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Zorluk: ZorWork Rate and Combined Work

A pharmaceutical production facility utilizes three automated synthesis modules—Module A, Module B, and Module C—to produce a specific batch of medication. Working alone at its constant rate, Module A can complete a full batch in 1515 hours. Modules B and C, working together at their respective constant rates, can complete a full batch in 2020 hours. A production run begins with Module A and Module B working together for 44 hours. At that point, Module A is turned off for recalibration, and Module C immediately joins Module B to complete the remaining portion of the batch. If Modules B and C work together for 1212 hours to finish the batch, how many hours would it take Module B to complete a full batch working alone?

  1. A
    2020 hours
  2. B
    2525 hours
  3. 3030 hoursCevap
  4. D
    4040 hours
  5. E
    6060 hours

Cevap

Module B would take 3030 hours to complete a full batch working alone.
The correct answer is 3030 hours. In Stage 2, Modules B and C work together for 1212 hours at their combined rate of 120\frac{1}{20} batch per hour, completing 1220=35\frac{12}{20} = \frac{3}{5} of the entire batch. This leaves 135=251 - \frac{3}{5} = \frac{2}{5} of the batch that was completed during Stage 1 by Modules A and B working together for 44 hours. Setting up the Stage 1 equation: 4(rA+rB)=254(r_A + r_B) = \frac{2}{5}. Substituting Module A's rate rA=115r_A = \frac{1}{15}, we get 4(115+rB)=25    415+4rB=615    4rB=215    rB=1304\left(\frac{1}{15} + r_B\right) = \frac{2}{5} \implies \frac{4}{15} + 4r_B = \frac{6}{15} \implies 4r_B = \frac{2}{15} \implies r_B = \frac{1}{30}. Therefore, Module B takes 3030 hours operating alone.

Adım Adım Çözüm

1
Express the individual and combined rates of the modules
Rate of Module A (rAr_A) = 115\frac{1}{15} batch/hr; Combined rate of Modules B and C (rB+rCr_B + r_C) = 120\frac{1}{20} batch/hr.
Work rate is defined as the fraction of the job completed per unit of time.
2
Calculate the work completed during Stage 2
Work in Stage 2 = 12×(rB+rC)=12×120=3512 \times (r_B + r_C) = 12 \times \frac{1}{20} = \frac{3}{5} of the batch.
Modules B and C worked together for 1212 hours at their known combined rate of 120\frac{1}{20} batch/hr.
3
Calculate the work done in Stage 1 and solve for Module B's rate (rBr_B)
Total Work = Stage 1 Work + Stage 2 Work = 11. Thus, 4(rA+rB)+35=1    4(115+rB)=25    415+4rB=615    4rB=215    rB=1304(r_A + r_B) + \frac{3}{5} = 1 \implies 4\left(\frac{1}{15} + r_B\right) = \frac{2}{5} \implies \frac{4}{15} + 4r_B = \frac{6}{15} \implies 4r_B = \frac{2}{15} \implies r_B = \frac{1}{30} batch/hr.
The sum of the work performed across both stages must equal 11 full batch.
4
Convert Module B's rate into total time required working alone
Time for Module B alone = 1rB=30\frac{1}{r_B} = 30 hours.
Total time working alone is the reciprocal of the individual work rate.

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Work Rate and Combined Work
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