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Zorluk: OrtaPrime Numbers and Prime Factorization

What is the smallest positive integer nn such that 180×n180 \times n is a perfect square and 450×n450 \times n is a perfect cube?

Cevap: 1620

Cevap

The smallest positive integer nn is 1620.
By writing 180 as 22×32×512^2 \times 3^2 \times 5^1 and 450 as 21×32×522^1 \times 3^2 \times 5^2, we can analyze the exponents needed for n=2a×3b×5cn = 2^a \times 3^b \times 5^c. To make 180n180n a perfect square, aa and bb must be even and cc must be odd. To make 450n450n a perfect cube, 1+a1+a, 2+b2+b, and 2+c2+c must be multiples of 3. Finding the minimal non-negative integers that satisfy both conditions yields a=2a = 2, b=4b = 4, and c=1c = 1. Thus, n=22×34×51=1620n = 2^2 \times 3^4 \times 5^1 = 1620.

Adım Adım Çözüm

1
Express 180 and 450 in terms of their prime factorizations.
180=22×32×51180 = 2^2 \times 3^2 \times 5^1 and 450=21×32×52450 = 2^1 \times 3^2 \times 5^2
Prime factorization exposes the exponent requirements for perfect powers.
2
Determine the constraints on exponents of n=2a×3b×5cn = 2^a \times 3^b \times 5^c.
For 180n180n to be a square, aa must be even, bb must be even, and cc must be odd. For 450n450n to be a cube, 1+a1+a, 2+b2+b, and 2+c2+c must be multiples of 3.
A number is a perfect square if all prime exponents are even, and a perfect cube if all prime exponents are multiples of 3.
3
Find the minimal values for a,b,ca, b, c.
a=2,b=4,c=1a = 2, b = 4, c = 1
a=2a=2 is even and makes 1+2=31+2=3; b=4b=4 is even and makes 2+4=62+4=6; c=1c=1 is odd and makes 2+1=32+1=3.
4
Compute nn.
n=22×34×51=1620n = 2^2 \times 3^4 \times 5^1 = 1620
Multiplying the prime powers together yields the smallest integer nn.

Anahtar Kavram

Prime Factorization and Exponent Rules for Perfect Powers
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