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Zorluk: KolaySequential Processes and State Transitions

A smart battery storage unit operates over three consecutive cycles (k=1,2,3k = 1, 2, 3). At the start of Cycle 1 (k=0k = 0), the stored energy (E0E_0) is 50 kWh50\text{ kWh} and the grid demand factor (D0D_0) is 1010.

For each cycle kk:
- Stored energy updates according to the demand factor of the previous cycle: Ek=Ek1+20E_k = E_{k-1} + 20 if Dk110D_{k-1} \ge 10; otherwise, Ek=Ek110E_k = E_{k-1} - 10.
- Grid demand factor updates according to: Dk=Dk12D_k = D_{k-1} - 2.

Which of the following statements regarding the system states must be true? (Select all that apply.)

  1. At the end of Cycle 1 (k=1k = 1), the stored energy is 70 kWh70\text{ kWh}.Cevap
  2. At the end of Cycle 3 (k=3k = 3), the grid demand factor is 44.Cevap
  3. C
    At the end of Cycle 2 (k=2k = 2), the stored energy is 90 kWh90\text{ kWh}.
  4. D
    At the end of Cycle 3 (k=3k = 3), the stored energy is 70 kWh70\text{ kWh}.
  5. E
    At the end of Cycle 2 (k=2k = 2), the grid demand factor is 88.

Cevap

The statements confirming that the stored energy at the end of Cycle 1 is 70 kWh and that the grid demand factor at the end of Cycle 3 is 4 are both correct.
Evaluating the transition steps sequentially: At Cycle 1 (k=1k=1), D0=1010D_0 = 10 \ge 10, so stored energy becomes 50+20=70 kWh50 + 20 = 70\text{ kWh} and demand factor becomes 102=810 - 2 = 8. This confirms the statement regarding Cycle 1 stored energy. Continuing through Cycle 2 (D1=8<10E2=60,D2=6D_1 = 8 < 10 \Rightarrow E_2 = 60, D_2 = 6) to Cycle 3 (D2=6<10E3=50,D3=4D_2 = 6 < 10 \Rightarrow E_3 = 50, D_3 = 4), the grid demand factor reaches 44, confirming the statement regarding Cycle 3 grid demand.

Adım Adım Çözüm

1
Calculate state values at the end of Cycle 1 (k=1k = 1)
E1=50+20=70 kWhE_1 = 50 + 20 = 70\text{ kWh} because D0=1010D_0 = 10 \ge 10. D1=102=8D_1 = 10 - 2 = 8.
Apply the conditional energy rule and the linear demand decrease rule using initial values.
2
Calculate state values at the end of Cycle 2 (k=2k = 2)
E2=7010=60 kWhE_2 = 70 - 10 = 60\text{ kWh} because D1=8<10D_1 = 8 < 10. D2=82=6D_2 = 8 - 2 = 6.
Since D1<10D_1 < 10, the energy decreases by 10 kWh10\text{ kWh}.
3
Calculate state values at the end of Cycle 3 (k=3k = 3)
E3=6010=50 kWhE_3 = 60 - 10 = 50\text{ kWh} because D2=6<10D_2 = 6 < 10. D3=62=4D_3 = 6 - 2 = 4.
Since D2<10D_2 < 10, the energy decreases by 10 kWh10\text{ kWh} and demand factor decreases by 22.

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Sequential Processes and State Transitions
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