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Zorluk: KolayMixture and Concentration

A barista has 4040 ounces of a flavored drink mixture that is 30%30\% syrup by volume. How many ounces of pure water must be added to reduce the syrup concentration to 24%24\% by volume?

Cevap: 10 ounces

Cevap

10 ounces of pure water must be added.
Adding 10 ounces of pure water increases the total volume of the mixture from 40 ounces to 50 ounces while keeping the volume of pure syrup constant at 12 ounces. The resulting concentration is 12 / 50 = 0.24, or 24% by volume.

Adım Adım Çözüm

1
Calculate the volume of pure syrup present in the initial mixture
1212 ounces of syrup
The initial 40-ounce mixture contains 30% syrup by volume (40×0.30=1240 \times 0.30 = 12).
2
Set up the concentration equation after adding xx ounces of pure water
1240+x=0.24\frac{12}{40 + x} = 0.24
Adding pure water increases the total volume to 40+x40 + x ounces without changing the amount of pure syrup.
3
Solve the linear equation for xx
x=10x = 10
Multiplying both sides by 40+x40 + x yields 12=9.6+0.24x12 = 9.6 + 0.24x, which simplifies to 2.4=0.24x2.4 = 0.24x, giving x=10x = 10.

Anahtar Kavram

Dilution of a mixture by adding pure solvent
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