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Zorluk: KolayConsecutive Integers and Number Sets

If the sum of three consecutive even integers is 4242, what is the smallest of these integers?

  1. A
    1010
  2. 1212Cevap
  3. C
    1313
  4. D
    1414
  5. E
    1616

Cevap

1212
The arithmetic mean (average) of three consecutive even integers is equal to the middle integer. Dividing the total sum 4242 by 33 yields 1414, which is the middle integer. Subtracting 22 gives the smallest integer, 1212.

Adım Adım Çözüm

1
Define the three consecutive even integers algebraically
Let the three consecutive even integers be nn, n+2n + 2, and n+4n + 4, where nn represents the smallest integer.
Consecutive even integers differ by 22.
2
Set up the equation for their sum
n+(n+2)+(n+4)=42    3n+6=42n + (n + 2) + (n + 4) = 42 \implies 3n + 6 = 42
The problem states that the sum of the three integers equals 4242.
3
Solve for nn
3n=36    n=123n = 36 \implies n = 12
Subtract 66 from both sides and divide by 33 to find the smallest integer.

Anahtar Kavram

Properties and Sums of Consecutive Even Integers
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