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Zorluk: OrtaSimultaneous Equations and Systems

An agricultural research station operates two types of automated irrigation pumps: Type Alpha and Type Beta. Operating 4 Type Alpha pumps and 3 Type Beta pumps simultaneously for 5 hours consumes a total of 215 kilowatt-hours (kWh)215\text{ kilowatt-hours (kWh)} of electricity. Operating 2 Type Alpha pumps and 5 Type Beta pumps simultaneously for 4 hours consumes a total of 156 kWh156\text{ kWh} of electricity. Based on the information provided, match each given pump metric on the left with its correct hourly electricity consumption value on the right.

  • Hourly electricity consumption rate of one Type Alpha pump7 kWh per hour7\text{ kWh per hour}
  • Hourly electricity consumption rate of one Type Beta pump5 kWh per hour5\text{ kWh per hour}
  • Combined hourly electricity consumption rate of one Type Alpha pump and one Type Beta pump12 kWh per hour12\text{ kWh per hour}

Cevap

The hourly consumption rate of one Type Alpha pump is 7 kWh per hour7\text{ kWh per hour}, one Type Beta pump is 5 kWh per hour5\text{ kWh per hour}, and their combined hourly rate is 12 kWh per hour12\text{ kWh per hour}.
Solving the system of simultaneous linear equations 4a+3b=434a + 3b = 43 and 2a+5b=392a + 5b = 39 yields a=7a = 7 for Type Alpha pumps and b=5b = 5 for Type Beta pumps. The sum a+ba + b equals 1212.

Adım Adım Çözüm

1
Set up equations for the total hourly consumption from the given scenario data.
Let aa be the hourly consumption of Type Alpha in kWh and bb be the hourly consumption of Type Beta in kWh. From 5 hours of operation: 5(4a+3b)=215    4a+3b=435(4a + 3b) = 215 \implies 4a + 3b = 43. From 4 hours of operation: 4(2a+5b)=156    2a+5b=394(2a + 5b) = 156 \implies 2a + 5b = 39.
Dividing total energy by total hours converts total consumption into hourly rates for each operating group.
2
Solve the system of simultaneous linear equations for aa and bb.
Multiply 2a+5b=392a + 5b = 39 by 2 to get 4a+10b=784a + 10b = 78. Subtract 4a+3b=434a + 3b = 43 from 4a+10b=784a + 10b = 78: (4a+10b)(4a+3b)=7843    7b=35    b=5(4a + 10b) - (4a + 3b) = 78 - 43 \implies 7b = 35 \implies b = 5.
Eliminating variable aa allows direct solution for variable bb.
3
Substitute b=5b = 5 back into one of the linear equations to find aa.
2a+5(5)=39    2a+25=39    2a=14    a=72a + 5(5) = 39 \implies 2a + 25 = 39 \implies 2a = 14 \implies a = 7.
Determines the single unit rate for Type Alpha pumps.
4
Calculate the combined hourly rate for one Type Alpha and one Type Beta pump.
a+b=7+5=12 kWh per houra + b = 7 + 5 = 12\text{ kWh per hour}.
Calculates the sum of both individual unit rates.

Anahtar Kavram

Formulating and solving a system of two linear equations in two variables from rates and total work/consumption.
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