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Zorluk: Çok zorMean, Median, and Mode

A data set SS consists of 1111 positive integers. The set has an arithmetic mean of 1515, a median of 1414, and a unique mode of 1818. If MM is the maximum possible value of an element in SS and mm is the minimum possible value of an element in SS, what is the maximum possible value of the range MmM - m?

  1. A
    6868
  2. B
    7171
  3. C
    7272
  4. 7373Cevap
  5. E
    7474

Cevap

The maximum possible value of the range MmM - m is 7373.
To maximize the range Mm=x11x1M - m = x_{11} - x_1, we minimize x1x_1 and maximize x11x_{11}. Since elements are positive integers, m=x1=1m = x_1 = 1. The sum of all 1111 elements is 11×15=16511 \times 15 = 165. With median x6=14x_6 = 14, the unique mode 1818 must lie above the median. Setting the frequency of 1818 to 33 allows other numbers to appear up to 22 times. Minimizing x1x5x_1 \dots x_5 gives 1,1,2,2,31, 1, 2, 2, 3 (sum 99). Minimizing x7x10x_7 \dots x_{10} by setting x7=14x_7 = 14 and x8=x9=x10=18x_8 = x_9 = x_{10} = 18 gives sum 6868. The sum of the first 1010 terms is 9+14+68=919 + 14 + 68 = 91, leaving M=x11=16591=74M = x_{11} = 165 - 91 = 74. Thus, the maximum range is 741=7374 - 1 = 73.

Adım Adım Çözüm

1
Calculate the sum of all elements in the set.
Sum =11×15=165= 11 \times 15 = 165.
The arithmetic mean of 1111 elements is 1515.
2
Identify the position of the median and order the elements.
Let elements be x1x2x6x11x_1 \le x_2 \le \dots \le x_6 \le \dots \le x_{11}, where x6=14x_6 = 14.
For an odd number of elements (1111), the median is the 6th element.
3
Determine the mode frequency constraint to maximize x11x1x_{11} - x_1.
The unique mode is 1818. If 1818 appears 33 times, the maximum frequency of any other value is 22.
To maximize x11x_{11}, we minimize x1x10x_1 \dots x_{10}. Allowing the mode to appear 33 times permits other elements to appear up to 22 times.
4
Minimize the sum of the lower five elements x1,x2,x3,x4,x5x_1, x_2, x_3, x_4, x_5.
x1=1,x2=1,x3=2,x4=2,x5=3x_1 = 1, x_2 = 1, x_3 = 2, x_4 = 2, x_5 = 3, giving sum =1+1+2+2+3=9= 1 + 1 + 2 + 2 + 3 = 9.
The smallest positive integers with maximum frequency 22 are 1,1,2,2,31, 1, 2, 2, 3.
5
Minimize elements x7,x8,x9,x10x_7, x_8, x_9, x_{10}.
x7=14x_7 = 14 (frequency 22 for 1414), and x8=18,x9=18,x10=18x_8 = 18, x_9 = 18, x_{10} = 18. Sum =14+18+18+18=68= 14 + 18 + 18 + 18 = 68.
Since x6=14x_6 = 14, setting x7=14x_7 = 14 minimizes x7x_7 while keeping the frequency of 1414 at 22, which is less than the mode frequency of 33.
6
Calculate the maximum value M=x11M = x_{11} and the range MmM - m.
Sum of first 10 elements =9+14+68=91= 9 + 14 + 68 = 91. Thus x11=16591=74x_{11} = 165 - 91 = 74. Range =741=73= 74 - 1 = 73.
Subtracting the sum of the first 10 elements from the total sum gives MM, and subtracting m=1m = 1 yields the range.

Anahtar Kavram

Range, Mean, Median, and Mode Constraints in Data Sets
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