Soru

Zorluk: OrtaBasic Single-Event Probability

An integer nn is randomly selected from the set of all integers from 1010 to 5959, inclusive. What is the probability that nn is a prime number whose units digit is 33?

  1. A
    110\frac{1}{10}
  2. B
    449\frac{4}{49}
  3. 225\frac{2}{25}Cevap
  4. D
    223\frac{2}{23}
  5. E
    350\frac{3}{50}

Cevap

The probability that the selected integer is a prime number whose units digit is 33 is 225\frac{2}{25}.
The correct answer identifies that there are 50 total integers in the inclusive range from 10 to 59. Among the numbers ending in 3 (13,23,33,43,5313, 23, 33, 43, 53), exactly four are prime (13,23,43,5313, 23, 43, 53), while 33 is composite. Dividing 4 favorable outcomes by 50 total outcomes yields 450\frac{4}{50}, which simplifies to 225\frac{2}{25}.

Adım Adım Çözüm

1
Determine the total number of outcomes in the set.
The set contains 5910+1=5059 - 10 + 1 = 50 integers.
For an inclusive set of integers from aa to bb, the total number of integers is ba+1b - a + 1.
2
Identify all integers in the set with a units digit of 33.
The candidate integers ending in 3 are 13,23,33,43,5313, 23, 33, 43, 53.
These are all two-digit numbers in the range [10,59][10, 59] ending with 33.
3
Determine which candidate integers are prime numbers.
The prime numbers are 13,23,43,13, 23, 43, and 5353 (a total of 4 favorable outcomes). Note that 33=3×1133 = 3 \times 11, so it is composite.
A prime number is an integer greater than 1 that has no positive divisors other than 1 and itself.
4
Calculate the single-event probability and simplify the fraction.
Probability=450=225\text{Probability} = \frac{4}{50} = \frac{2}{25}.
Probability is defined as the number of favorable outcomes divided by the total number of possible outcomes.

Anahtar Kavram

Basic Single-Event Probability
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