Soru

Zorluk: ZorMean, Median, and Mode

A data set consists of 88 positive integers with an arithmetic mean of 1515 and a unique mode of 1212. What is the maximum possible value of an integer in this data set?

Cevap: 81

Cevap

81
The total sum of the 88 integers is 8×15=1208 \times 15 = 120. To maximize the single largest integer, the sum of the remaining 77 integers must be minimized. Since 1212 is the unique mode, 1212 must appear at least twice, and no other value can appear more than once. The smallest positive integers that can occupy the first 55 positions without creating another mode are 1,2,3,4,1, 2, 3, 4, and 55. Placing 1212 in the 6th6\text{th} and 7th7\text{th} positions minimizes the sum of the first 77 elements to 1+2+3+4+5+12+12=391 + 2 + 3 + 4 + 5 + 12 + 12 = 39. Thus, the maximum possible value for the largest integer is 12039=81120 - 39 = 81.

Adım Adım Çözüm

1
Calculate the total sum of the 8 positive integers.
Total Sum = 8×15=1208 \times 15 = 120.
The sum of a set of numbers equals the arithmetic mean multiplied by the number of elements.
2
Minimize the sum of the first 7 integers to maximize the 8th integer.
Minimum sum of the first 7 integers = 1+2+3+4+5+12+12=391 + 2 + 3 + 4 + 5 + 12 + 12 = 39.
To maximize the largest integer, the remaining 7 integers must be as small as possible. Since 12 is the unique mode, 12 must appear at least twice, and no other integer can appear more than once. Placing two 12s at the highest available positions among the 7 terms (a6=12a_6 = 12 and a7=12a_7 = 12) and selecting the smallest distinct positive integers (1,2,3,4,51, 2, 3, 4, 5) for the first 5 terms minimizes their total sum.
3
Subtract the minimum sum of the 7 smallest terms from the total sum.
Maximum integer = 12039=81120 - 39 = 81.
Subtracting the smallest possible sum of 7 terms from the fixed sum of 120 yields the maximum possible value for the 8th term.

Anahtar Kavram

Maximizing an element in a data set under mean and mode constraints
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