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Zorluk: OrtaOverlapping Sets, Statistics, and Data Distributions

In a laboratory, 8080 experimental trials were conducted. Each trial was monitored by Sensor P, Sensor Q, or both. The average (arithmetic mean) duration of the trials monitored by Sensor P only was 4545 minutes, and the average duration of the trials monitored by Sensor Q only was 6060 minutes. What was the average duration of all 8080 trials?

(1) Exactly 2020 trials were monitored by Sensor P only, and 3030 trials were monitored by Sensor Q only.
(2) The average duration of all trials monitored by Sensor Q was 5555 minutes, and the average duration of the trials monitored by both sensors was 5050 minutes.

  1. A
    Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
  2. B
    Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.Cevap
  4. D
    EACH statement ALONE is sufficient.
  5. E
    Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

Both statements together are sufficient to answer the question, but neither statement alone is sufficient.
Evaluating Statement (1) gives the counts for all three disjoint regions (2020 P-only, 3030 Q-only, and 3030 Both), but does not provide the mean duration of the 3030 trials in the 'Both' category. Evaluating Statement (2) gives the mean duration of the 'Both' category (5050 minutes) and establishes that nB=nQn_{B} = n_{Q}, but does not give absolute counts. Combining both statements provides all subgroup sizes and their respective means, allowing us to calculate the exact weighted average of 52.552.5 minutes.

Adım Adım Çözüm

1
Formulate the algebraic expressions for total trials and total duration.
Let nPn_{P}, nQn_{Q}, and nBn_{B} be the counts for Sensor P only, Sensor Q only, and Both sensors respectively. nP+nQ+nB=80n_{P} + n_{Q} + n_{B} = 80. The total duration is 45nP+60nQ+MBnB45 n_{P} + 60 n_{Q} + M_{B} n_{B}, where MBM_{B} is the mean duration of the trials monitored by both sensors.
Deconstruct the overlapping sets into three mutually exclusive subgroups: P only, Q only, and Both.
2
Evaluate Statement (1) alone.
nP=20n_{P} = 20 and nQ=30    nB=802030=30n_{Q} = 30 \implies n_{B} = 80 - 20 - 30 = 30. Total duration =45(20)+60(30)+MB(30)=2700+30MB= 45(20) + 60(30) + M_{B}(30) = 2700 + 30 M_{B}.
Since the mean duration MBM_{B} for trials monitored by both sensors is unknown, Statement (1) is insufficient.
3
Evaluate Statement (2) alone.
The total group Q consists of Q only (nQn_{Q}, mean 6060) and Both (nBn_{B}, mean 5050). Average for Q is 55    60nQ+50nBnQ+nB=55    5nB=5nQ    nB=nQ55 \implies \frac{60 n_{Q} + 50 n_{B}}{n_{Q} + n_{B}} = 55 \implies 5 n_{B} = 5 n_{Q} \implies n_{B} = n_{Q}.
Statement (2) proves nB=nQn_{B} = n_{Q}, which gives nP+2nQ=80n_{P} + 2 n_{Q} = 80, but without specific numbers for nQn_{Q} or nPn_{P}, the overall average cannot be uniquely determined. Thus Statement (2) is insufficient.
4
Evaluate Statements (1) and (2) together.
From (1), nP=20n_{P} = 20 and nQ=30n_{Q} = 30, so nB=30n_{B} = 30. From (2), MB=50M_{B} = 50. Total duration =45(20)+60(30)+50(30)=900+1800+1500=4200= 45(20) + 60(30) + 50(30) = 900 + 1800 + 1500 = 4200. Overall average =420080=52.5= \frac{4200}{80} = 52.5 minutes.
Combining both statements yields a unique numeric value for the overall average duration.

Anahtar Kavram

Weighted Averages and Overlapping Sets Partitioning
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