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Zorluk: KolayRate, Time, and Distance Problems

A commuter drives from home to work at a constant speed of 4545 miles per hour and arrives 1010 minutes late. On the following day, driving along the exact same route at a constant speed of 6060 miles per hour, the commuter arrives 55 minutes early. What is the distance, in miles, from the commuter's home to work?

Cevap: 45 miles

Cevap

The distance from the commuter's home to work is 45 miles.
Let dd be the distance in miles between home and work. At 4545 miles per hour, the time taken is d45\frac{d}{45} hours. At 6060 miles per hour, the time taken is d60\frac{d}{60} hours. The difference between being 1010 minutes late and 55 minutes early is 1515 minutes, or 1560=14\frac{15}{60} = \frac{1}{4} hour. Setting up the equation d45d60=14\frac{d}{45} - \frac{d}{60} = \frac{1}{4} and finding a common denominator of 180180 gives 4d3d180=14\frac{4d - 3d}{180} = \frac{1}{4}, which simplifies to d180=14\frac{d}{180} = \frac{1}{4}. Multiplying both sides by 180180 yields d=45d = 45 miles.

Adım Adım Çözüm

1
Calculate the difference in travel time between the two trips in hours.
The time difference is 10 minutes late - (-5 minutes early) = 15 minutes = 1/4 hour.
Since speeds are given in miles per hour, time must be expressed in hours.
2
Set up an equation relating the two travel times using the formula time = distance / speed.
d/45 - d/60 = 1/4, where d represents the distance in miles.
The slower speed (45 mph) takes 1/4 hour longer than the faster speed (60 mph).
3
Solve the equation for the distance variable d.
(4d - 3d)/180 = 1/4 => d/180 = 1/4 => d = 45.
Find a common denominator for 45 and 60, which is 180, and solve for d.

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Rate, Time, and Distance Problems
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