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Zorluk: ZorMean, Median, and Mode
A software quality team tracked the number of bug tickets resolved daily over a period of 1515 consecutive workdays. The recorded number of resolved tickets for the first 1414 days, listed in ascending order, were: 2,3,3,4,5,5,6,7,8,9,9,10,11,122, 3, 3, 4, 5, 5, 6, 7, 8, 9, 9, 10, 11, 12 If the number of tickets resolved on the 15th15\text{th} day was xx, and the arithmetic mean of the complete 1515-day data set is equal to its median, what is the value of xx?
  1. A
    77
  2. B
    88
  3. 1111Cevap
  4. D
    1313
  5. E
    1515

Cevap

The value of xx is 1111.
Summing the initial 14 numbers yields 94. In a set of 15 numbers, the median is the 8th term when ordered. Because there are exactly 7 terms smaller than 7 in the initial list, any value of x7x \ge 7 keeps 7 at the 8th position, making the median 7. Setting the mean 94+x15\frac{94+x}{15} equal to 7 gives 94+x=10594 + x = 105, which leads to x=11x = 11.

Adım Adım Çözüm

1
Calculate the sum of the known 14 values.
Sum14=2+3+3+4+5+5+6+7+8+9+9+10+11+12=94\text{Sum}_{14} = 2 + 3 + 3 + 4 + 5 + 5 + 6 + 7 + 8 + 9 + 9 + 10 + 11 + 12 = 94.
The sum of all 15 terms will be 94+x94 + x, making the arithmetic mean 94+x15\frac{94 + x}{15}.
2
Determine the position of the median in a 15-element set.
The median of an odd-numbered set with N=15N = 15 is the 15+12=8th\frac{15+1}{2} = 8\text{th} term when arranged in ascending order.
To set the mean equal to the median, we must determine how xx affects the 8th term.
3
Analyze the position of the 8th term based on potential values of xx.
The first 14 numbers contain 7 values less than 7 (2,3,3,4,5,5,62, 3, 3, 4, 5, 5, 6) and 7 values greater than or equal to 7 (7,8,9,9,10,11,127, 8, 9, 9, 10, 11, 12). Therefore, for any x7x \ge 7, the 8th term in the sorted set of 15 numbers is fixed at 77.
Since 7 values are strictly less than 7, placing x7x \ge 7 ensures that 7 is the 8th smallest value.
4
Set the arithmetic mean equal to the median (77) and solve for xx.
\frac{94 + x}{15} = 7 \implies 94 + x = 105 \implies x = 11.
Since x=117x = 11 \ge 7, the condition holds and the median remains 7.

Anahtar Kavram

Properties of Mean and Median in a Data Set
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