected as the Designated Port while the second port on Switch-2 becomes a Backup Port.

Cevap

The correct statements are that the full-duplex point-to-point link enables rapid Root Port forwarding via the Proposal/Agreement handshake, and that connecting two interfaces from the same switch to a shared hub results in one Designated Port and one Backup Port.
The statement regarding full-duplex rapid transitions is correct because RSTP replaces timer-based 802.1D transitions on point-to-point links with an active sync and Proposal/Agreement handshake. The statement regarding the shared hub is correct because when a switch receives its own BPDUs on a secondary link connected to a common hub, the primary link becomes the Designated Port and the secondary link becomes a Backup Port.

Adım Adım Çözüm

1
Analyze point-to-point link convergence mechanisms under IEEE 802.1w (RSTP).
RSTP uses full-duplex link state detection to execute an explicit Proposal/Agreement handshake, allowing fast convergence to the Forwarding state without waiting for legacy 15-second Listening and Learning forward delay timers.
Point-to-point links guarantee that only two switches exist on the segment, enabling direct negotiation.
2
Differentiate between RSTP Alternate and Backup port roles on Switch-2.
An Alternate Port receives superior BPDUs from another switch (providing a backup path to the Root Bridge). A Backup Port receives superior BPDUs from its own switch on a shared segment (hub).
Because both links connect to the same hub, Switch-2 hears its own BPDUs. The port with the lower Port ID becomes Designated, and the redundant port on the same switch becomes Backup.
3
Evaluate the Root Bridge priority selection mechanics.
Lower numerical bridge priority values are preferred (e.g., 4096 is preferred over 32768). Raising the priority to 61440 makes it least likely to become Root.
STP root elections always choose the minimum Bridge Identifier value.

Anahtar Kavram

RSTP Port Roles (Alternate vs. Backup) and Fast Convergence Mechanisms
Soru 27Soru →

A network host on VLAN 10 needs an IP address from a centralized DHCP server located across a routed network on VLAN 100. Place the steps of the initial DHCP discovery and offer process in the correct order from first to last.

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Cevap

The correct sequence starts with the host broadcasting a DHCPDISCOVER packet on its local subnet, followed by the local relay agent populating the GIADDR header and forwarding a unicast packet to the central server, then the DHCP server replying with a unicast DHCPOFFER using the GIADDR to choose the pool, and finally the relay agent delivering the DHCPOFFER to the local host.
The correct sequence reflects standard DHCP relay behavior across subnets: a local client broadcast is captured by the relay agent, converted to a unicast packet containing the GIADDR, processed by the central DHCP server, sent back to the relay agent as a unicast DHCPOFFER, and lastly delivered back to the client host.

Adım Adım Çözüm

1
Identify the initial client transmission on the local subnet.
The host broadcasts a DHCPDISCOVER message on UDP port 67 within VLAN 10.
The client lacks an IP address and must broadcast locally to find a DHCP server.
2
Trace the relay agent intervention at the layer 3 boundary.
The relay agent records its interface IP address in the GIADDR field and unicasts the packet across the network to the DHCP server.
Routers drop broadcast packets by default; the relay agent converts the broadcast into a routable unicast message.
3
Determine the server response mechanism.
The remote DHCP server allocates an IP address matching the GIADDR subnet and sends a unicast DHCPOFFER back to the relay agent.
The server relies on GIADDR information to determine which subnet scope to select.
4
Follow final packet delivery back to the requesting client.
The relay agent forwards the DHCPOFFER onto VLAN 10 so the client host can process it.
The relay agent completes the return path from the centralized server to the local client.

Anahtar Kavram

DHCP Relay Operation and Packet Transformation Sequence
Soru 28Soru →

A network administrator is performing Variable Length Subnet Masking (VLSM) on an enterprise network segment. A router interface is currently assigned the IP address 10.140.77.218/2110.140.77.218/21. Upon inspecting the existing IP allocations, the administrator determines that subnets 10.140.72.0/2310.140.72.0/23 and 10.140.74.0/2310.140.74.0/23 are already assigned to production VLANs. What is the maximum number of additional /26/26 subnets that can be created using only the remaining unallocated address space within this parent /21/21 block?

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Cevap: 16

Cevap

16 additional /26 subnets can be created.
The host IP address 10.140.77.218/2110.140.77.218/21 resides in the network block 10.140.72.0/2110.140.72.0/21, spanning 10.140.72.010.140.72.0 through 10.140.79.25510.140.79.255. The two allocated /23/23 subnets consume IPs 10.140.72.010.140.72.0 through 10.140.75.25510.140.75.255. This leaves 10.140.76.010.140.76.0 through 10.140.79.25510.140.79.255 unallocated, which equals a contiguous /22/22 block (10.140.76.0/2210.140.76.0/22). Dividing a /22/22 space into /26/26 subnets yields 2(26−22)=24=162^{(26-22)} = 2^4 = 16 subnets.

Adım Adım Çözüm

1
Determine the network boundary of the parent /21 subnet.
The host IP 10.140.77.218/2110.140.77.218/21 belongs to the network 10.140.72.0/2110.140.72.0/21, covering IP range 10.140.72.010.140.72.0 to 10.140.79.25510.140.79.255.
A /21 mask uses a third-octet block size of 8 (256−248=8256 - 248 = 8). Since 77÷8=977 \div 8 = 9 remainder 55, the network start is 9×8=729 \times 8 = 72.
2
Calculate the address space consumed by existing allocations.
Subnet 10.140.72.0/2310.140.72.0/23 consumes 10.140.72.010.140.72.0 - 10.140.73.25510.140.73.255, and subnet 10.140.74.0/2310.140.74.0/23 consumes 10.140.74.010.140.74.0 - 10.140.75.25510.140.75.255.
Each /23 subnet covers 2 third-octet values (224−23=22^{24-23} = 2).
3
Identify the unallocated address space remaining in the /21 parent block.
The remaining contiguous range is 10.140.76.010.140.76.0 through 10.140.79.25510.140.79.255, which forms a single 10.140.76.0/2210.140.76.0/22 subnet.
The unallocated space spans 4 third-octet blocks (76,77,78,7976, 77, 78, 79), equivalent to a /22 prefix (256−252=4256 - 252 = 4).
4
Calculate how many /26 subnets fit into the remaining /22 block.
Number of /26 subnets = 2(26−22)=24=162^{(26 - 22)} = 2^4 = 16.
Subnet division is determined by exponentiation of the bit prefix difference between the parent block prefix and the target subnet prefix.

Anahtar Kavram

VLSM Subnet Allocation and CIDR Block Subdivisions
Soru 29Soru →

A network administrator is provisioning a dedicated IPv4 subnet for a new VoIP deployment from an available 192.168.10.0/24192.168.10.0/24 network block. The subnet must accommodate 6060 IP phones, 22 router interfaces operating VRRP for default gateway redundancy, and 11 switch management interface. Which of the following CIDR prefixes represents the smallest subnet that fulfills all required host assignments while preserving the maximum amount of address space for future allocation?

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Cevap: /25/25

Cevap

The smallest subnet prefix that satisfies the host requirements while maximizing remaining address space is /25/25.
The scenario requires 6363 usable host IP addresses (6060 IP phones + 22 VRRP router addresses + 11 switch management address). The number of usable hosts in an IPv4 subnet is determined by 2h−22^h - 2, where hh is the number of host bits. A /26/26 subnet has 66 host bits, yielding 26−2=622^6 - 2 = 62 usable addresses, which is 1 address short of the required total. A /25/25 subnet has 77 host bits, providing 27−2=1262^7 - 2 = 126 usable host IP addresses. Therefore, /25/25 is the smallest subnet mask (longest CIDR prefix) that meets the requirement while conserving IP space.

Adım Adım Çözüm

1
Calculate the total number of required usable host IP addresses.
Total usable host IPs required = 60 (phones)+2 (VRRP interfaces)+1 (switch management)=6360 \text{ (phones)} + 2 \text{ (VRRP interfaces)} + 1 \text{ (switch management)} = 63 addresses.
Every active host device and redundant gateway interface requires a distinct usable IP address within the subnet.
2
Apply the usable host capacity formula for IPv4 subnetting.
Usable host capacity = 2h−22^h - 2, where h=32−prefix lengthh = 32 - \text{prefix length}.
The network ID (all host bits 0) and broadcast address (all host bits 1) are reserved and cannot be assigned to hosts.
3
Evaluate candidate CIDR prefix lengths against the required 63 usable addresses.
For /26/26 (h=6h=6): 26−2=64−2=622^6 - 2 = 64 - 2 = 62 usable addresses (insufficient by 1 IP). For /25/25 (h=7h=7): 27−2=128−2=1262^7 - 2 = 128 - 2 = 126 usable addresses (sufficient).
Selecting /26/26 by counting total addresses (6464) instead of usable addresses (6262) is a common subnetting calculation error.
4
Select the smallest subnet (longest prefix mask) that accommodates the minimum host requirement.
/25/25 is the smallest subnet mask that fulfills the 63 usable IP address requirement.
Although /24/24 also fits 63 hosts, it leaves 191 unused IP addresses in the subnet, wasting space compared to /25/25.

Anahtar Kavram

Subnet Usable Host Capacity Calculation (2h−22^h - 2 Rule) and CIDR Prefix Selection
Tahmini Süre:2m 0s
Soru 30Soru →

A network technician is deploying a new fleet of VoIP desktop phones across multiple subnets. To automate initial provisioning, each phone must automatically receive the IP address or hostname of its TFTP boot server from the central DHCP server upon starting up. Which DHCP option should the technician configure within the DHCP scope to supply this provisioning server information?

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Cevap: Option 66

Cevap

Option 66 is used in DHCP scope configurations to specify the TFTP server hostname or IP address required by booting clients like VoIP phones and PXE-enabled computers.
DHCP Option 66 is explicitly designated in core networking standards to provide the TFTP server name or IP address to DHCP clients. This allows unconfigured network devices, such as VoIP phones or PXE boot workstations, to automatically contact their boot server and download operating configurations.

Adım Adım Çözüm

1
Identify the service requirement from the scenario.
The devices need automated TFTP provisioning server information delivered via DHCP.
VoIP phones require a boot server address during IP lease acquisition to download firmware and configuration files.
2
Map the requirement to standard DHCP option codes.
DHCP Option 66 is defined specifically for TFTP Server Name / IP Address.
Standardized DHCP options allow centralized addressing services to pass vendor-neutral and protocol-specific metadata to client endpoints.

Anahtar Kavram

DHCP Options for Automated IP Addressing Services
Tahmini Süre:1m 0s
Soru 31Soru →

An enterprise border router maintains two paths to reach a remote corporate subnet (10.45.0.0/2410.45.0.0/24). Path 1 is learned via internal BGP (iBGP) with an Administrative Distance (AD) of 200, while Path 2 is learned via Open Shortest Path First (OSPF) with an AD of 110. Both routes report the exact same prefix length (/24/24). Network monitoring shows that traffic is actively taking Path 2 over the low-bandwidth OSPF backup link instead of the primary iBGP connection. Which configuration modification should the network administrator perform on the border router to ensure traffic prefers the primary iBGP link under normal operations?

Cevabı ve açıklamayı göster

Cevap: Decrease the Administrative Distance for the learned iBGP route to a value lower than 110.

Cevap

Decreasing the Administrative Distance of the iBGP route below 110 ensures the router prefers the primary iBGP link.
When a router receives multiple routes to the same network prefix with identical prefix lengths, it chooses the route with the lowest Administrative Distance (AD). Standard iBGP has a default AD of 200, whereas OSPF has a default AD of 110. Because 110 is lower than 200, the router prefers the OSPF path. Lowering the AD for the iBGP route below 110 ensures the router selects the iBGP path as primary while maintaining OSPF as the secondary backup path.

Adım Adım Çözüm

1
Evaluate the route selection hierarchy
Both candidate routes have identical prefix lengths (/24/24), so Longest Prefix Match is a tie.
When prefix lengths match, the router moves to the next evaluation criteria: Administrative Distance.
2
Compare Administrative Distance values
OSPF has an AD of 110, while iBGP has a default AD of 200.
Lower AD values indicate higher reliability/preference. The router currently installs the OSPF route (110 < 200).
3
Determine the necessary configuration change
Lower the iBGP AD below 110 (e.g., to 20 or 100).
This makes the iBGP route more believable to the routing table manager than the OSPF route.

Anahtar Kavram

Route Selection Hierarchy and Administrative Distance Preference
Soru 32Soru →

A network technician needs to assign an IPv4 subnet mask to a network segment that must accommodate 2828 usable host devices. Which CIDR notation prefix fulfills this requirement while reserving the minimal amount of unused IP addresses?

Cevabı ve açıklamayı göster

Cevap: /27

Cevap

The /27 prefix is the smallest subnet mask that provides at least 28 usable host IP addresses.
A /27 prefix allocates 5 bits for host addressing (32−27=532 - 27 = 5), resulting in 25=322^5 = 32 total IP addresses. Subtracting 22 for the network and broadcast addresses leaves 3030 usable IP addresses (32−2=3032 - 2 = 30). This is the smallest standard subnet mask that accommodates 2828 hosts.

Adım Adım Çözüm

1
Calculate the total required IP addresses by adding 2 reserved addresses (network ID and broadcast address) to the needed host count.
28 hosts+2 reserved=30 total addresses needed28\text{ hosts} + 2\text{ reserved} = 30\text{ total addresses needed}.
Every IPv4 subnet requires one network address and one broadcast address, which cannot be assigned to hosts.
2
Find the smallest block size (power of 2) that is greater than or equal to the total required addresses.
25=32 total addresses2^5 = 32\text{ total addresses}, requiring 55 host bits.
Subnet block sizes must be powers of two.
3
Subtract the host bits from 32 to determine the network prefix length.
32−5=/2732 - 5 = /27.
An IPv4 address contains 32 total bits.

Anahtar Kavram

IPv4 Host Capacity and Subnet Mask Selection
Tahmini Süre:45s
Soru 33Soru →

Match each 802.1Q trunking component or port mode behavior on the left with its corresponding operational description on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Native VLAN egress behavior
Tagged VLAN egress behavior
Standard access port ingress behavior
802.1Q Tag Control Information (TCI)

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Native VLAN egress behavior matches forwarding frames untagged across the trunk. Tagged VLAN egress behavior matches inserting a 4-byte header containing a 12-bit VLAN ID. Standard access port ingress behavior matches accepting untagged frames, assigning them to the configured access VLAN, and dropping tagged frames. 802.1Q Tag Control Information (TCI) matches containing PCP/CoS priority bits, DEI, and the 12-bit VLAN ID.
The correct pairings accurately reflect IEEE 802.1Q header structures and switchport operations: Native VLAN egress traffic flows untagged; non-native VLAN traffic has a 4-byte header with a 12-bit VLAN ID inserted; access ports accept untagged host frames for a single broadcast domain while discarding tagged frames; and the 802.1Q TCI field encodes 3-bit CoS priority, 1-bit DEI, and the 12-bit VLAN identifier.

Adım Adım Çözüm

1
Analyze Native VLAN trunking behavior
Native VLAN traffic travels across 802.1Q trunk links untagged without modifying the original frame encapsulation.
IEEE 802.1Q trunking specifies that the native VLAN carries untagged frames across interconnecting switches for backward compatibility.
2
Analyze Tagged VLAN trunking behavior
Non-native VLAN frames receive a 4-byte 802.1Q tag containing a 12-bit VLAN Identifier (VID).
Explicit tagging enables switches on both ends of the trunk to correctly segregate traffic into distinct logical networks.
3
Analyze Access Port ingress behavior
Access ports receive untagged traffic from host interfaces and assign it to a single target VLAN.
Access ports belong strictly to one VLAN domain and discard incoming tagged frames for security and operational integrity.
4
Analyze 802.1Q TCI subfields
The TCI subfield allocates 3 bits for Class of Service (CoS), 1 bit for DEI, and 12 bits for VID.
The 12-bit VID allows support for up to 4,094 usable VLANs (212−22^{12} - 2).

Anahtar Kavram

VLAN Configuration and 802.1Q Trunking Mechanics
Soru 34Soru →

A network host connected to interface FastEthernet 0/120/12 on a Layer 2 switch transmits an Address Resolution Protocol (ARP) request broadcast frame. Interface FastEthernet 0/120/12 is configured as an access port belonging to VLAN 5050. Which of the following actions will the switch perform upon receiving this frame?

Cevabı ve açıklamayı göster

Cevap: The switch forwards the frame out all operational access ports assigned to VLAN 5050, excluding interface FastEthernet 0/120/12.

Cevap

The switch forwards the broadcast frame out all active access ports configured for VLAN 50, excluding the receiving port FastEthernet 0/12.
A Virtual Local Area Network (VLAN) creates a logical Layer 2 broadcast domain. When a broadcast frame (such as an ARP request) is received on an access port, the switch floods that frame to every active port belonging to the same VLAN, while excluding the port on which the frame originally arrived to prevent loops.

Adım Adım Çözüm

1
Identify the frame type and ingress port configuration.
The frame is an ARP request broadcast (destination MAC ff:ff:ff:ff:ff:ff) arriving on access port FastEthernet 0/12 assigned to VLAN 50.
Understanding the PDU type and port membership determines how the switch handles forwarding.
2
Determine the Layer 2 broadcast domain boundary.
VLAN 50 forms a logical Layer 2 broadcast domain isolated from all other VLANs on the switch.
Broadcast frames are contained strictly within the originating VLAN.
3
Apply Layer 2 switch flooding behavior rules.
The switch floods the broadcast frame to all active interfaces assigned to VLAN 50, except the ingress port FastEthernet 0/12, without applying 802.1Q tags to access port output.
Standard switch logic dictates flooding broadcast traffic within the VLAN while preventing loopback to the source port.

Anahtar Kavram

VLAN Broadcast Domain Boundaries and Layer 2 Flooding Logic
Tahmini Süre:1m 15s
Soru 35Soru →

An enterprise firewall is configured to handle traffic between an internal network (10.0.0.0/810.0.0.0/8) and the Internet. The administrator configures Port Address Translation (PAT / NAT Overload) using the firewall's public interface IP address (203.0.113.1203.0.113.1) for internal host outbound access. Simultaneously, a Static NAT rule is configured to map an internal web server (10.0.0.5010.0.0.50) to a dedicated public IP address (203.0.113.2203.0.113.2). Which of the following statements accurately describe how address translation operates in this environment? (Select TWO.)

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Cevap: Outbound packets from internal workstations undergoing PAT have their source IP address translated to 203.0.113.1203.0.113.1 and their source Layer 4 port numbers dynamically mapped to track individual sessions.; Inbound connections destined for 203.0.113.2203.0.113.2 undergo a 1-to-1 destination IP translation to 10.0.0.5010.0.0.50 without requiring Layer 4 port modification.

Cevap

Port Address Translation (PAT) dynamically translates both the private source IP address and Layer 4 source port numbers to track sessions for multiple hosts using a single public IP address. Static NAT performs a fixed 1-to-1 Layer 3 translation between a private IP address and a public IP address without altering transport-layer ports.
Port Address Translation (PAT) handles many-to-one outbound traffic by translating private source IP addresses to a single public IP address (203.0.113.1203.0.113.1) while dynamically allocating unique Layer 4 source ports to track connections. Static NAT provides a bi-directional 1-to-1 mapping between a private IP address (10.0.0.5010.0.0.50) and a public IP address (203.0.113.2203.0.113.2) strictly at Layer 3 without changing port numbers.

Adım Adım Çözüm

1
Analyze the operational mechanics of Port Address Translation (PAT / NAT Overload).
PAT allows many internal hosts to share one public IP address by tracking session state using unique TCP/UDP source ports assigned at the router/firewall.
Layer 4 port tracking is necessary to demultiplex returning traffic back to the correct internal private IP address.
2
Analyze the operational mechanics of Static NAT.
Static NAT creates a permanent one-to-one mapping between an inside local address (e.g., 10.0.0.5010.0.0.50) and an inside global address (e.g., 203.0.113.2203.0.113.2).
Static NAT operates entirely at Layer 3 and translates only the network header addresses, preserving the transport layer header.
3
Evaluate the option statements against Network NAT/PAT definitions.
The statement regarding outbound PAT host port mapping and the statement regarding 1-to-1 static destination translation are correct.
Distractors confuse Layer 3 IP translation with Layer 4 port translation roles.

Anahtar Kavram

NAT and PAT Implementation Differences
Soru 36Soru →

A network engineer is implementing DHCP Relay Agent Information Option (Option 82) on Layer 2 access switches within an enterprise building. When a client sends a broadcast DHCPDISCOVERDHCPDISCOVER message, the relay agent appends sub-options to the request before forwarding it to a centralized DHCP server across a routed core. Which sub-option field specifically carries identifying information about the physical switch port and VLAN from which the client request originated?

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Cevap: Circuit ID (Sub-option 1)

Cevap

Circuit ID (Sub-option 1) is added by the DHCP relay agent to specify the client's physical port and VLAN information.
DHCP Option 82 allows a relay agent to attach location-specific metadata to client DHCP broadcasts. Sub-option 1 (Circuit ID) encodes the specific physical interface, module, and VLAN tag where the client broadcast was received.

Adım Adım Çözüm

1
Analyze the role of DHCP Option 82 (Relay Agent Information Option)
Option 82 allows relay agents to insert network topology details into client DHCP requests before forwarding them to the server.
This information enables the DHCP server to enforce security policies and assign IP addresses or parameters based on physical location.
2
Differentiate between Option 82 standard sub-options
Sub-option 1 (Circuit ID) identifies the incoming port/VLAN circuit, whereas Sub-option 2 (Remote ID) identifies the relay agent switch/router identity.
Circuit ID contains specific access port details (e.g., interface index, VLAN tag) necessary to identify where the host connects.

Anahtar Kavram

DHCP Option 82 and Relay Agent Information Sub-options
Soru 37Soru →

A network technician is documenting IPv6 deployment scopes and prefix classifications across an enterprise infrastructure. Match each IPv6 address type on the left to its correct prefix range and functional scope on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Global Unicast Address (GUA)
Link-Local Address
Unique Local Address (ULA)
Multicast Address

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Global Unicast Address (GUA) pairs with the 2000::/3 globally routable internet block. Link-Local Address pairs with the fe80::/10 single local segment block. Unique Local Address (ULA) pairs with the fc00::/7 private internal routing block. Multicast Address pairs with the ff00::/8 one-to-many group delivery block.
Each IPv6 address type is defined by specific prefix allocations. Global Unicast Addresses use 2000::/3 for public internet traffic. Link-Local addresses use fe80::/10 for communications limited strictly to the local network segment. Unique Local Addresses use fc00::/7 for internal enterprise networks. Multicast addresses start with ff00::/8 to reach multiple subscribed devices across a network.

Adım Adım Çözüm

1
Identify the prefix and functional scope for Global Unicast Addresses (GUA).
GUA corresponds to 2000::/3 (including 2001::/16) for public internet routing.
GUAs are equivalent to public IPv4 addresses.
2
Identify the prefix and scope for Link-Local addresses.
Link-Local corresponds to fe80::/10 for non-routable communication within the immediate physical or logical link.
Link-Local addresses are automatically created on IPv6-enabled interfaces for neighbor discovery and local communications.
3
Identify the prefix and scope for Unique Local Addresses (ULA).
ULA corresponds to fc00::/7 for private internal networks.
ULAs allow organization-wide internal routing without being reachable from the global internet.
4
Identify the prefix and scope for Multicast addresses.
Multicast corresponds to ff00::/8 for delivering messages to multiple subscribing hosts.
IPv6 uses multicast instead of broadcast for efficient group delivery.

Anahtar Kavram

IPv6 Address Classifications and Scope Prefixes
Soru 38Soru →

A network administrator is configuring perimeter security rules to allow an internal Remote Authentication Dial-In User Service (RADIUS) server to authenticate wireless users against an external partner system. Which transport protocol and destination port pair must be permitted through the firewall for standard RADIUS authentication traffic?

Cevabı ve açıklamayı göster

Cevap: UDP port 1812

Cevap

Standard RADIUS authentication traffic operates over UDP port 1812.
UDP port 1812 is the standard IANA-assigned port for RADIUS authentication and authorization traffic. RADIUS uses UDP for lightweight connectionless transmission.

Adım Adım Çözüm

1
Identify the protocol and required function in the scenario
The scenario requires RADIUS performing authentication.
RADIUS separates authentication/authorization (port 1812) from accounting functions (port 1813).
2
Determine the transport protocol used by RADIUS
RADIUS uses UDP rather than TCP at the Transport Layer.
RADIUS relies on connectionless UDP transport and handles retransmissions at the application layer.
3
Select the correct port and transport protocol pairing
UDP port 1812 is the official standard IANA port for RADIUS authentication.
UDP 1812 ensures RADIUS authentication requests reach the RADIUS daemon properly.

Anahtar Kavram

RADIUS Port Numbers and Protocols
Tahmini Süre:1m 0s
Soru 39Soru →

A network engineer is configuring a core router that learns a path to the 10.50.0.0/1610.50.0.0/16 network through multiple routing sources simultaneously: an internal OSPF advertisement, a RIPv2 advertisement, and a manually configured static route. All sources advertise the exact same prefix length. Which path will the router install into its active routing table, and why?

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Cevap: The static route, because static routes have a lower Administrative Distance than OSPF and RIPv2.

Cevap

The static route is installed into the routing table because it has the lowest Administrative Distance (AD = 1) compared to OSPF (AD = 110) and RIPv2 (AD = 120) for the exact same destination prefix.
When a router receives multiple routes to the exact same destination network prefix from different routing sources, it uses Administrative Distance (AD) to select the best route. Default AD values are: Static route = 1, OSPF = 110, and RIPv2 = 120. Because lower AD indicates higher trustworthiness, the static route is selected.

Adım Adım Çözüm

1
Identify the advertised destination prefix lengths across all sources.
All three routes offer identical prefix lengths (10.50.0.0/1610.50.0.0/16), so Longest Prefix Match (LPM) ties.
When prefix lengths match, the router evaluates Administrative Distance (AD) to determine trustworthiness.
2
Compare the Administrative Distance values of the competing routing sources.
Static Route AD = 1, OSPF AD = 110, RIPv2 AD = 120.
Lower Administrative Distance values indicate higher administrative preference and trustworthiness.
3
Select the winning route to install in the IP routing table.
The static route with AD = 1 is selected.
The router selects the path with the lowest Administrative Distance.

Anahtar Kavram

Administrative Distance Hierarchy and Route Selection
Soru 40Soru →

During a facility renovation, an IT team installs new workstations across multiple offices. A network technician needs to record the detailed mapping between individual wall outlet jacks, patch panel ports, and physical cable run paths back to the Intermediate Distribution Frame (IDF). Which type of documentation should the technician update to preserve this physical cabling location data?

Cevabı ve açıklamayı göster

Cevap: Cable run schedule

Cevap

The cable run schedule is the appropriate document for recording physical wall jack locations, cabling paths, and patch panel port assignments.
A cable run schedule (or wiring documentation) provides an itemized index of physical network drops. It documents cable tag numbers, originating wall outlets, floor locations, and the corresponding patch panel and switch port assignments in an IDF or MDF cabinet.

Adım Adım Çözüm

1
Analyze the documentation requirements described in the scenario
The scenario requires tracking physical copper drops, wall jack numbers, patch panel ports, and cable routes between offices and the IDF.
Physical infrastructure details belong to Layer 1 documentation rather than logical configuration maps.
2
Compare network documentation types against the physical requirements
A cable run schedule provides a comprehensive matrix of cable IDs, floor locations, port terminations, and jack IDs.
It enables technicians to quickly trace physical connections during maintenance or troubleshooting.

Anahtar Kavram

Cable Run Schedule and Physical Network Documentation
Tahmini Süre:1m 0s
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