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Zorluk: OrtaAlgebraic Word Problems and Equation Modeling

An event catering service charges a fixed setup fee plus a constant hourly rate for event staff. For a 4-hour event, the total charge is 680.Fora7houreventwiththesamestaffrequirements,thetotalchargeis680. For a 7-hour event with the same staff requirements, the total charge is 1,070. What is the fixed setup fee, in dollars, charged by the catering service?

Cevap: 160 dollars

Cevap

The fixed setup fee charged by the catering service is 160 dollars.
Modeling the total cost as C=S+rtC = S + rt, where SS is the fixed setup fee and rr is the hourly rate, yields the system of equations S+4r=680S + 4r = 680 and S+7r=1070S + 7r = 1070. Subtracting the first equation from the second yields 3r=3903r = 390, so r=130r = 130. Substituting r=130r = 130 back into the first equation yields S+520=680S + 520 = 680, which gives S=160S = 160.

Adım Adım Çözüm

1
Define the algebraic model for total cost.
Let SS be the fixed setup fee in dollars and rr be the hourly rate in dollars per hour. The total cost CC for tt hours is modeled by C=S+rtC = S + rt.
The problem presents a linear relationship between time and total cost, consisting of a fixed component and a variable component.
2
Construct a system of linear equations.
S+4r=680S + 4r = 680 and S+7r=1070S + 7r = 1070.
Substitute the two given combinations of time (t=4t = 4 and t=7t = 7) and total cost (C=680C = 680 and C=1070C = 1070) into the algebraic model.
3
Solve for the variable hourly rate rr.
(S+7r)(S+4r)=1070680    3r=390    r=130(S + 7r) - (S + 4r) = 1070 - 680 \implies 3r = 390 \implies r = 130.
Subtracting the first equation from the second eliminates the fixed setup fee variable SS.
4
Calculate the fixed setup fee SS.
S+4(130)=680    S+520=680    S=160S + 4(130) = 680 \implies S + 520 = 680 \implies S = 160.
Substitute r=130r = 130 back into the first equation to find the value of SS.

Anahtar Kavram

Linear Equation Modeling and Systems of Equations
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