Networking Concepts

538 soru

Soru 521Soru

An enterprise router receives two dynamic route updates for the destination network 172.16.40.0/24. The first update is received from OSPF with a metric cost of 45. The second update is received from RIPv2 with a hop count metric of 2. Default administrative distance values are configured across all protocols on the router. Which path will be installed into the active IP routing table?

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Cevap: The OSPF route, because OSPF has a lower default administrative distance than RIPv2.

Cevap

The OSPF route will be selected and installed into the routing table because OSPF has a lower default administrative distance (110) than RIPv2 (120).
When a router receives candidate routes to the exact same prefix length from two different dynamic routing protocols, it evaluates Administrative Distance (AD) first. By default, OSPF has an AD of 110 and RIPv2 has an AD of 120. The lower AD value indicates a more reliable route source, so the OSPF path is chosen for installation in the routing table.

Adım Adım Çözüm

1
Identify the routing protocols providing updates for the target network
Two distinct protocols (OSPF and RIPv2) are offering paths to 172.16.40.0/24.
When multiple sources offer paths to the same destination network prefix, the router must decide which source is more trustworthy.
2
Compare the default Administrative Distance (AD) for both protocols
OSPF has a default AD of 110, while RIPv2 has a default AD of 120.
Administrative Distance ranks the reliability of routing protocols; lower numerical AD values indicate higher trustworthiness.
3
Determine which route is selected for routing table insertion
The OSPF route is selected due to its lower AD (110 vs 120).
Because AD resolves route selection between different protocols, protocol metric values (cost of 45 vs hop count of 2) are not compared against each other.

Anahtar Kavram

Administrative Distance in Multi-Protocol Routing Selection
Soru 522Soru

A network administrator is provisioning a dedicated IPv4 subnet for a smart building automation system that requires static IP addresses for 5858 environmental sensors. To conserve address space, which of the following CIDR prefix lengths represents the smallest subnet that accommodates this requirement?

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Cevap: /26/26

Cevap

The prefix length /26/26 provides 6262 usable host IP addresses, which is the smallest subnet that can accommodate 5858 sensors.
The prefix length /26/26 allocates 6 host bits (26=642^6 = 64 total IP addresses). Subtracting 2 reserved addresses (one for network ID and one for broadcast) yields 6262 usable host IP addresses. This is the smallest subnet size that accommodates all 5858 required hosts without unnecessary address wastage.

Adım Adım Çözüm

1
Determine required host capacity including overhead
58 hosts needed + 2 overhead addresses (network ID and broadcast address) = 60 total IP addresses minimum.
Every IPv4 subnet requires one address for the network ID and one address for the subnet broadcast.
2
Calculate the required host bits (h)
2^h >= 60 total addresses. For h = 5, 2^5 = 32 (too small). For h = 6, 2^6 = 64 (sufficient).
We need the smallest power of 2 that is greater than or equal to 60.
3
Calculate prefix length
32 total IPv4 bits - 6 host bits = /26.
Subtracting host bits from 32 gives the network prefix length.

Anahtar Kavram

Determining Minimum IPv4 Subnet Mask / CIDR Prefix for Host Requirements
Tahmini Süre:1m 0s
Soru 523Soru

A network engineer is evaluating dynamic routing protocols for an enterprise network expansion. The requirement is to implement a protocol that maintains a detailed topology map of the network and converges quickly upon topology changes. Which of the following statements accurately describe operational characteristics of Link-State dynamic routing protocols? (Select TWO)

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Cevap: Routers build an independent, complete view of the network topology stored in a Link-State Database (LSDB).; Routers transmit triggered Link-State Advertisements (LSAs) immediately upon detecting link updates rather than periodically sending full routing tables.

Cevap

Link-State routing protocols are characterized by each router maintaining a complete topology map in its Link-State Database (LSDB) and using event-driven Link-State Advertisements (LSAs) to notify neighbors of topology changes.
Link-state protocols function by having every router build an identical topology database (LSDB) for its area using the Shortest Path First (SPF) algorithm. In addition, link-state protocols do not send their full routing tables on a periodic timer; instead, they flood incremental Link-State Advertisements (LSAs) immediately when a link status change occurs.

Adım Adım Çözüm

1
Identify the fundamental mechanics of Link-State routing protocols.
Link-state protocols (such as OSPF and IS-IS) rely on neighbor discovery, LSA flooding, and the Dijkstra Shortest Path First (SPF) algorithm to calculate optimal paths.
Unlike distance-vector protocols that route by rumor, link-state routers possess full topology visibility.
2
Evaluate statements regarding LSDB structure and update mechanisms.
The statement regarding routers building an independent topology map in an LSDB and the statement regarding event-driven, triggered LSA updates are both true characteristics of link-state protocols.
Event-driven updates ensure fast convergence, while the LSDB provides full topology awareness.
3
Eliminate statements describing distance-vector features or Layer 2 misattributions.
The statement describing periodic routing table broadcasts based on hop count refers to distance-vector protocols (e.g., RIP), and the statement claiming routing logic operates strictly at Layer 2 confuses OSI layer roles.
Link-state protocols use cost metrics based on bandwidth (not hop count) and function within Layer 3 routing control plane processes.

Anahtar Kavram

Operational characteristics of Link-State dynamic routing protocols (LSDB, event-driven LSAs, SPF algorithm)
Soru 524Soru

An enterprise network engineer is provisioning an isolated management subnet using the IPv4 block 10.150.80.0/2310.150.80.0/23. Out of the total usable host IP addresses in this subnet, 55 IP addresses are statically reserved for gateway redundancy protocols and infrastructure monitoring agents. How many usable host IP addresses remain available for assignment to endpoint workstations in this subnet?

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Cevap: 505

Cevap

The total number of usable host IP addresses remaining available for endpoint workstations is 505.
A /23 CIDR prefix allocates 9 bits for host addressing, yielding 29=5122^9 = 512 total IP addresses. Subtracting 2 addresses for the network ID and broadcast address leaves 510 usable host IP addresses. Deducting the 5 statically reserved infrastructure addresses results in 505 remaining usable host addresses for endpoint workstations.

Adım Adım Çözüm

1
Calculate the total IP address capacity of a /23 prefix block.
A /23 subnet contains 23223=29=5122^{32 - 23} = 2^9 = 512 total IP addresses.
The prefix length of /23 leaves 9 bits available for host addressing.
2
Subtract the non-assignable network ID and broadcast address.
5122=510512 - 2 = 510 standard usable host IP addresses.
The first address in the block is the network identifier and the last address is the subnet broadcast address.
3
Deduct the statically reserved IP addresses from the usable host pool.
5105=505510 - 5 = 505 host IP addresses remaining.
Five addresses are designated for gateway redundancy and monitoring infrastructure, leaving 505 addresses for workstations.

Anahtar Kavram

IPv4 Subnet Usable Host Calculation with Infrastructure Reservations
Tahmini Süre:1m 30s
Soru 525Soru

A network engineer is configuring an interface on a gateway router for an isolated security camera subnet with the network IP address block 192.168.88.192/27192.168.88.192/27. What is the last usable host IP address that can be assigned to a device on this subnet?

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Cevap: 192.168.88.222

Cevap

192.168.88.222
For the IPv4 subnet block 192.168.88.192/27192.168.88.192/27, a block size of 32 addresses spans from 192.168.88.192 to 192.168.88.223. The network ID is 192.168.88.192 and the broadcast address is 192.168.88.223. Consequently, the assignable host range is 192.168.88.193 through 192.168.88.222, making 192.168.88.222 the last usable host IP address.

Adım Adım Çözüm

1
Determine the block size for a /27 subnet mask.
A /27 prefix leaves 5 host bits (3227=532 - 27 = 5). The total address count per block is 25=322^5 = 32.
Calculating the block size establishes the address boundary for the subnet.
2
Identify the broadcast address for the subnet block starting at 192.168.88.192.
Adding the block size of 32 to the network ID gives 192+32=224192 + 32 = 224 (the start of the next subnet). Thus, the broadcast address for this block is 192.168.88.223.
The last IP address in any subnet block is reserved for broadcast traffic.
3
Calculate the last usable host IP address.
Subtracting 1 from the broadcast address (192.168.88.2231192.168.88.223 - 1) yields 192.168.88.222.
Usable host addresses exist strictly between the network ID and the broadcast address.

Anahtar Kavram

Subnet Host Boundaries and Usable IP Allocation
Soru 526Soru

A network administrator is inspecting a packet capture file on a host receiving an automated file transfer. As the destination host de-encapsulates the incoming data unit from the physical network interface up to the application process, the protocol stack must inspect specific header fields to identify which higher-layer protocol or service should receive the payload next. Which of the following correctly identifies the sequential order of header fields evaluated at Layer 2, Layer 3, and Layer 4 to route the payload to the correct application process?

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Cevap: EtherType in the Ethernet frame header, Protocol field in the IPv4 packet header, and Destination Port in the Transport segment header

Cevap

EtherType in the Ethernet frame header, Protocol field in the IPv4 packet header, and Destination Port in the Transport segment header
De-encapsulation is a bottom-up process where each OSI layer evaluates specific header fields to demultiplex and route the payload to the next higher layer protocol. At Layer 2 (Data Link), the EtherType field specifies the Layer 3 protocol (such as IPv4 or IPv6). At Layer 3 (Network), the Protocol field specifies the Layer 4 transport protocol (such as TCP or UDP). At Layer 4 (Transport), the Destination Port number identifies the target service or process at the Application layer.

Adım Adım Çözüm

1
Analyze Layer 2 de-encapsulation requirements
The network interface card processes the Ethernet frame header and evaluates the EtherType field (e.g., 0x0800 for IPv4) to determine which Network layer protocol driver should process the frame payload.
Layer 2 headers use EtherType to demultiplex traffic to the proper Layer 3 protocol.
2
Analyze Layer 3 de-encapsulation requirements
The Internet Protocol driver processes the IPv4 packet header and evaluates the Protocol field (e.g., 6 for TCP, 17 for UDP) to determine which Transport layer protocol module receives the packet payload.
Layer 3 headers use the Protocol field to demultiplex traffic to the proper Layer 4 protocol.
3
Analyze Layer 4 de-encapsulation requirements
The Transport layer protocol processes the segment header and evaluates the Destination Port number to direct the data payload to the specific socket/application bound to that port.
Layer 4 headers use port numbers to direct data to the correct application layer process.

Anahtar Kavram

De-encapsulation Demultiplexing Fields
Soru 527Soru

An enterprise layer 3 switch receives an IP packet destined for 10.20.30.4510.20.30.45. The active routing table contains three matching entries for this destination:

- Static route to 10.20.30.0/2410.20.30.0/24 (Administrative Distance: 11)
- OSPF route to 10.20.30.32/2810.20.30.32/28 (Administrative Distance: 110110)
- BGP route to 10.0.0.0/810.0.0.0/8 (Administrative Distance: 2020)

Which route will the switch select to forward the packet?

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Cevap: The OSPF route (10.20.30.32/2810.20.30.32/28), because it has the longest matching network prefix.

Cevap

The switch will forward the packet using the OSPF route (10.20.30.32/2810.20.30.32/28) because it represents the longest prefix match for the destination address 10.20.30.4510.20.30.45.
The router selects the OSPF route (10.20.30.32/2810.20.30.32/28) because Longest Prefix Match (LPM) is the top priority in IP routing decisions. The /28/28 prefix matches 2828 bits of the destination address 10.20.30.4510.20.30.45, making it more specific than the /24/24 or /8/8 routes.

Adım Adım Çözüm

1
Analyze the destination IP address against the routing table subnet masks.
The destination address 10.20.30.4510.20.30.45 falls within 10.0.0.0/810.0.0.0/8 (88 matching bits), 10.20.30.0/2410.20.30.0/24 (2424 matching bits), and 10.20.30.32/2810.20.30.32/28 (2828 matching bits, range 10.20.30.3210.20.30.32 - 10.20.30.4710.20.30.47).
Before comparing administrative distance, the router must identify all routes that encompass the target address.
2
Apply the Longest Prefix Match (LPM) rule.
The 10.20.30.32/2810.20.30.32/28 route has the longest prefix length (/28/28), making it the most specific route.
LPM is the fundamental criteria for IP packet forwarding, overriding Administrative Distance when destination network masks differ.

Anahtar Kavram

Longest Prefix Match (LPM) Precedence
Tahmini Süre:1m 15s
Soru 528Soru

A network engineer is dividing the enterprise IPv4 address block 10.45.0.0/2110.45.0.0/21 into equal-sized subnets using a prefix mask of /26/26. What is the total number of usable host IP addresses available across all of the newly created /26/26 subnets?

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Cevap: 1984

Cevap

1984 total usable host IP addresses
Subnetting a /21/21 block into /26/26 subnets borrows 5 bits, creating 25=322^5 = 32 subnets. Each /26/26 subnet has 232262=622^{32-26} - 2 = 62 usable host IP addresses. Multiplying 32 subnets by 62 usable host IPs per subnet equals 1984 total usable host IP addresses across the allocated block.

Adım Adım Çözüm

1
Calculate the total number of subnets created from the /21/21 parent block.
32 subnets (22621=25=322^{26-21} = 2^5 = 32)
Borrowing 5 additional subnet bits (262126 - 21) yields 25=322^5 = 32 equal-sized subnets.
2
Calculate the usable host IP address capacity per /26/26 subnet.
62 usable host IP addresses (232262=642=622^{32-26} - 2 = 64 - 2 = 62)
Each /26/26 subnet has 6 host bits (26=642^6 = 64 total IPs), minus 2 addresses reserved for the network ID and broadcast address.
3
Compute total usable host capacity across all subnets.
1984 total usable hosts (32×62=198432 \times 62 = 1984)
Multiplying the total number of subnets by the usable capacity of a single subnet yields the aggregate usable host addresses.

Anahtar Kavram

Subnetting and Aggregate Host Capacity Calculation
Soru 529Soru

A network administrator is categorizing dynamic routing protocols based on administrative distance and metric calculations for an enterprise baseline audit. Match each dynamic routing protocol on the left with its corresponding default administrative distance and primary metric characteristics on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

OSPF (Open Shortest Path First)
RIPv2 (Routing Information Protocol version 2)
Internal EIGRP (Enhanced Interior Gateway Routing Protocol)
eBGP (External Border Gateway Protocol)

Eşleşmeler

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Cevap

OSPF pairs with Default Administrative Distance 110 (cost based on bandwidth); RIPv2 pairs with Default Administrative Distance 120 (hop count); Internal EIGRP pairs with Default Administrative Distance 90 (composite bandwidth/delay metric); eBGP pairs with Default Administrative Distance 20 (path attributes).
Each routing protocol is accurately matched to its standard administrative distance hierarchy and path selection metric calculation method: eBGP (20, AS-Path), Internal EIGRP (90, composite bandwidth/delay), OSPF (110, cost/bandwidth), and RIPv2 (120, hop count).

Adım Adım Çözüm

1
Identify administrative distance and metric type for OSPF.
OSPF has an AD of 110 and uses bandwidth-derived cost.
OSPF link-state calculations evaluate cumulative cost based on interface reference bandwidth.
2
Identify administrative distance and metric type for RIPv2.
RIPv2 has an AD of 120 and relies on hop count (max 15).
As a distance-vector protocol, RIP uses simple hop counts up to 15.
3
Identify administrative distance and metric type for Internal EIGRP.
Internal EIGRP has an AD of 90 and uses composite bandwidth and delay.
EIGRP assigns an AD of 90 for internal routes and uses K-values (bandwidth and delay by default).
4
Identify administrative distance and metric type for eBGP.
eBGP has an AD of 20 and uses path attributes like AS-Path.
External BGP routes take high trustworthiness priority (AD 20) over internal dynamic routing protocols when selecting paths across autonomous systems.

Anahtar Kavram

Administrative Distance and Metric Properties of Dynamic Routing Protocols
Soru 530Soru

A network engineer is configuring access control lists on a core switch that routes traffic between an enterprise client VLAN and a server subnet hosting central network services. Endpoints on the client VLAN rely on a local DHCP relay agent embedded in their default gateway to receive IP assignments from the central DHCP server. Which of the following port and transport protocol combinations must be permitted to allow full bidirectional DHCP relay and client-server operation? (Select TWO.)

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Cevap: UDP port 67 for communication directed to the DHCP server; UDP port 68 for communication directed to the DHCP client

Cevap

The correct port and protocol combinations are UDP port 67 for communication directed to the DHCP server and UDP port 68 for communication directed to the DHCP client.
DHCP operates over UDP using port 67 for destination servers and relay agents, and port 68 for destination clients. Allowing both UDP 67 and UDP 68 ensures that broadcast and unicast DHCP messages (DISCOVER, OFFER, REQUEST, ACK) can traverse network boundaries between client endpoints and central services.

Adım Adım Çözüm

1
Identify the transport protocol used by Dynamic Host Configuration Protocol (DHCP).
DHCP uses User Datagram Protocol (UDP) because initial bootstrapping messages are sent before hosts have configured IP addresses.
TCP requires a valid IP address to complete a three-way handshake, making UDP the necessary choice for host configuration protocols.
2
Determine the destination ports assigned to DHCP server and client roles.
UDP port 67 is utilized by the DHCP server/relay agent, while UDP port 68 is used by the DHCP client.
Both ports must be permitted on intervening firewalls and access lists to allow bidirectional messaging (DISCOVER/REQUEST to server on port 67, and OFFER/ACK to client on port 68).

Anahtar Kavram

DHCP Port and Transport Protocol Specification
Tahmini Süre:1m 30s
Soru 531Soru

A network engineer is allocated the IPv4 block 198.51.100.0/24198.51.100.0/24 and needs to provision subnets for departmental networks. Each departmental network must support a minimum of 2525 usable host IP addresses. Using the longest prefix length (smallest subnet size) that satisfies this host requirement, what is the maximum number of usable host IP addresses available on each generated subnet?

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Cevap: 30

Cevap

Each subnet supports a maximum of 30 usable host IP addresses.
To support at least 2525 usable host IP addresses, 55 host bits are required (252=302^5 - 2 = 30). This corresponds to a /27/27 subnet prefix length (325=2732 - 5 = 27). Each /27/27 subnet contains 3232 total IP addresses. Subtracting 22 reserved addresses for the network identifier and broadcast address leaves 3030 usable host IP addresses per subnet.

Adım Adım Çözüm

1
Determine the minimum number of host bits (hh) required to accommodate 2525 usable host IP addresses using the formula 2h2252^h - 2 \ge 25.
h=5h = 5 host bits are needed because 242=142^4 - 2 = 14 (too small) and 252=30252^5 - 2 = 30 \ge 25.
Host bits determine the size of the host portion of the IPv4 address space for the subnet.
2
Calculate total usable host IP addresses per subnet created with 55 host bits (a /27/27 subnet mask, or 255.255.255.224255.255.255.224).
252=302^5 - 2 = 30 usable host IP addresses.
Two IP addresses in every block are reserved for the network ID and the broadcast address, leaving 3030 addresses available for host assignment.

Anahtar Kavram

IPv4 Subnet Mask and Usable Host Capacity Calculation
Tahmini Süre:1m 30s
Soru 532Soru

A network administrator is provisioning a dedicated IPv4 subnet for a store's point-of-sale terminals using the network address block 172.16.100.0/22172.16.100.0/22. Which of the following represents the first usable host IP address within this subnet?

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Cevap: 172.16.100.1172.16.100.1

Cevap

The first usable host IP address in the 172.16.100.0/22172.16.100.0/22 subnet is 172.16.100.1172.16.100.1.
For the network block 172.16.100.0/22172.16.100.0/22, the subnet mask is 255.255.252.0255.255.252.0. The network boundary starts at 172.16.100.0172.16.100.0. Because the network address cannot be assigned to an endpoint, the first usable host IP address is obtained by adding 1 to the network address, yielding 172.16.100.1172.16.100.1.

Adım Adım Çözüm

1
Determine the network address and block size for a /22 prefix.
A /22 mask (255.255.252.0255.255.252.0) has a block size of 256252=4256 - 252 = 4 in the third octet. Since 100100 is a multiple of 44, 172.16.100.0172.16.100.0 is the valid network boundary.
Identifying the network ID establishes the starting boundary of the subnet.
2
Calculate the first usable host IP address by adding 1 to the host portion of the network ID.
Network ID 172.16.100.0172.16.100.0 + 11 = 172.16.100.1172.16.100.1.
The network address itself cannot be assigned to hosts, so the first usable host IP is immediately after the network ID.

Anahtar Kavram

IPv4 Subnet Boundaries and Usable Host Range
Soru 533Soru

A network architect is evaluating dynamic routing protocol behaviors for an enterprise network expansion. Which of the following statements accurately contrast the operational characteristics and algorithms of link-state routing protocols with distance-vector routing protocols? (Select TWO.)

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Cevap: Link-state protocols maintain a complete topology database of the network before calculating paths, whereas distance-vector protocols rely on routing updates received from immediate neighbors.; Link-state protocols calculate optimal paths using Dijkstra's Shortest Path First (SPF) algorithm, whereas distance-vector protocols compute routes using the Bellman-Ford algorithm.

Cevap

Link-state protocols maintain a complete topology database of the network before calculating paths, whereas distance-vector protocols rely on routing updates received from immediate neighbors; and link-state protocols calculate optimal paths using Dijkstra's Shortest Path First (SPF) algorithm, whereas distance-vector protocols compute routes using the Bellman-Ford algorithm.
The correct selections describe fundamental operational differences between dynamic routing protocol classes: (1) Link-state protocols assemble a complete topological map (LSDB) before determining optimal paths, while distance-vector protocols rely on periodic vector updates from adjacent neighbors ('routing by rumor'); and (2) Link-state protocols apply Dijkstra's Shortest Path First (SPF) algorithm to their topology database, while distance-vector protocols use the Bellman-Ford algorithm.

Adım Adım Çözüm

1
Analyze network topology visibility across routing protocol families
Link-state protocols (such as OSPF) build a complete link-state database (LSDB) representing the entire network topology before running path calculation. Distance-vector protocols (such as RIP) only receive destination subnets and distance values from adjacent neighbors.
This core distinction defines how topology information is gathered and maintained.
2
Evaluate path calculation algorithms
Link-state protocols process their LSDB using Dijkstra's Shortest Path First (SPF) algorithm to construct a shortest-path tree. Distance-vector protocols calculate route metric updates using the Bellman-Ford routing algorithm.
Algorithmic foundation differentiates link-state database processing from distance-vector metric accumulation.
3
Verify metric definitions and protocol layering
Link-state protocols evaluate cost based on bandwidth, while standard distance-vector protocols use hop count. Both protocol families serve Layer 3 network routing operations.
Options reversing metrics or categorizing link-state protocols as Layer 2 mechanisms are incorrect.

Anahtar Kavram

Operational Differences Between Link-State and Distance-Vector Routing Protocols
Soru 534Soru

A network operations team is configuring intermediate Access Control Lists (ACLs) to allow perimeter routers to send standardized event logs to a central SIEM server located in the management VLAN. If the infrastructure relies on standard unencrypted log forwarding, which transport protocol and destination port combination must be allowed through the ACLs?

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Cevap: UDP port 514

Cevap

UDP port 514 is the correct transport protocol and destination port for standard unencrypted Syslog forwarding.
Standard unencrypted Syslog log forwarding uses User Datagram Protocol (UDP) on port 514 to send event notifications to a log collector or SIEM server without incurring TCP connection setup overhead.

Adım Adım Çözüm

1
Identify the standard protocol utilized by routers and switches to send system notifications and logs to a central collector.
The network protocol used for system log aggregation is Syslog.
Syslog is the defined RFC standard for transmitting event messages across IP networks.
2
Determine the transport layer protocol and destination port number for traditional unencrypted Syslog.
Unencrypted Syslog operates over User Datagram Protocol (UDP) on destination port 514.
UDP is selected for standard logging to ensure lightweight transmission without requiring connection handshakes or acknowledgement overhead.

Anahtar Kavram

Syslog transport protocol and port assignments
Tahmini Süre:1m 0s
Soru 535Soru

A network administrator is allocated the IPv4 address block 10.75.12.0/2310.75.12.0/23 to provision subnets for remote branch kiosks. Each kiosk requires a subnetwork capable of supporting at least 2828 usable host IP addresses. What is the maximum number of equal-sized subnets meeting this host requirement that can be created from the allocated address block?

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Cevap: 16

Cevap

The maximum number of equal-sized subnets that can be created is 16.
To support at least 2828 usable host addresses, each subnet must have 5 host bits (252=302^5 - 2 = 30 usable addresses). An allocation of 5 host bits yields a /27/27 mask (325=2732 - 5 = 27). Dividing the parent /23/23 block into /27/27 subnets borrows 2723=427 - 23 = 4 subnet bits, yielding 24=162^4 = 16 maximum usable subnets.

Adım Adım Çözüm

1
Calculate the minimum number of host bits required per subnet
5 host bits are needed because 252=302^5 - 2 = 30 usable hosts, which satisfies the requirement of at least 2828 usable host IP addresses (242=142^4 - 2 = 14 is insufficient).
Subnet sizing requires accounting for 2 reserved addresses (network ID and broadcast address).
2
Determine the required CIDR subnet prefix length
The subnet prefix length is /27/27 (325=2732 - 5 = 27).
Subtracting the 5 host bits from the 32-bit IPv4 address space leaves 27 bits for the network identifier.
3
Calculate the total number of /27/27 subnets that fit into the assigned /23/23 address block
16 subnets (22723=24=162^{27 - 23} = 2^4 = 16).
Dividing a /23/23 address block into /27/27 subnets requires borrowing 4 bits from the host portion for subnetting.

Anahtar Kavram

IPv4 Subnet Sizing and Subnet Count Calculation
Soru 536Soru

A network administrator is setting up a network management system (NMS) to poll status and performance metrics from managed routers and switches across an internal firewall. Which port and transport layer protocol combination must be permitted on the firewall to allow the NMS to issue these polling requests to the managed devices?

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Cevap: UDP port 161

Cevap

UDP port 161 must be allowed through the firewall to enable SNMP polling requests from the NMS to managed devices.
Simple Network Management Protocol (SNMP) polling requests initiated by a Network Management System (NMS) target managed agents listening on UDP port 161. Opening UDP port 161 outbound from the NMS to managed devices allows polling traffic to traverse the firewall successfully.

Adım Adım Çözüm

1
Identify the protocol required for network device monitoring and polling.
Simple Network Management Protocol (SNMP) is used by an NMS to poll managed devices for status metrics.
SNMP is the standard protocol for centralized network hardware monitoring and metrics collection.
2
Determine the transport protocol and port number for SNMP polling.
SNMP polling requests are sent to managed devices listening on UDP port 161.
UDP is chosen for lower overhead, and well-known port 161 handles request/response agent communications.
3
Differentiate polling operations from asynchronous event notifications.
UDP port 161 receives polling requests, whereas UDP port 162 receives unsolicited SNMP trap/notification events.
Distinguishing between polling (port 161) and traps (port 162) ensures correct directional firewall rule configuration.

Anahtar Kavram

SNMP Port and Transport Protocol Differentiation
Tahmini Süre:1m 0s
Soru 537Soru

A systems administrator is configuring perimeter firewall access control rules to enable centralized administrative access across enterprise infrastructure. The security baseline requires deploying TACACS+ for AAA management of network switches and Remote Desktop Protocol (RDP) for graphical management of remote Windows servers. Which of the following port and transport layer protocol combinations must be permitted through the firewall to support these services? (Select TWO)

Geçerli olan tümünü seçin

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Cevap: TCP port 49; TCP port 3389

Cevap

The correct port and protocol combinations are TCP port 49 for TACACS+ and TCP port 3389 for RDP.
TACACS+ uses TCP port 49 to provide reliable, connection-oriented transmission for network access authentication, authorization, and accounting. Remote Desktop Protocol (RDP) uses TCP port 3389 to establish graphical administrative sessions on Windows systems.

Adım Adım Çözüm

1
Identify the transport layer protocol and default port for TACACS+.
TACACS+ uses connection-oriented TCP on port 49 to ensure reliable delivery of AAA payloads.
Unlike RADIUS which uses UDP ports 1812/1813, TACACS+ encrypts the entire packet body over TCP port 49.
2
Identify the transport layer protocol and default port for Remote Desktop Protocol (RDP).
RDP uses TCP port 3389 for remote desktop session initiation and control.
Graphical remote desktop traffic requires a reliable connection provided by TCP port 3389.

Anahtar Kavram

Identifying transport layer protocols (TCP/UDP) and default well-known port numbers for administrative remote management services (TACACS+ and RDP).
Soru 538Soru

A network administrator is dividing the IP address block 172.20.0.0/23172.20.0.0/23 into subnets with a prefix length of /26/26 to accommodate multiple department networks. What is the broadcast address of the third subnet in this allocation?

Cevabı ve açıklamayı göster

Cevap: 172.20.0.191172.20.0.191

Cevap

The broadcast address of the third subnet is 172.20.0.191172.20.0.191.
With a /26/26 subnet mask (255.255.255.192255.255.255.192), each subnet contains 6464 IP addresses. The subnets start at 172.20.0.0172.20.0.0 (1st), 172.20.0.64172.20.0.64 (2nd), 172.20.0.128172.20.0.128 (3rd), and 172.20.0.192172.20.0.192 (4th). The broadcast address of the 3rd subnet (172.20.0.128/26172.20.0.128/26) is the highest IP address in its block, which is 172.20.0.191172.20.0.191.

Adım Adım Çözüm

1
Determine the subnet block size for a /26/26 prefix length.
A /26/26 prefix uses a subnet mask of 255.255.255.192255.255.255.192. The block size in the fourth octet is 256192=64256 - 192 = 64 IP addresses per subnet.
Calculating the block size identifies the boundary increment for each subnet.
2
List the subnet network boundaries starting from the base address 172.20.0.0/23172.20.0.0/23.
Subnet 1 starts at 172.20.0.0/26172.20.0.0/26.
Subnet 2 starts at 172.20.0.64/26172.20.0.64/26.
Subnet 3 starts at 172.20.0.128/26172.20.0.128/26.
Subnet 4 starts at 172.20.0.192/26172.20.0.192/26.
Adding the block size of 6464 sequentially locates the network ID of each subnet.
3
Calculate the broadcast address of the third subnet.
The third subnet network ID is 172.20.0.128172.20.0.128. The fourth subnet starts at 172.20.0.192172.20.0.192. Therefore, the broadcast address of the third subnet is one IP address before the fourth subnet's network ID, which is 172.20.0.191172.20.0.191.
The broadcast address is always the last IP address in a subnet range immediately preceding the next subnet's network ID.

Anahtar Kavram

Subnet Masking and Subnet Boundary Calculation
Tahmini Süre:1m 30s
ÖncekiSayfa 27 / 27
Networking Concepts Alıştırma Soruları — CompTIA Network+ — Sayfa 27 | Examkin