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Zorluk: Çok zorSimultaneous Equations and Systems

A biotechnology laboratory operates two automated synthesis workflows, System X and System Y, to manufacture two compounds, Alpha (AA) and Beta (BB). System X operates for xx hours, producing AA at a rate of 3 mg/hr3\text{ mg/hr} and BB at a rate of 5 mg/hr5\text{ mg/hr}. System Y operates for yy hours, producing AA at a rate of 15 mg/hr15\text{ mg/hr} and BB at a rate of 8 mg/hr8\text{ mg/hr}. The combined mass of compounds AA and BB produced across both workflows is exactly 340 mg340\text{ mg}. Furthermore, the system's operating efficiency requires that the ratio of operating hours xy\frac{x}{y} equals the ratio of total mass produced BA\frac{B}{A}. What is the total operating time, x+yx + y, in hours?

Cevap: 20 hours

Cevap

The total operating time of both workflows is 20 hours.
Representing the total production of compounds A and B as functions of hours x and y yields the linear total mass equation 8x + 23y = 340 and the ratio relation x/y = B/A, which simplifies to the homogeneous quadratic 3x^2 + 10xy - 8y^2 = 0. Factoring gives (3x - 2y)(x + 4y) = 0. Since operating hours are strictly positive, x = (2/3)y. Substituting this into the linear equation yields (85/3)y = 340, giving y = 12 hours and x = 8 hours. The total operating time is 8 + 12 = 20 hours.

Adım Adım Çözüm

1
Set up algebraic expressions for total mass of each compound produced.
Compound A mass = 3x+15y3x + 15y mg; Compound B mass = 5x+8y5x + 8y mg.
Mass equals production rate multiplied by total operating hours.
2
Formulate the total combined production equation.
8x+23y=3408x + 23y = 340.
The sum of all Compound A and Compound B produced across both systems is given as 340 mg.
3
Set up and simplify the ratio equality xy=BA\frac{x}{y} = \frac{B}{A}.
3x2+10xy8y2=03x^2 + 10xy - 8y^2 = 0.
Cross-multiplying xy=5x+8y3x+15y\frac{x}{y} = \frac{5x + 8y}{3x + 15y} gives x(3x+15y)=y(5x+8y)x(3x + 15y) = y(5x + 8y).
4
Factor the homogeneous quadratic equation.
(3x2y)(x+4y)=0    x=23y(3x - 2y)(x + 4y) = 0 \implies x = \frac{2}{3}y.
Because operating hours xx and yy must be positive, x+4y>0x + 4y > 0, forcing 3x2y=03x - 2y = 0.
5
Substitute x=23yx = \frac{2}{3}y into 8x+23y=3408x + 23y = 340.
y=12y = 12 hours and x=8x = 8 hours.
Solving 853y=340\frac{85}{3}y = 340 gives y=12y = 12, and substituting back into x=23yx = \frac{2}{3}y gives x=8x = 8.
6
Compute total operating time x+yx + y.
8+12=208 + 12 = 20 hours.
The question asks for the combined total operating time of both systems.

Anahtar Kavram

Solving non-linear systems of simultaneous equations involving ratio constraints and quadratic factorization
Tahmini Süre:2m 30s
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