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Zorluk: KolayInequalities and Absolute Value Equations

If 32x=7|3 - 2x| = 7, what is the product of all possible real values of xx?

  1. 10-10Cevap
  2. B
    3-3
  3. C
    33
  4. D
    55
  5. E
    1010

Cevap

The product of all possible real values of xx is 10-10.
Solving 32x=7|3 - 2x| = 7 yields two equations: 32x=73 - 2x = 7, which gives x=2x = -2, and 32x=73 - 2x = -7, which gives x=5x = 5. Multiplying these two values together gives (2)×5=10(-2) \times 5 = -10.

Adım Adım Çözüm

1
Set up two linear equations corresponding to the positive and negative cases of the absolute value expression.
32x=73 - 2x = 7 or 32x=73 - 2x = -7
By definition, a=b|a| = b (where b0b \ge 0) implies a=ba = b or a=ba = -b.
2
Solve the first linear equation for xx.
2x=4    x=2-2x = 4 \implies x = -2
Subtract 3 from both sides and divide by 2-2.
3
Solve the second linear equation for xx.
2x=10    x=5-2x = -10 \implies x = 5
Subtract 3 from both sides and divide by 2-2.
4
Calculate the product of the two solutions.
(2)×5=10(-2) \times 5 = -10
The question asks for the product of all possible real values of xx.

Anahtar Kavram

Absolute Value Equations
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