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Zorluk: OrtaSequential Processes and State Transitions

An automated smart climate controller regulates room temperature (TT, in C{}^\circ\text{C}) and relative humidity (HH, in %\%) across three sequential hourly cycles (k=1,2,3k = 1, 2, 3). The initial state at cycle k=0k = 0 is T0=24CT_0 = 24^\circ\text{C} and H0=60%H_0 = 60\%.

At the end of each hourly cycle kk, the new state (Tk,Hk)(T_k, H_k) is updated according to the following transition rules:
- Tk=Tk12T_k = T_{k-1} - 2 if Hk150%H_{k-1} \ge 50\%; otherwise, Tk=Tk1+1T_k = T_{k-1} + 1
- Hk=Hk110H_k = H_{k-1} - 10 if Tk1>20T_{k-1} > 20; otherwise, Hk=Hk1+5H_k = H_{k-1} + 5

Which of the following statements regarding the system's state are correct? Select all that apply.

  1. The temperature at the end of cycle 3 is 21C21^\circ\text{C}.Cevap
  2. The relative humidity at the end of cycle 3 is 45%45\%.Cevap
  3. C
    The temperature continuously decreases across all three consecutive cycles.
  4. D
    The relative humidity at the end of cycle 2 is 30%30\%.
  5. E
    The temperature at the end of cycle 2 is 18C18^\circ\text{C}.

Cevap

The temperature at the end of cycle 3 is 21C21^\circ\text{C} and the relative humidity at the end of cycle 3 is 45%45\%.
Evaluating the state transitions step-by-step shows:
- Cycle 1: T1=22C,H1=50%T_1 = 22^\circ\text{C}, H_1 = 50\%
- Cycle 2: T2=20C,H2=40%T_2 = 20^\circ\text{C}, H_2 = 40\%
- Cycle 3: T3=21C,H3=45%T_3 = 21^\circ\text{C}, H_3 = 45\%
Therefore, the statements confirming that the temperature at the end of cycle 3 is 21C21^\circ\text{C} and that the relative humidity at the end of cycle 3 is 45%45\% are both correct.

Adım Adım Çözüm

1
Calculate state at cycle k=1k = 1 from initial state (T0,H0)=(24,60)(T_0, H_0) = (24, 60).
T1=242=22CT_1 = 24 - 2 = 22^\circ\text{C} (since H0=6050H_0 = 60 \ge 50); H1=6010=50%H_1 = 60 - 10 = 50\% (since T0=24>20T_0 = 24 > 20).
Apply transition rules based on conditions satisfied by cycle 0 values.
2
Calculate state at cycle k=2k = 2 from state (T1,H1)=(22,50)(T_1, H_1) = (22, 50).
T2=222=20CT_2 = 22 - 2 = 20^\circ\text{C} (since H1=5050H_1 = 50 \ge 50); H2=5010=40%H_2 = 50 - 10 = 40\% (since T1=22>20T_1 = 22 > 20).
Apply transition rules based on conditions satisfied by cycle 1 values.
3
Calculate state at cycle k=3k = 3 from state (T2,H2)=(20,40)(T_2, H_2) = (20, 40).
T3=20+1=21CT_3 = 20 + 1 = 21^\circ\text{C} (since H2=40<50H_2 = 40 < 50); H3=40+5=45%H_3 = 40 + 5 = 45\% (since T2=20T_2 = 20 is NOT strictly greater than 2020).
Carefully check strict inequalities (T2>20T_2 > 20 is false for T2=20T_2 = 20) and update parameters accordingly.

Anahtar Kavram

Sequential State Transitions with Conditional Updates
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