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Zorluk: OrtaExponents, Radicals, and Algebraic Expressions

If 2a+b=122^{a+b} = 12 and 2ab=32^{a-b} = 3, what is the value of 22a22b2^{2a} - 2^{2b}?

Cevap: 32

Cevap

32
Multiplying the equations gives (2a+b)(2ab)=22a=12×3=36(2^{a+b})(2^{a-b}) = 2^{2a} = 12 \times 3 = 36. Dividing the first equation by the second gives 2a+b2ab=22b=123=4\frac{2^{a+b}}{2^{a-b}} = 2^{2b} = \frac{12}{3} = 4. Subtracting the two values gives 22a22b=364=322^{2a} - 2^{2b} = 36 - 4 = 32.

Adım Adım Çözüm

1
Multiply the given exponent expressions to evaluate 22a2^{2a}.
22a=(2a+b)(2ab)=12×3=362^{2a} = (2^{a+b})(2^{a-b}) = 12 \times 3 = 36.
According to the product rule of exponents, 2x2y=2x+y2^{x} \cdot 2^{y} = 2^{x+y}. Adding (a+b)+(ab)(a+b) + (a-b) yields 2a2a.
2
Divide the first exponent expression by the second to evaluate 22b2^{2b}.
22b=2a+b2ab=123=42^{2b} = \frac{2^{a+b}}{2^{a-b}} = \frac{12}{3} = 4.
According to the quotient rule of exponents, 2x2y=2xy\frac{2^{x}}{2^{y}} = 2^{x-y}. Subtracting (a+b)(ab)(a+b) - (a-b) yields 2b2b.
3
Calculate the value of 22a22b2^{2a} - 2^{2b}.
364=3236 - 4 = 32.
Substitute the evaluated components 22a=362^{2a} = 36 and 22b=42^{2b} = 4 into the expression.

Anahtar Kavram

Exponent Operations (Product and Quotient Rules)
Tahmini Süre:1m 30s
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