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Zorluk: OrtaExponents, Radicals, and Algebraic Expressions

If 3x+3x+1+3x+2=3513^x + 3^{x+1} + 3^{x+2} = 351, what is the value of (x+1)x(x + 1)^x?

  1. A
    1212
  2. B
    2727
  3. 6464Cevap
  4. D
    8181
  5. E
    243243

Cevap

The value of (x+1)x(x + 1)^x is 6464.
Factoring 3x3^x out of the sum gives 3x(1+3+9)=133x=3513^x(1 + 3 + 9) = 13 \cdot 3^x = 351. Dividing 351351 by 1313 gives 3x=273^x = 27, so x=3x = 3. Substituting x=3x = 3 into (x+1)x(x + 1)^x yields (3+1)3=43=64(3 + 1)^3 = 4^3 = 64.

Adım Adım Çözüm

1
Factor out the common exponential term 3x3^x from the left side of the equation.
3x(1+31+32)=3513^x(1 + 3^1 + 3^2) = 351, which simplifies to 3x(1+3+9)=3513^x(1 + 3 + 9) = 351 or 133x=35113 \cdot 3^x = 351.
When adding terms with identical bases and variable exponents, factor out the term with the smallest exponent.
2
Solve for 3x3^x and determine the value of xx.
3x=35113=273^x = \frac{351}{13} = 27. Since 27=3327 = 3^3, x=3x = 3.
Divide both sides by 1313 and set the powers of equal bases equal to find xx.
3
Substitute x=3x = 3 into the target expression (x+1)x(x + 1)^x.
(3+1)3=43=64(3 + 1)^3 = 4^3 = 64.
Evaluate the expression as requested by the question stem.

Anahtar Kavram

Factoring exponential expressions with common bases and applying exponent rules
Tahmini Süre:1m 30s
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