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Zorluk: ZorDivisibility, Factors, and Multiples

A positive integer nn is not divisible by 33. If nn has exactly 1515 positive divisors and 2n2n has exactly 2020 positive divisors, how many positive divisors does 3n3n have?

Cevap: 30

Cevap

30
The number of positive divisors of an integer with prime factorization p1e1p2e2p_1^{e_1} p_2^{e_2} \dots is (e1+1)(e2+1)(e_1 + 1)(e_2 + 1) \dots. Given d(n)=15d(n) = 15, nn can be p14p^{14} or p4q2p^4 q^2. Given d(2n)=20d(2n) = 20, 2 must be a prime factor of nn with exponent 2, making n=22p4n = 2^2 p^4. Since nn is not divisible by 3, p3p \neq 3. Multiplying nn by 3 introduces 313^1 into the prime factorization, giving 3n=2231p43n = 2^2 \cdot 3^1 \cdot p^4. The total number of positive divisors is (2+1)(1+1)(4+1)=30(2+1)(1+1)(4+1) = 30.

Adım Adım Çözüm

1
Analyze the number of positive divisors of nn.
nn is either p14p^{14} or p4q2p^4 q^2 for distinct primes pp and qq.
The number of positive divisors of n=p1e1p2e2n = p_1^{e_1} p_2^{e_2} \dots is given by (e1+1)(e2+1)(e_1 + 1)(e_2 + 1) \dots. Since 15=15×1=5×315 = 15 \times 1 = 5 \times 3, the exponent structure must be 14 or 4 and 2.
2
Analyze the number of positive divisors of 2n2n.
n=22p4n = 2^2 p^4, where pp is a prime other than 2 and 3.
If n=p4q2n = p^4 q^2, multiplying by 2 increases the exponent of 2 by 1. If q=2q = 2, then n=22p4n = 2^2 p^4 and 2n=23p42n = 2^3 p^4, yielding (3+1)(4+1)=20(3 + 1)(4 + 1) = 20 divisors. Any other prime structure yields a different count.
3
Determine the prime factorization of 3n3n and count its positive divisors.
The number of divisors of 3n3n is 30.
Since nn is not divisible by 3, p3p \neq 3. Thus 3n=2231p43n = 2^2 \cdot 3^1 \cdot p^4, which has (2+1)(1+1)(4+1)=30(2 + 1)(1 + 1)(4 + 1) = 30 positive divisors.

Anahtar Kavram

Divisor Count Formula and Prime Factorization
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