Soru

Zorluk: ZorExponents, Roots, and Powers of Integers

Which of the following is equivalent to 810+41584+46\sqrt{\frac{8^{10} + 4^{15}}{8^4 + 4^6}}?

  1. A
    282^8
  2. 292^9Cevap
  3. C
    2102^{10}
  4. D
    2122^{12}
  5. E
    2182^{18}

Cevap

The expression is equivalent to 292^9.
By converting all terms to base 2, 810+415=(23)10+(22)15=230+230=2318^{10} + 4^{15} = (2^3)^{10} + (2^2)^{15} = 2^{30} + 2^{30} = 2^{31} in the numerator, and 84+46=(23)4+(22)6=212+212=2138^4 + 4^6 = (2^3)^4 + (2^2)^6 = 2^{12} + 2^{12} = 2^{13} in the denominator. The expression simplifies to 231213=218=29\sqrt{\frac{2^{31}}{2^{13}}} = \sqrt{2^{18}} = 2^9.

Adım Adım Çözüm

1
Convert all terms in the numerator and denominator to a common base of 2.
Numerator: 810+415=(23)10+(22)15=230+2308^{10} + 4^{15} = (2^3)^{10} + (2^2)^{15} = 2^{30} + 2^{30}. Denominator: 84+46=(23)4+(22)6=212+2128^4 + 4^6 = (2^3)^4 + (2^2)^6 = 2^{12} + 2^{12}.
Expressing terms with prime bases enables simplification using exponent rules.
2
Factor out common terms to simplify addition in numerator and denominator.
Numerator: 230+230=2230=2312^{30} + 2^{30} = 2 \cdot 2^{30} = 2^{31}. Denominator: 212+212=2212=2132^{12} + 2^{12} = 2 \cdot 2^{12} = 2^{13}.
Adding two equal quantities x+xx + x equals 2x2x, increasing the power of 2 by 1.
3
Simplify the fraction inside the square root.
\frac{2^{31}}{2^{13}} = 2^{31 - 13} = 2^{18}.
Apply the quotient rule of exponents: aman=amn\frac{a^m}{a^n} = a^{m-n}.
4
Evaluate the radical expression.
\sqrt{2^{18}} = (2^{18})^{1/2} = 2^{18/2} = 2^9.
Taking the square root of a power halves its exponent.

Anahtar Kavram

Exponents, Roots, and Powers of Integers
Tahmini Süre:2m 0s
Bu soruyu puanla